I have canvas generated jpg in base64 string uploaded by ajax to php. I have the following working code to do the data:image/jpeg;base64 to svg conversion.
//Uploaded is a string start from data:image/jpeg;base64,...(not a .jpg)
$b64 = (isset($_POST['img']) ? $_POST['img'] : null);
if($b64){
$b64= str_replace('data:image/jpeg;base64,', '', $b64);
$b64= str_replace(' ', '+', $b64);
$im = new Imagick();
$im->readImageBlob(base64_decode($b64));
$im->trimImage(2000);
$im->setImageFormat( "ppm" );
$im->writeImage( "out.ppm" );
$cmd = exec("potrace out.ppm -s -o out.svg 2>&1", $output, $e);
}
However, I found that writing file is a very slow process and make my file system messy. I want to eliminate the writing process by piping the command so that no writing file is needed, but I am not familiar with command line.
Imagick limits the input string up to 5000 characters, so I cannot do like this as it fails once b64 is too long.
exec("convert inline:".$b64." ppm:- | potrace -s -o out.svg");
So,I tried to do the following to wrap the string to a text file but it fails as the content is different and without the "data:image/jpeg;base64" at the beginning. I don't want to write a text file everytime too.
if(strlen($b64)> 4000){
$arr = str_split($b64, 4000);
foreach ($arr as $key => $a) {
$test = exec("echo ".$a." >> out.b64 2>&1", $output, $e);
}
}
Q1: Any chance I can wrap the b64 string into a temp text file as an input to imagick?
Q2: I want to echo back the svg xml instead of download it as a file. And again, this writes a new file although this is faster. I hope there is a method not outputing as a file but as a variable or object like thing in php.
Any suggestions are welcome. Thank you.
Try this.,
$base64_str = str_replace('data:image/png;base64,', '', $b64);
$base64_str = str_replace(' ', '+', $base64_str);
$decoded = base64_decode($base64_str);
$targetPath ="../your target path/";
$png_url ="../your target path/"."product-".strtotime('now').".png";
$image_name ="product-".strtotime('now').".png";
$result = file_put_contents($png_url, $decoded);
I'm sorry to respond to such an old question, but I'm a little confused, why are you trying to convert a base64 encoded JPG (a raster image format) to SVG (a vector image format)?
That won't work, and best case scenario, the SVG will just contain a reference to the original JPG. Is that what you were looking to do?
I am not sure if you are looking for this:
to get base64_encode of an uploaded image (tmp image):
$filename = $_FILES['image']['tmp_name'];
$handle = fopen($filename, "r");
$data = fread($handle, filesize($filename));
$encoded_img = base64_encode($data);
Related
I had base64 encoded data.
Look my code, please.
First of all, see my code.
$data = "data:image/png;base64,iVBORw0KGgoAAAA..........";
$image_array_1 = explode(";", $data);
$image_array_2 = explode(",", $image_array_1[1]);
$data = base64_decode($image_array_2[1]);
$imageName = uniqid().time().".png";
I want to set an extension .png to complete my file so that I can count this file extension by laravel method $image->getClientOriginalExtension() and others laravel file methods.
sorry for miss spell of language.
Hope I make you understand.
This works, although I cannot say if it's the best way to go about it. It's a full working example with a 1x1 black pixel png image. This assumes you already removed the data:image/png;base64, portion from the image data.
$data = base64_decode('iVBORw0KGgoAAAANSUhEUgAAAAEAAAABCAQAAAC1HAwCAAAAC0lEQVR
42mNk+A8AAQUBAScY42YAAAAASUVORK5CYII=');
// Create a temp file and write the decoded image.
$temp = tmpfile();
fwrite($temp, $data);
// Get the path of the temp file.
$tempPath = stream_get_meta_data($temp)['uri'];
// Initialize the UploadedFile.
$imageName = uniqid().time().".png";
$file = new \Illuminate\Http\UploadedFile($tempPath, $imageName, null, null, true);
// Test if the UploadedFile works normally.
echo $file->getClientOriginalExtension(); // Shows 'png'
$file->storeAs('images', 'test.png'); // Creates image in '\storage\app\images'.
// Delete the temp file.
fclose($temp);
I know there are so many solutions for decode base64 image. But any of them didn't work for me.
I have the Base64 image data and i need to convert it to a png file and save it to the local directory.
