YII2 - How to merge row yii2 gridview? - php

Question

i have gridview table like this :
i want to merge store 1(example) with 4 row detail information. is it possible to do it with?
i have a code in gridview :
<?php Pjax::begin(['id' => 'pjax_filesetting','timeout'=>false]) ?>
<?php
$this->registerJs(
"
$('.btneditfile').click(function(){
var hqid = $(this).attr('data-hqid');
var storeid = $(this).attr('data-storeid');
var filename = $(this).attr('data-filename');
location.href = '/pos/editfilesetting?hqid='+hqid+'&storeid='+storeid+'&filename='+filename;
return false;
});
");
?>
<?= GridView::widget([
'dataProvider' => $dataProvider,
'options' => ['class' => 'grid-view active-table'],
'columns' =>
[
['class' => 'yii\grid\SerialColumn'],
[
'label' => 'Store Name',
'attribute' => 'store_name',
'encodeLabel' => false,
],
[
'label' => 'Filename',
'attribute' => 'filename',
'encodeLabel' => false,
],
[
'label' => 'Datecheck',
'attribute' => 'datecheck',
'encodeLabel' => false,
'value' => function($model){
$datecheck = $model["datecheck"];
if($datecheck)
{
return $model["datecheck"] = "Check";
}
else
{
return $model["datecheck"] = "Not Check";
}
}
],
[
'label' => 'Timecheck',
'attribute' => 'timecheck',
'encodeLabel' => false,
'value' => function($model){
$timecheck = $model["timecheck"];
if($timecheck)
{
return $model["timecheck"] = "Check";
}
else
{
return $model["timecheck"] = "Not Check";
}
}
],
[
'label' => 'Maintenance code',
'attribute' => 'maincode',
'encodeLabel' => false,
],
[
'label' => 'Final Filename',
'attribute' => 'usedfilename',
'encodeLabel' => false,
],
[
'class' => 'yii\grid\ActionColumn',
'template' => '<div align="center">{update} {delete}</div>',
'buttons' => [
'update' => function ($url, $model) use ($controller) {
return Html::button(
'<span class="glyphicon glyphicon-pencil"></span>',
[
'class' => 'btn btn-primary btn-xs btneditfile',
'title' => Yii::t( $controller->transmodule, 'Edit' ),
'style' => ['padding-top' => '5px', 'padding-bottom' => '5px'],
'id' => 'editfile',
'data-storeid' => $model['id'],
'data-hqid' => $model['cmshqid'],
'data-filename' => $model['filename']
]
);
},
'delete' => function ($url, $model)use ($controller){
return Html::button(
'<span class="glyphicon glyphicon-trash"></span>',
[
'class' => 'btn btn-danger btn-xs btndeletefile',
'title' => Yii::t( $controller->transmodule, 'Delete' ),
'style' => ['padding-top' => '5px', 'padding-bottom' => '5px'],
'data-storeid' => $model['id'],
'data-hqid' => $model['cmshqid'],
'data-filename' => $model['filename']
]
);
},
],
]
],
]) ?>
<?php Pjax::end() ?>
what must i do to merge it?
what i need is if the store name is same, merge it column .

Answer 1

Is the store and other details in one table or separate table? If it is in separate tables, the $dataProvider should query from the store table. In the store model create a hasMany relation to the other table which contain the details. So in the view, in the gridview column function you can loop through those values and display it in the same row.