I have an Oracle query which returns date string in the format Y-m-d H:i:s and I need to pass them to the Series::AddXY method. How can I do that?
The "CandleChart.php" example in the Features demo shipped with the product uses DateTimes on the horizontal axis.
Here a variation:
<?php
//Includes
include "../../../../sources/TChart.php";
$chart1 = new TChart(600,450);
$chart1->getChart()->getHeader()->setText("Candle Style");
$chart1->getChart()->getAspect()->setView3D(false);
// Clip Series points
$chart1->getChart()->getAspect()->setClipPoints(true);
$chart1->getChart()->getLegend()->setVisible(false);
// Add Candle data using doubles for date values
$today = time();
$day = 86400;
$hour = 3600;
$chart1->getAxes()->getBottom()->setIncrement(DateTimeStep::$ONEMINUTE);
$chart1->getAxes()->getBottom()->getLabels()->setDateTimeFormat('d/m/Y H:i:s');
$chart1->getAxes()->getBottom()->getLabels()->setAngle(90);
$candle=new Candle($chart1->getChart());
$chart1->setAutoRepaint(false);
for ($i=$today;$i<($today+$hour);$i+=60) {
$candle->addCandle($i,rand(0,100),rand(0,100),rand(0,100),rand(0,100));
}
$chart1->setAutoRepaint(true);
$chart1->doInvalidate();
$chart1->render("chart1.png");
$rand=rand();
print '<font face="Verdana" size="2">Candle Chart Style<p>';
print '<img src="chart1.png?rand='.$rand.'">';
?>
The problem is that I do not have constant time intervals and I can not use a "time machine" as in the Candle example .
The time (X value) I have comes from an Oracle query:
$query = "SELECT ptm.IDENTIFICACAO,
mtr.SERIAL,
TO_CHAR(rtu.DATAHORA, 'yyyy-mm-dd hh24:mi:ss') AS DATAHORA,
So the DateTime value is a string in the PHP date format : Y-m-d H:i:s, which I need to convert to TChart values. I do not know if I am full correct but it
seems that DateTime values should be entered as float values (Unix Timestamp)
So I am converting them as follows:
while( ($row = oci_fetch_array($stmt, OCI_ASSOC)) != false ){
$thetime = DateTime::createFromFormat('Y-m-d H:i:s', $row["DATAHORA"]);
if($thetime)
$tchart->getChart()->getSeries(0)->addXY((float) $thetime->getTimestamp() , $row["ENERTOT"] / 1000);
}
++$rowCount;
}
I hope this can help someone else.
Best regards.
Related
I have SQLite DB one table contains datetime field
with datatype "timestamp" REAL value is 18696.0
attach image for table structure
So, I want this 18696.0 value to be converted into MySQL Y-m-d format and result should be 2021-03-10
I have didn't found any solution online. any help would be appreciated.
SQLite timestamp converted into MySQL timestamp.
EDIT: Thankyou for updating your question with the correct number and what date it should represent.
You can achieve what you need with a function that adds the days onto the Unix Epoch date:
function realDateToYmd($real, $outputFormat='Y-m-d')
{
$date = new DateTime('1970-01-01');
$date->modify('+' . intval($real) . ' days');
return $date->format($outputFormat);
}
echo realDateToYmd('18696.0');
// returns 2021-03-10
SQLite dates stored in REAL data type stores dates as a Julian Day.
From https://www.sqlite.org/datatype3.html
REAL as Julian day numbers, the number of days since noon in Greenwich on November 24, 4714 B.C. according to the proleptic Gregorian calendar.
PHP has a jdtogregorian function, in which one comment has a handy function to convert to ISO8601 dates:
function JDtoISO8601($JD) {
if ($JD <= 1721425) $JD += 365;
list($month, $day, $year) = explode('/', jdtogregorian($JD));
return sprintf('%+05d-%02d-%02d', $year, $month, $day);
}
echo JDtoISO8601('17889.0');
// Results in -4664-11-16
The results don't exactly look right, is it definitely 17889.0 in SQLite?
If this float number 18696.0 represents the number of days since 1970-01-01 then the date can also be calculated like this:
$days = 18696.0;
$dt = date_create('#'.((int)($days * 86400)));
$mysqlDate = $dt->format('Y-m-d'); //"2021-03-10"
background information
Or simply with gmdate:
$mySqlDate = gmdate('Y-m-d',$days*86400);
The days are simply converted into seconds to get a valid timestamp for gmdate.
Try this:
<?php
echo date('Y-m-d H:i:s', 17889);
?>
Output:
1970-01-01 04:58:09
Ive checked the leads here and have not found the right solution,
<?php
$mysqldate = $row['callbackdate'];
$phpcurrentdate = strtotime( $mysqldate );
if ( $phpcurrentdate == date("Y-m-d") ) {
echo $row['last_name'];
}else{
echo "Nothing";
}
?>
The date field in sql is date and the format is YYYY-mm-dd. The answer always being returned is "Nothing". I know this sort of question has many variations but Ive had no luck finding this type. Im not looking for a range sort just a simple match is all... and the data $row['callbackdate']is functioning as Ive tested all other connections.
So Id appreciate any help! Thanks,
Les
$mysqldate = "2017-08-28"; //example
$phpcurrentdate = DateTime::createFromFormat('Y-m-d', $mysqldate); //put your format
$today= new DateTime("now");
if ( $phpcurrentdate == $today ) {
echo 'last_name';
}else{
echo "Nothing";
}
The dates are stored as string in your database. As possible solution to this is formatting both as dateTime for example:
$today = date('Y-m-d H:i:s');
$databaseDate = '2017-08-06 20:50:38';
var_dump(new DateTime($today) > new DateTime($databaseDate)) // returns true
var_dump(new DateTime($today) < new DateTime($databaseDate)) // returns false
Another way to do this is to make your columns type in the database a DateTime. This way you only have to format the current date as a DateTime and then you can compare them
I want to compare two dates and time values in PHP. One date is coming from MySQL, and second one is the current date. I want to run some code when both dates are the same. I tried the code below, but condition satisfies any time which is wrong.
