array undefined offset with php - php

Question

<?php
$ar = Array (
[0] => Array ( [id] => 1 [social_id] => [role_id] => 0 [name] => [first_name] => Jimmy [last_name] => rathore [gender] => male [dob] => 06-02-1992 [language] => english [location] => xyz [address] => xyz [email] => xyz#xyz.com [phone] => 9876543210 )
[1] => Array ( [id] => 3 [social_id] => [role_id] => 0 [name] => [first_name] => Dev [last_name] => Smith [gender] => [dob] => [language] => [location] => xyz [address] => xyz [email] => yyy#sds.com [phone] => 7838344344 )
[2] => Array ( [id] => 4 [social_id] => [role_id] => 0 [name] => [first_name] => Col [last_name] => Manon [gender] => male [dob] => 02-02-2017 [language] => english [location] => London [address] => ABCD [email] => londs#an.com [phone] => 7894561230)
) ;
$array = Array (
[0] => Array ( [id] => 1 [sm_id] => 1 [field_name] => first_name [value] => G2 [created_at] => 2017-02-24 11:05:03 [updated_at] => 2017-02-24 11:05:03 [deleted_at] => )
);
$arr = array();
foreach($row=0; $row<count($ar); $row++){
foreach($col=0; $col<count($array); $col++){
if($ar['0']['id'] == $array['0']['id']){
$arr['first_name'] = $ar['0']['first_name'];
$arr['last_name'] = $ar['0']['last_name'];
$arr['email'] = $ar['0']['email'];
$arr['phone'] = $ar['0']['phone'];
}
}
}
print_r($arr);die;
?>
I want map data from one array to other array based on $ar['0]['id'] with $array['0']['sm_id']
if $ar's id matched with $array's sm_id push to one array with its value how can i achieve the same. please suggest
Expected result
Array( [id] => 1 [first_name] => Jimmy [last_name] => rathore [gender] => male [dob] => 06-02-1992 [language] => english [location] => xyz [address] => xyz [email] => xyz#xyz.com [phone] => 9876543210 );

Answer 1

You could do it like this, given the original array is $ar, and the array with sm_id values $array:
// Create a hash of all sm_id values to be found
$ids = array_flip(array_column($array, "sm_id"));
// filter the original array to get only those with an id value in that hash
$arr = array_filter($ar, function ($row) use ($ids) {
return isset($ids[$row["id"]]);
});
print_r ($arr);