Edit multiple values in ajax - php

Question

I am trying to edit two columns using ajax and php.My code currently edits one values(name) in my table and saves it to my database.When i add the second variable (p) my ajax call it updates both columns p and y with the same value.How do i edit the third value and assign it a different value from y.I want the two different columns to have different values in my db(columns:name and capacity)
This code edits and updates two values:
<script type="text/javascript">
jQuery(document).ready(function() {
$.fn.editable.defaults.mode = 'popup';
$('.xedit').editable();
$(document).on('click','.editable-submit',function(){
var x = $(this).closest('td').children('span').attr('id');
var y = $('.input-sm').val();
var z = $(this).closest('td').children('span');
$.ajax({
url: "process.php?id="+x+"&data="+y,
type: 'GET',
success: function(s){
if(s == 'status'){
$(z).html(y);}
if(s == 'error') {
alert('Error Processing your Request!');}
},
error: function(e){
alert('Error Processing your Request!!');
}
});
});
});
</script>
And this is what i tried to edit three values:
<script type="text/javascript">
jQuery(document).ready(function() {
$.fn.editable.defaults.mode = 'popup';
$('.xedit').editable();
$(document).on('click','.editable-submit',function(){
var x = $(this).closest('td').children('span').attr('id');
var y = $('.input-sm').val();
var p = $('.input-sm').val();
var z = $(this).closest('td').children('span');
$.ajax({
url: "process.php?id="+x+"&data="+y+"&capacity="+y,
type: 'GET',
success: function(s){
if(s == 'status'){
$(z).html(y);
$(z).html(p);}
if(s == 'error') {
alert('Error Processing your Request!');}
},
error: function(e){
alert('Error Processing your Request!!');
}
});
});
});
</script>
And heres my php file(process.php)
<?php
include("connect.php");
if
($_GET['id'],$_GET['capacity'] and $_GET['data'])
{
$id = $_GET['id'];
$data = $_GET['data'];
$capacity = $_GET['capacity'];
if(mysqli_query($con,"update mytable set name='$data',capacity='$data' where id='$id'")){
echo "success";
}
else{
echo 'failed';
}
}
?>
And my table in index.php
<tbody>
<?php
$query = mysqli_query($con,"select * from mytable");
$i=0;
while($fetch = mysqli_fetch_array($query))
{
if($i%2==0) $class = 'even'; else $class = 'odd';
echo'<tr class="'.$class.'">
<td><span class= "xedit external-event bg-brown" id="'.$fetch['id'].'">'.$fetch['name'].'</span></td>
<td><span class= "xedit external-event bg-brown" id="'.$fetch['id'].'">'.$fetch['capacity'].'</span></td>
</tr>';
}
?>
</tbody>

Answer 1

1) your just typo error : capacity=$data look this line and change it to capacity=$capacity :
if(mysqli_query($con,"update mytable set name='$data',capacity='$capacity' where id='$id'"))
2) And take look in If condition too .finally your code should be like this .
<?php
include("connect.php");
if($_GET['id'] && $_GET['capacity'] && $_GET['data'])
{
$id = $_GET['id'];
$data = $_GET['data'];
$capacity = $_GET['capacity'];
if(mysqli_query($con,"update mytable set name='$data',capacity='$capacity' where id='$id'"))
{
echo "success";
}
else
{
echo 'failed';
}
}
?>

Answer 2

You have error in your sql query. As you not passing correct parameters.
Please see below code.
$id = $_GET['id'];
$data = $_GET['data'];
$capacity = $_GET['capacity'];
// Check Sql
$query = "update mytable set name='$data',capacity='$capacity' where id='$id'";
if(mysqli_query($con,$query)){
echo "success";
} else{
echo 'failed';
}