Issues with Inserting array hidden form values into the database [duplicate] - php

I have seen a ton of people like me posting about this issue on this forum.
I have not been able to resolve my own issue from any of those examples.
For instance, this code below is from a page called review.php:
<?php
error_reporting(E_ALL);
echo "DEBUG POST DATA: <pre>".print_r($_POST, 1)."</pre>";
if(isset($_POST['employeename']))
$employeename = $_POST['employeename'];
if(isset($_POST['email']))
$email = $_POST['email'];
if(isset($_POST['ttitle']))
$ttitle = $_POST['ttitle'];
$rowIDs = $_POST['rowIDs'];
$row2IDs = $_POST['row2IDs'];
echo $employeename .'<br>';
echo $ttitle .'<br> <hr width=400 align=left>';
$rowIDs = $_POST['rowIDs'];
foreach ($rowIDs as $id) {
$sourcename = $_POST['sourcename' . $id];
$sourceaddress = $_POST['sourceaddress' . $id];
$income = $_POST['income' . $id];
echo 'Name: '. $sourcename . '<br />';
echo 'Address: '. $sourceaddress . '<br />';
echo 'Income: '. $income . '<br /><br>';
}
foreach ($row2IDs as $id) {
$spousename = $_POST['spousename' . $id];
$spouseAddress = $_POST['spouseAddress' . $id];
$spouseIncome = $_POST['spouseIncome' . $id];
echo 'Name: '. $spousename . '<br />';
echo 'Address: '. $spouseAddress . '<br />';
echo 'spouseIncome: '. $spouseIncome . '<br /><br>';
echo 'Your email: '. $email . '<br /><br>';
}
?>
<body>
<form action='final.php' method = 'POST'>
<input type="hidden" name="employeename" value="<?php echo $employeename; ?>">
<input type="hidden" name="ttitle" value="<?php echo $ttitle; ?>">
<input type="hidden" name="sourcename[]" value="<?php echo $_POST['sourcename' . $id]; ?>">
<input type="hidden" name="sourceaddress[]" value="<?php echo $_POST['sourceaddress' . $id]; ?>">
<input type="hidden" name="income[]" value="<?php echo $_POST['income' . $id]; ?>">
<input type="hidden" name="spousename[]" value="<?php echo $_POST['spousename' . $id]; ?>">
<input type="hidden" name="spouseAddress[]" value="<?php echo $_POST['spouseAddress' . $id]; ?>">
<input type="hidden" name="spouseIncome[]" value="<?php echo $_POST['spouseIncome' . $id]; ?>">
Return to correct changes <input type="submit" value="submit" />
</form>
</body>
When I run it, I get:
Notice: Array to string conversion in C:\xampp\htdocs\folder\forms\final.php on line 70
The error points to this line:
if( mysqli_stmt_execute($sth) ) {...
which is a part of the following insert statement:
$sql = 'INSERT INTO `mydb`.`wp_mytable` ( `employeeID`'
. ', `sourcename`, `sourceaddress`, `income`,`spousename`,`spouseAddress`,`spouseincome` )'
. ' VALUES ( ? , ? , ? , ? , ? , ? , ? )';
if( $sth = mysqli_prepare($conn,$sql) ) {
mysqli_stmt_bind_param($sth,'sssssss'
,$last_id
,$_POST["sourcename"]
,$_POST["sourceaddress"]
,$_POST["income"]
,$_POST["spousename"]
,$_POST["spouseAddress"]
,$_POST["spouseIncome"]
);
I also know that I need to do a FOR loop on these fields like this one below that I am passing as an array in hidden form.
<input type="hidden" name="sourcename[]" value="<?php echo $_POST['sourcename' . $id]; ?>">
How do incorporate a foreach loop on these hidden form fields on review.php so that users can store as many rows as possible without these errors getting in the way?
Thank you

Related

It is not possible to output data from MySQL (Wordpress)