I tried the following code which i got from here. But it didnt work for me. Please help me to get this done..
define('UPLOAD_DIR', 'images/');
$base64string = "data:image/png;base64,/9j/4AAQSkZJRgABAQEAYABgAAD/2wBB...";
$img = $base64string;
$img = str_replace('data:image/png;base64,', '', $img);
$img = str_replace(' ', '+', $img);
$data = base64_decode($img);
$file = UPLOAD_DIR . uniqid() . 'txtimg.png';
$success = file_put_contents($file, $data);
print $success ? $file : 'Unable to save the file.';
When i execute the script its getting the error message Unable to save. Then i gave full permission for the users. But still no luck.
I tried to save a simple text file through file_put_contents() ; it worked.
I'm using IIS 8 on Windows Azure Server.
Want to take image from own server rotate certain angle and save the image.
Image file $filename = 'kitten_rotated.jpg'; With echo '<img src='.$filename.'>'; i see the image.
Then
$original = imagecreatefromjpeg($filename);
$angle = 90.0;
$rotated = imagerotate($original, $angle, 0);
Based on this https://stackoverflow.com/a/3693075/2118559 answer trying create image file
$output = 'google.com.jpg';
If i save the same image with new file name, all works
file_put_contents( $output, file_get_contents($filename) );
But if i try to save rotated image, then file_put_contents(): supplied resource is not a valid stream resource.
file_put_contents( $output, $rotated );
Here https://stackoverflow.com/a/12185462/2118559 read $export is going to be a GD image handle. It is NOT something you can simply dump out to a file and expect to get a JPG or PNG image.. but can not understand how to use the code in that answer.
How to create image file from $rotated?
Tried to experiment, based on this http://php.net/manual/en/function.imagecreatefromstring.php
$fh = fopen( 'some_name.png' , 'w') or die("can't open file");
fwrite($fh, $data );
fclose($fh);
Does it means that need something like
$data = base64_encode($rotated);
And then write in new file?
I have not tested this, but I think you need to encode the image as base 64 first.
If you check the string from any Image URL, you'd see data:image/png;base64, preceding the hash. Prepending this to your image string and saving.
Here is a function that may help, based on what you already have:
// Function settings:
// 1) Original file
// 2) Angle to rotate
// 3) Output destination (false will output to browser)
function RotateJpg($filename = '',$angle = 0,$savename = false)
{
// Your original file
$original = imagecreatefromjpeg($filename);
// Rotate
$rotated = imagerotate($original, $angle, 0);
// If you have no destination, save to browser
if($savename == false) {
header('Content-Type: image/jpeg');
imagejpeg($rotated);
}
else
// Save to a directory with a new filename
imagejpeg($rotated,$savename);
// Standard destroy command
imagedestroy($rotated);
}
// Base image
$filename = 'http://upload.wikimedia.org/wikipedia/commons/b/b4/JPEG_example_JPG_RIP_100.jpg';
// Destination, including document root (you may have a defined root to use)
$saveto = $_SERVER['DOCUMENT_ROOT']."/images/test.jpg";
// Apply function
RotateJpg($filename,90,$saveto);
If you want to save image just use one of GD library functions: imagepng() or imagepng().
imagerotate() returns image resource so this is not something like string.
In your case just save rotate image:
imagejpg($rotated, $output);
And now You can use $output variable as your new filename to include in view like before:
echo '<img src='.$output.'>';
Don't forget to include appropriate permissions in directory where You're saveing image.
Can I safely assume that the size (in bytes) of a PNG image file created with the following PHP code:
$f = fopen("newImageFile.png", 'w');
$content = base64_decode(substr($dataURL, strpos($dataURL, ',') + 1));
fwrite($f, $content);
where $dataURL is posted from HTML's canves.toDataURL(), exactly equals strlen($content)?
You could use getimagesizefromstring() If you have a newer php version.
But since you are decoding you could use this as well.
$uri = 'data://application/octet-stream;base64,' . base64_encode($data);
getimagesize($uri);
Is there any way to remove the EXIF data from a JPG using PHP? I have heard of PEL, but I'm hoping there's a simpler way. I am uploading images that will be displayed online and would like the EXIF data removed.
Thanks!
EDIT: I don't/can't install ImageMagick.
Use gd to recreate the graphical part of the image in a new one, that you save with another name.
See PHP gd
edit 2017
Use the new Imagick feature.
Open Image:
<?php
$incoming_file = '/Users/John/Desktop/file_loco.jpg';
$img = new Imagick(realpath($incoming_file));
Be sure to keep any ICC profile in the image
$profiles = $img->getImageProfiles("icc", true);
then strip image, and put the profile back if any
$img->stripImage();
if(!empty($profiles)) {
$img->profileImage("icc", $profiles['icc']);
}
Comes from this PHP page, see comment from Max Eremin down the page.
