Dynamically Added Input fields passed Validation and submit cannot to another page - php

I 'm beginner, In dynamically added Input fields Reference From: Validate Dynamically Added Input fields, when passed Validation and submit cannot to another page
Follow script sample.
<script src="js/jquery-3.1.1.min.js"></script>
<script src="js/jquery.validate.js"></script>
<script type="text/javascript">
$(document).ready(function() {
var numberIncr = 1; // used to increment the name for the inputs
function addInput() {
$('#inputs').append($('<input class="comment" name="name'+numberIncr+'" />'));
numberIncr++;
}
$('form.commentForm').on('submit', function(event) {
// adding rules for inputs with class 'comment'
$('input.comment').each(function() {
$(this).rules("add",
{
required: true
})
});
// prevent default submit action
event.preventDefault();
// test if form is valid
if($('form.commentForm').validate().form()) {
console.log("validates");
} else {
console.log("does not validate");
}
})
// set handler for addInput button click
$("#addInput").on('click', addInput);
// initialize the validator
$('form.commentForm').validate();
});
</script>
when passed validation click submit butt cannot to action="/action_page_post.php"
And HTML code
<form class="commentForm" method="get" action="/action_page_post.ph">
<div>
<p id="inputs">
<input class="comment" name="name0" />
</p>
<input class="submit" type="submit" value="Submit" />
<input type="button" value="add" id="addInput" />
</div>
</form>

Changes I made
changed on('submit') to submitbutton.onclick
added $('.commentForm').submit(); inside the if condition which execute if the validation is true
Reason : Since you are using event.preventDefault(), it will prevent the default behaviour of the form and so did not go to next page. So You have to submit the form manually using $(form).submit();
The below code will work on normal page but not on SO Snippet
$(document).ready(function() {
var numberIncr = 1; // used to increment the name for the inputs
function addInput() {
$('#inputs').append($('<input class="comment" name="name'+numberIncr+'" />'));
numberIncr++;
}
$('input.submit').click(function(event) {
// adding rules for inputs with class 'comment'
$('input.comment').each(function() {
$(this).rules("add",
{
required: true
});
});
// prevent default submit action
event.preventDefault();
// test if form is valid
if($('form.commentForm').validate().form()) {
console.log("validates");
$('.commentForm').submit();
} else {
console.log("does not validate");
}
})
// set handler for addInput button click
$("#addInput").on('click', addInput);
// initialize the validator
$('form.commentForm').validate();
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery-validate/1.16.0/jquery.validate.min.js"></script>
<form class="commentForm" method="get" action="action_page_post.php">
<div>
<p id="inputs">
<input type="text" class="comment" name="name0" />
</p>
<input class="submit" type="submit" value="Submit" />
<input type="button" value="add" id="addInput" />
</div>
</form>

Related

how to show error in jquery after clicking submit button

My problem is that after clicking on submit button the page will go to php file any way my html code is like this
<form action="register.php" method="post">
<input type="text" name="name" id="name"><div id="adiv"></div>
<input type="submit" value="submit" id="button">
</form>
and my jquery code goes like this
$('#name').focusout(function(){
if($('#name').val().length==0){
$('#adiv').html("please enter name")
}
});
$('#button').click(function(){
if($('#name').val().length==0){
$('#adiv').html("please enter your name")
}
});
but after clicking submit button it redirects to php file and doesn't show any error and store blank data in the database.
Because your input type is submit you can either change the type to button or add event.preventDefault() to avoid automatic passing of form
use event.preventDefault()
$('#button').click(function(e) {
e.preventDefault();//this will stop form auto submit thus showing your error
if ($('#name').val().length == 0) {
$('#adiv').html("please enter your name")
}
});
Or
<input type="submit" value="submit" id="button">
change to
<input type="button" value="submit" id="button">//also prevent form auto submit thus will show the error
Well you need to stop the code to execute after error has been detected. For example you can simple use return false or return:
$('#name').focusout(function() {
if ($('#name').val().length == 0) {
$('#adiv').html("please enter name")
}
});
$('#button').click(function() {
if ($('#name').val().length == 0) {
$('#adiv').html("please enter your name")
return false;//add this
}
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form action="register.php" method="post">
<input type="text" name="name" id="name">
<div id="adiv"></div>
<input type="submit" value="submit" id="button">
</form>
I strongly recommend never to assign validation to a submit button click.
Instead assign the submit event handler of the form.
I also added trim and removed the content of the error from the code.
$(function() {
$('#name').focusout(function() {
var empty = $.trim($('#name').val()).length == 0;
$('#adiv').toggle(empty);
});
$('#form1').on("submit",function(e) {
$('#name').focusout();
if ($('#adiv').is(":visible")) {
e.preventDefault()
}
});
});
#adiv { display:none }
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<form action="register.php" method="post" id="form1">
<input type="text" name="name" id="name">
<div id="adiv">please enter name</div><br/>
<input type="submit" value="submit" id="button">
</form>
Please check this
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form method="post">
<input type="text" name="name" id="name">
<div id="adiv"></div>
<input type="button" value="submit" id="button">
</form>
<script>
$(document).ready(function(){
$('#button').on('click',function(){
if($('#name').val() == ''){
$('#adiv').text("Please enter name!!");
}else{
$('#adiv').text($('#name').val());
}
})
})
</script>
try this..:D
function validateFunction(){
if(document.getElementByID('name').value.length==0){
document.getElementByID('adiv').innerHTML = "please enter your name";
return false;
}
return true;
}
<input type="submit" value="submit" id="button" onclick="return validateFunction();" />
$('your-form').on('submit', function(e) {
e.preventDefault();
//your code bere
});
preventDefault stop the normal submit behaviour of your browser so that you can trigger any event you want

