Create array from another array if values are same - php

Question

I have the following array -
Array
(
[31] => Array
(
[0] => 3
[1] => 3
)
[33] => Array
(
[0] => 2
[1] => 1
)
)
Now for the key 31 both of the elements has same value ie 3 but not for the key 33. So I am trying to create another array which will look like.
Array
(
[31] => same
[33] => notsame
)
That means if a key from multidimensional array has got all the values same then it will have the text 'same' else 'notsame'
My code-
foreach($subvaluesArr as $k1=>$v1) //$subvaluesArr is the multidimensional array here
{
foreach($v1 as $k2=>$v2)
{
if($v1[$k2] = $v1[$k2+1])
{
$newArr[$k1] = 'same';
}
else
{
$newArr[$k1] = 'notsame';
}
}
}
echo '<pre>';
print_r($newArr);
echo '</pre>';
And the output is showing 'notsame' for both keys.
Array
(
[31] => notsame
[33] => notsame
)
Any help is highly appreciated.

Answer 1

When you run this snippet, you will get this error
Notice: Undefined index: 2 in /in/bcqEH on line 14
See https://3v4l.org/bcqEH
This is because the code tries to compare first and second, and it tries to compare second and third element. But this third element doesn't exist. This means the comparison fails and sets the value to notsame.
To fix this, you could just compare the first two elements, e.g.
foreach ($subvaluesArr as $k1 => $v1) {
if ($v1[0] == $v1[1]) {
$newArr[$k1] = 'same';
} else {
$newArr[$k1] = 'notsame';
}
}
When you really have more than two elements, you might try array_unique
foreach ($subvaluesArr as $k1 => $v1) {
$u = array_unique($v1);
if (count($u) == 1) {
$newArr[$k1] = 'same';
} else {
$newArr[$k1] = 'notsame';
}
}

Answer 2

You have to break; loop after running the if-else condition.
example :
foreach($subvaluesArr as $k1=>$v1) //$subvaluesArr is the multidimensional array here
{
foreach($v1 as $k2=>$v2)
{
if($v1[$k2] === $v1[$k2+1])
{
$newArr[$k1] = 'same';
}
else
{
$newArr[$k1] = 'notsame';
}
break;
}
}

Answer 3

cant comment so I write it as answer. In your loop when you hit last element of an array, you ask
if($v1[$k2] == $v1[$k2+1])
where $v1[$k2+1] is "undefined" as you are out of bounds. So this last element is always false and you end up with "notsame"