PHP doesn't get results from database [duplicate] - php

Question

This question already has an answer here:
Why does mysqli num_rows always return 0?
(1 answer)
Closed 6 years ago.
I want to make instant search (google like) on key up Jquery ajax must ass value from HTML input field to PHP and PHP must chec in SQL table named "title" for any words which Begin or Contain the written word/letter,if there isn't anything found it must print the results out in a div.
Here is an example:
The picture explains: Up is the input field and down box is the box for results to be printed,as we can see it is working,but PHP don't want to get data from SQL,and only printing the result for 0 value (Nothing Found) on Bulgarian language.
There is my code:
<?php
$hostname = "localhost";
$username = "shreddin";
$password = "!utf55jyst";
$databaseName = "shreddin_nation";
$connect = new mysqli($hostname, $username, $password, $databaseName);
$fsearch = "";
if (!empty($_POST['fsearch'])) {
$fsearch = $_POST['fsearch'];
$req = $connect->prepare("SELECT title FROM food_data_bg WHERE title LIKE ?");
$req->bind_param('s', $fsearch);
$req->execute();
if ($req->num_rows == 0) {
echo 'Не бяха намерени резултати!';
}
else {
while ($row = $req->fetch_array()) {
?>
<div class = "search-result">
<span class = "result-title">
<? php
echo $row['title'];
?>
</span><br>
</div>
<?php
}
}
}
?>
The code is working till else {...} only this part didn't work..;/
I tried to use echo some results after else {...} because i thought it was a problem with my code,but it didn't work either way ...Can somebody explain to me where is my mistake (with simple language please) i am not really good at coding exept with PHP.
I won't put Jquery and HTML here because all working fine there, the post method is all good, the problem is with the php. But of course if you need it to help me I will paste it with no problem.

Answer 1

Edited
$value = '%'.$fsearch.'%;
$req->bind_param('s', $value);
it will work :)

Answer 2

<?php
$hostname = "localhost";
$username = "username";
$password = "pass";
$databaseName = "dbName";
$connect = new mysqli($hostname, $username, $password, $databaseName);
$fsearch="";
if(!empty($_POST['fsearch'])) {
$fsearch = $_POST['fsearch'];
$req = $connect->prepare("SELECT title FROM food_data_bg WHERE title LIKE ?");
$value = '%'.$fsearch.'%';
$req->bind_param("s", $value);
$req->execute();
$req->store_result();
if ($req->num_rows == 0){
echo 'Няма резултати';
}
else{
echo 'ДАА';
}
}
FINALY !!! that is the final result,it is printing ДАА when there is a result found and Няма резултати when there isn't any results fixed it after 1 month of pain lol Thanks to everyone which helped me <3<3 <3 <3 <3