A fast way to do it in PHP using ImageMagick (Assuming you have it installed and enabled).
<?php
$images = glob('*.jpg');
foreach($images as $image)
{
try
{
$img = new Imagick($image);
$img->stripImage();
$img->writeImage($image);
$img->clear();
$img->destroy();
echo "Removed EXIF data from $image. \n";
} catch(Exception $e) {
echo 'Exception caught: ', $e->getMessage(), "\n";
}
}
?>
I was looking for a solution to this as well. In the end I used PHP to rewrite the JPEG with ALL Exif data removed. I didn't need any of it for my purposes.
This option has several advantages...
The file is smaller because the EXIF data is gone.
There is no loss of image quality (because the image data is unchanged).
Also a note on using imagecreatefromjpeg: I tried this and my files got bigger. If you set quality to 100, your file will be LARGER, because the image has been resampled, and then stored in a lossless way. And if you don't use quality 100, you lose image quality. The ONLY way to avoid resampling is to not use imagecreatefromjpeg.
Here is my function...
/**
* Remove EXIF from a JPEG file.
* #param string $old Path to original jpeg file (input).
* #param string $new Path to new jpeg file (output).
*/
function removeExif($old, $new)
{
// Open the input file for binary reading
$f1 = fopen($old, 'rb');
// Open the output file for binary writing
$f2 = fopen($new, 'wb');
// Find EXIF marker
while (($s = fread($f1, 2))) {
$word = unpack('ni', $s)['i'];
if ($word == 0xFFE1) {
// Read length (includes the word used for the length)
$s = fread($f1, 2);
$len = unpack('ni', $s)['i'];
// Skip the EXIF info
fread($f1, $len - 2);
break;
} else {
fwrite($f2, $s, 2);
}
}
// Write the rest of the file
while (($s = fread($f1, 4096))) {
fwrite($f2, $s, strlen($s));
}
fclose($f1);
fclose($f2);
}
The code is pretty simple. It opens the input file for reading and the output file for writing, and then starts reading the input file. It data from one to the other. Once it reaches the EXIF marker, it reads the length of the EXIF record and skips over that number of bytes. It then continues by reading and writing the remaining data.
The following will remove all EXIF data of a jpeg file. This will make a copy of original file without EXIF and remove the old file. Use 100 quality not to loose any quality details of picture.
$path = "/image.jpg";
$img = imagecreatefromjpeg ($path);
imagejpeg ($img, $path, 100);
imagedestroy ($img);
(simple approximation to the graph can be found here)
function remove_exif($in, $out)
{
$buffer_len = 4096;
$fd_in = fopen($in, 'rb');
$fd_out = fopen($out, 'wb');
while (($buffer = fread($fd_in, $buffer_len)))
{
// \xFF\xE1\xHH\xLLExif\x00\x00 - Exif
// \xFF\xE1\xHH\xLLhttp:// - XMP
// \xFF\xE2\xHH\xLLICC_PROFILE - ICC
// \xFF\xED\xHH\xLLPhotoshop - PH
while (preg_match('/\xFF[\xE1\xE2\xED\xEE](.)(.)(exif|photoshop|http:|icc_profile|adobe)/si', $buffer, $match, PREG_OFFSET_CAPTURE))
{
echo "found: '{$match[3][0]}' marker\n";
$len = ord($match[1][0]) * 256 + ord($match[2][0]);
echo "length: {$len} bytes\n";
echo "write: {$match[0][1]} bytes to output file\n";
fwrite($fd_out, substr($buffer, 0, $match[0][1]));
$filepos = $match[0][1] + 2 + $len - strlen($buffer);
fseek($fd_in, $filepos, SEEK_CUR);
echo "seek to: ".ftell($fd_in)."\n";
$buffer = fread($fd_in, $buffer_len);
}
echo "write: ".strlen($buffer)." bytes to output file\n";
fwrite($fd_out, $buffer, strlen($buffer));
}
fclose($fd_out);
fclose($fd_in);
}
It is a prototype for a call from a command line.
this is the simplest way:
$images = glob($location.'/*.jpg');
foreach($images as $image) {
$img = imagecreatefromjpeg($image);
imagejpeg($img,$image,100);
}
I completely misunderstood your question.
You could use some command line tool to do this job. or write your own php extension to do it. have a look at this lib that would be useful: http://www.sno.phy.queensu.ca/~phil/exiftool/
Cheers,
vfn
I'm not pretty sure about it, but if its possible using GD o ImageMagick, the first thing that come to my mind is to create a new Image and add the old image to the new one.