$current_datetime = date('Y-m-d H:i');
$send_date = date("Y-m-d H:i", strtotime($row['send_date'])); // suppose $row['send_date']'s value is '2016-10-17 15:00'
if($current_datetime == $send_date){
//I want to run some code here
}else{
}
What is wrong with the code? I also tried to covert both dates with strtotime() before comparing, but it gave me the same issue. The above condition satisfies any time even if both dates are different.
Try this :
$current_datetime = date('Y-m-d H:i');
$send_date = date("Y-m-d H:i", strtotime($row['send_date'])); // suppose $row['send_date']'s value is '2016-10-17 15:00'
if(strtotime($current_datetime) == strtotime($send_date)){
//I want to run some code here
}else{
}
Hope it helps !!!!
One way is to fetch the Unix timestamp (seconds since '1970-01-01 00:00:00' UTC) from MySQL, then operate on the numbers:
$row = get_db_row("SELECT UNIX_TIMESTAMP(send_date) AS send_date_ts
FROM table WHERE $condition");
$hours = (int) ($row['send_date_ts'] / 3600);
$current_hours = (int) (time() / 3600);
if ($hours == $current_hours) {
// current hour
}
Timestamps are convenient because:
there is no need to take the format into account;
operations on numbers are usually faster;
the code looks cleaner.
Try this. On my server is working just great I've got something else because they aren't equal. Date which I receive from database is type datetime format 2015-04-13 09:03:49
<?php
$current_datetime = strtotime(date('Y-m-d H:i'));
$send_date = date("Y-m-d H:i", strtotime($row['send_date'])); // suppose $row['send_date']'s value is '2016-10-17 15:00'
if($current_datetime == $send_date){
//I want to run some code here
echo 'something';
}else{
echo 'something else';
}
Output:
echo $current_datetime . '<br/>';
2016-10-17 09:19
echo $send_date .'<br/>';
2015-04-13 09:03
// result
something else
I'm required to take a date in the format 'Y-z' which is year-doy (e.g, 2013-146) and convert that into a unix time stamp to be store into a database.
The issue i have is that i input 2013-146 and turn it into a DateTime Object. then when i output this date in unix or 'Y-m-d' format i get 2013-5-27 not 2013-5-26 which is the correct day.
You can verify the DOY on this NASA website and this NOAA website.
Summary:
--I have the date: '2013-146'
--Using DateTime::createFromFormat and echoing using 'Y-m-d' and 'Y-z' i get: 2013-5-27 and 2013-146 respectively.
--This does not agree with the NASA website I listed and is offset by one day can anyone verify that I'm not losing my mind?
Here is the code you can test:
<?php
date_default_timezone_set('America/Chicago');
$year = 2013; //where this outputs a simple year 'CCYY'
$day = 146; //where this provides the day of year
$format = 'Y-z'; //specifying what format i'm creating the datetime with
$date = $year.'-'.$day; //formatting the strings to the above $format
$timezone = new DateTimeZone('America/Chicago'); //specify the timezone
$fileDateStore = DateTime::createFromFormat($format, $date, $timezone);//, $timezone); //create the DateTime object
$fileDateString = date_format($fileDateStore,"Y-m-d"); //format it so strtotime() can read it
$fileDate = strtotime($fileDateString); //finally create the Unix Timestamp for the date.
$newfileDOY = date_format($fileDateStore,"Y-z");
echo 'newfileDOY = '.$newfileDOY.', ';
echo 'date = '.$date.', ';
echo 'fileDateString = '.$fileDateString.', ';
echo 'fileDate = '.$fileDate.PHP_EOL;
?>
The problem is than z format in PHP begins with 0 and not with 1.
Look at: http://www.php.net/manual/en/function.date.php
z: The day of the year (starting from 0)
I have a MySQL database with a list of dates. I want to output all these dates, provided they occur after today, into a page. The dates are stored in the database in DATE format, as Y-m-d.
I've got the following code (excluding the query etc):
$dateToday = date('Y-m-d');
do{
$dateCompare = new DateTime($row['date']);
if ($dateCompare > $dateToday){
echo '<p>'.$dateCompare -> format('Y-m-d').'</p>';
} else {
echo '<p>FALSE</p>';
}
}while ($row = $stmt->fetch(PDO::FETCH_ASSOC));
But this just outputs all the dates, including one I have set in the past for testing purposes. What am I doing wrong?
$dateToday is a string. $dateCompare is a DateTime object.
You should use strtotime() function.
http://www.w3schools.com/php/func_date_strtotime.asp
Try and convert the date from myssql to a datetime object and output.
$changetime = new DateTime($time, new DateTimeZone('UTC'));
ECHO $changetime->format('m/d/y h:i a');
// list of timezones http://us1.php.net/manual/en/timezones.php
I actually use this to output all my MYSQL datetime data - allows me to convert to any timezone. Note, this will assume your datetime is in UTC - you should convert to your timezone.
$stmt->setFetchMode(PDO::FETCH_ASSOC);
foreach ($stmt as $row) {
$time = strtotime($row['date']);
if ($_SERVER['REQUEST_TIME'] - $time) {
echo '<p>'. date('Y-m-d', $time) . '</p>';
} else {
echo '<p>FALSE</p>';
}
}