Redirect GET form with action in another url

I have a form with the action set to "/resutls". But i have a txt input and i want to check if that is not empty to redirect to another location than "/results". Is this possible?
Code example as below:
<form id="results" action="/results" method="get">
<select id="country" name="country">
....
</select>
<input type="text" name="id">
<input type="submit" class="form-submit" value="Apply Search" name="submit">
</form>
Any ideas? Can this be done with jquery?
Sure you can do that in the submit handler. Warning: I wouldn't give a form control a name of id. It does cause confusion: if this refers to the form, should this.id refer to the id of the form or the text field with name="id"?
if( !!this.somefield.value ) { //did not want to write this.id.value !!!!
this.action = '/other-url';
} else {
this.action = '/results';
}
$(function() {
$('#results').on('submit', function(e) {
e.preventDefault(); // just so we can see that form action changes
if( !!this.somefield.value ) {
this.action = '/other-url';
} else {
this.action = '/results';
}
alert( this.action );
//$(this)[0].submit(); //now submit the form
});
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<form id="results" action="/results" method="get">
<select id="country" name="country">
</select>
<input type="text" name="somefield">
<input type="submit" class="form-submit" value="Apply Search" name="submit">
</form>
Yes it is possible. Just set the form element's action property using jQuery .prop().
As a simple example:
var valid = false;
// go though validation here
if (false === valid) {
$('#results').prop('action', '/some/url/to/redirect/to');
}
HTML5 provides the "required" attribute wich will prevent the form for being posted, use it like this
<input type="text" name="id" required="required">
or, if you prefer to redirect to other page instead, you can do this
<script src="js/jquery-1.11.1.min.js" type="text/javascript"></script>
<script>
$("#results").submit(function (e){
e.preventDefault();
if($("#results input[name='id']").length < 1){
window.location.href = "your detiny url";
}
else{
this.submit();
}
});
</script>

jQuery form plugin , how to submit only visible fields

Using the jQuery form plugin, I just want to submit the visible fields (not the hidden ones ) of the form.
HTML:
<div class="result"></div>
<form id="myForm" action="comment.php" method="post">
Name: <input type="text" name="name" />
Comment: <textarea name="comment"></textarea>
<div style="display:none;">
<input type="text" value="" name="name_1" />
</div>
<input type="submit" value="Submit Comment" />
</form>
I cannot find a way to submit only the visible fields using any of the methods below:
ajaxForm:
// wait for the DOM to be loaded
$(document).ready(function() {
// bind 'myForm' and provide a simple callback function
$('#myForm').ajaxForm(function() {
alert("Thank you for your comment!");
});
});
ajaxSubmit:
$('#myForm').ajaxSubmit({
target: '.result',
success: function(response) {
alert("Thank you for your comment!");
}
});
There is another method formSerialize but found no way to use it with the 2 methods mentioned above (usable with $.ajax however).
How to submit only the visible fields using any of the two methods ?
$("#myForm").on("submit", function() {
var visibleData = $('#myForm input:visible,textarea:visible,select:visible').fieldSerialize();
$.post(this.action, visibleData, function(result) {
alert('Thank you for your comment!');
});
// this is needed to prevent a non-ajax submit
return false;
});

Jquery for submiting without refresh (no validation required)

I have a form for Tags that is working OK, with some server validation, I would like to add a Jquery to submit the content without refreshing:
<form method="post" action="tags">
<div>
<input type="hidden" name="id" value="getId()" />
<input type="text" name="tag" />
<input type="submit" value="Add" name="add" />
</div>
</form>
Any advice will be highly appreciated.
Check out the jQuery Form Plugin. Using it, you can submit a form without reloading the page like so:
<form id="aForm" action="target.php" method="post>
...
</form>
<script type="text/javascript">
$(document).ready(function() {
$("#aForm").ajaxForm();
});
</script>
The ajaxForm() function also supports all options (such as a callback function) that can be passed to the standard jQuery $.ajax function.
$(document).ready(function() {
$(form).submit( function() { // could use $(#submit).on('click', function(){ as well
$.ajax({
url: 'yourposturl',
data: $(form).serialize(),
Success: function() {
alert('ok');
}
}); //end ajax
return false;
}); //end submit()
});
Should take all form vars , serialize them so the server can receive, the return false is so page doesnt refresh on submit (stops propagation and default)
Add the JQuery javascript library
Turn the submit into a button
<button id="submitbutton" >Add</button>
Add ids to your inputs
<input type="text" id="tag" name="tag" />
And add the jquery to the click for the button ...
<script type="text/javascript">
$(document).ready(function() {
$("#submitbutton").button().click(function(){
$.post("tags.php",{id: $("#id").val(), tag: $("#tag").val()});
});
});
</script>
<form method="post" action="tags">
<div>
<input type="hidden" name="id" value="getId()" />
<input type="text" name="tag" />
<input class="button" type="button" value="Add" name="add" />
</div>
</form>
$(function(){
$('.button').click(function(){
var data = $('form').serializeToObject();
$.post('tags.php', data);
});
});
// jQuery Extension to serialize a selector's elements to an object
$.fn.serializeToObject = function () {
var o = {};
var a = this.serializeArray();
$.each(a, function () {
if (o[this.name] !== undefined) {
if (!o[this.name].push) {
o[this.name] = [o[this.name]];
}
o[this.name].push(this.value || '');
} else {
o[this.name] = this.value || '';
}
});
return o;
};

Ajax with multiple submit buttons

How can I change the code below so instead of a text input type with a submit button I want multiple submit buttons each with their own unique value? Everything I try just ends up with submit's value being undefined. Any help would be great!
Code source: Submit Search query & get Search result without refresh
<script type="text/javascript">
$(function() {
$("#lets_search").bind('submit',function() {
var value = $('#str').val();
$.post('db_query.php',{value:value}, function(data){
$("#search_results").html(data);
});
return false;
});
});
</script>
<form id="lets_search" action="" >
Search:<input type="text" name="str" id="str">
<input type="submit" value="send" name="send" id="send">
</form>
You can add multiple submit buttons and attach to all of them onclick event listener. When button was clicked - get the value and send with a POST request.
<script>
$(function(){
$('input[type=submit]').click(function(){
$.post('db_query.php', {value:$(this).val()}, function(data){
$("#search_results").html(data);
});
return false;
});
});
</script>
<form id="lets_search" action="">
<input type="submit" name="button1" value="hi"/>
<input type="submit" name="button2" value="bye"/>
</form>
If you want to use multiple submit buttons, you can catch the click event and determine which button was clicked. then run different Ajax submit. this also works when enter is hit.
//submit buttons
<form id="lets_search" action="" >
Search:<input type="text" name="str" id="str" />
<input type="submit" value="v1"/>
<input type="submit" value="v2"/>
//...more submit buttons
</form>
//submit func
$(function() {
$("#lets_search input[type=submit]").click(function() {
switch ($(this).val){
case 'v1':...;
case 'v2':...
}
});
});
Here is my version - which now looks very much like Bingjies because it was written while I was testing out his version
DEMO
<form id="lets_search" action="" >
Search:<input type="text" name="q" id="q">
<input type="submit" value="Google" name="send" id="google">
<input type="submit" value="Bing" name="send" id="bing">
</form>
$(function() {
$("#lets_search input[type=submit]").click(function() {
switch ($(this).val()) {
case "Bing" :
$("#lets_search").attr("action","http://www.bing.com/search");
break;
case "Google":
$("#lets_search").attr("action","https://www.google.com/search");
break;
}
});
});
Here, I would prefer to Vamsi's solution n Why not Sanjeev mk?
Give some extra thought on prefering the solution.
case: If there are mulitple submit buttons
If the user is in the text field and hits enter, the system will assume the first submit button was hit.
So, here, it would be good to go for not having mulitple submit
buttons for end user point of view
You can have multiple submit buttons in the form, no problem. They may have the same name, type etc, but just assign them different values. Like Submit Button 1 can have value="hi" and Button 2 can have value="bye".
Then when the action function is called for the button, all you have to do when entering the function is do a check with: $(this).val
HTML:
<input type="submit" name="button1" value="hi"/>
<input type="submit" name="button2" value="bye"/>
jQuery:
$(function() {
$("#lets_search").bind('submit',function() {
var value = $(this).val();
if(value == "hi")
do_something;
else
do_something_else;
});
});

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