I use a Wordpress site, I do my search on a custom database called "operations". The search is performed on the website.
I need to get other results from the table related to this row on request, not just what I entered. And get other data related to this string. Here is the search form on the site:
<form method="post" action="https://site-name.com/wp-content/themes/theme/select_user.php">
<label for="sku">SKU:</label><br/>
<input type="text" name="sku" size="30"><br/>
<label for="barcode">Barcode:</label><br/>
<input type="text" name="barcode" size="30"><br/>
<input id="submit" type="submit" value="Search"><br/>
</form>
</fieldset>
The database has the following columns: id, date, title, size, sku, barcode, price
File Contents select_user.php:
require( __DIR__ . '/../../../wp-load.php' );
global $wpdb;
$sku = trim($_REQUEST['sku']);
$barcode = trim($_REQUEST['barcode']);
$sql_select = $wpdb->get_results(
$wpdb->prepare(
"
SELECT * FROM " . $wpdb->prefix . "operations
WHERE sku='$sku' || barcode='$barcode',
ARRAY_N
"
)
);
if ($sql_select)
{
foreach($sql_select as $row)
{
echo 'SKU: ' . $row['sku'] .'</br>';
echo 'Barcode: ' . $row['barcode'] .'</br>';
}
}
else {
echo 'No results';
}
With this code, I get the answer "no results".
I would be grateful for any help
use the post hook for wp forms not directly use .php file
add_action( 'admin_post_add_foobar', 'prefix_admin_add_foobar' );
function prefix_admin_add_foobar() {
// Handle request then generate response using echo or leaving PHP and using HTML
}
for your form use :
<form action="http://www.example.com/wp-admin/admin-post.php" method="post">
<input type="hidden" name="action" value="add_foobar">
<input type="hidden" name="data" value="foobarid">
<input type="submit" value="Submit">
</form>
I created my own shortcode, and placed everything that is necessary there. Everything works.
function custom_search_func( $atts ){
echo '<fieldset>
<form action="' . get_permalink() . '" method="POST">
<label for="sku">SKU:</label><br/>
<input type="text" name="sku" size="30"><br/>
<label for="barcode">Barcode:</label><br/>
<input type="text" name="barcode" size="30"><br/>
<label for="date">Date:</label><br/>
<input type="date" name="date" size="30"><br/>
<input type="submit" value="Search">
</form>
</fieldset>';
global $wpdb;
$sku = trim($_REQUEST['sku']);
$barcode = trim($_REQUEST['barcode']);
$date = trim($_REQUEST['date']);
$sql_select = $wpdb->get_results(
$wpdb->prepare(
"
SELECT id, date, title, size, barcode, sku, price FROM " . $wpdb->prefix . "operations
WHERE sku='$sku' || barcode='$barcode' || date='$date'
"
)
);
if ($sql_select)
{
echo '<table border="1" width="100%" cellpadding="5">';
echo '<tr><th>ID</th>';
echo '<th>Title</th>';
echo '<th>Size</th>';
echo '<th>SKU</th>';
echo '<th>Barcode</th>';
echo '<th>Price</th>';
echo '<th>Date</th></tr>';
foreach ( $sql_select as $id) {
echo '<tr>';
echo '<td>';
echo $id->id;
echo '</td>';
echo '<td>';
echo $id->title;
echo '</td>';
echo '<td>';
echo $id->size;
echo '</td>';
echo '<td>';
echo $id->sku;
echo '</td>';
echo '<td>';
echo $id->barcode;
echo '</td>';
echo '<td>';
echo $id->price;
echo '</td>';
echo '<td>';
echo $id->date;
echo '</td>';
echo '</tr>';
}
echo '</table>';
}
else {
echo 'No results';
}
}
add_shortcode( 'customsearch', 'custom_search_func' );
Use the [customsearch] shortcode to output this anywhere on the page

How do I get rid of this Notice: Array to string conversion in... error

I have seen a ton of people like me posting about this issue on this forum.
I have not been able to resolve my own issue from any of those examples.
For instance, this code below is from a page called review.php:
<?php
error_reporting(E_ALL);
echo "DEBUG POST DATA: <pre>".print_r($_POST, 1)."</pre>";
if(isset($_POST['employeename']))
$employeename = $_POST['employeename'];
if(isset($_POST['email']))
$email = $_POST['email'];
if(isset($_POST['ttitle']))
$ttitle = $_POST['ttitle'];
$rowIDs = $_POST['rowIDs'];
$row2IDs = $_POST['row2IDs'];
echo $employeename .'<br>';
echo $ttitle .'<br> <hr width=400 align=left>';
$rowIDs = $_POST['rowIDs'];
foreach ($rowIDs as $id) {
$sourcename = $_POST['sourcename' . $id];
$sourceaddress = $_POST['sourceaddress' . $id];
$income = $_POST['income' . $id];
echo 'Name: '. $sourcename . '<br />';
echo 'Address: '. $sourceaddress . '<br />';
echo 'Income: '. $income . '<br /><br>';
}
foreach ($row2IDs as $id) {
$spousename = $_POST['spousename' . $id];
$spouseAddress = $_POST['spouseAddress' . $id];
$spouseIncome = $_POST['spouseIncome' . $id];
echo 'Name: '. $spousename . '<br />';
echo 'Address: '. $spouseAddress . '<br />';
echo 'spouseIncome: '. $spouseIncome . '<br /><br>';
echo 'Your email: '. $email . '<br /><br>';
}
?>
<body>
<form action='final.php' method = 'POST'>
<input type="hidden" name="employeename" value="<?php echo $employeename; ?>">
<input type="hidden" name="ttitle" value="<?php echo $ttitle; ?>">
<input type="hidden" name="sourcename[]" value="<?php echo $_POST['sourcename' . $id]; ?>">
<input type="hidden" name="sourceaddress[]" value="<?php echo $_POST['sourceaddress' . $id]; ?>">
<input type="hidden" name="income[]" value="<?php echo $_POST['income' . $id]; ?>">
<input type="hidden" name="spousename[]" value="<?php echo $_POST['spousename' . $id]; ?>">
<input type="hidden" name="spouseAddress[]" value="<?php echo $_POST['spouseAddress' . $id]; ?>">
<input type="hidden" name="spouseIncome[]" value="<?php echo $_POST['spouseIncome' . $id]; ?>">
Return to correct changes <input type="submit" value="submit" />
</form>
</body>
When I run it, I get:
Notice: Array to string conversion in C:\xampp\htdocs\folder\forms\final.php on line 70
The error points to this line:
if( mysqli_stmt_execute($sth) ) {...
which is a part of the following insert statement:
$sql = 'INSERT INTO `mydb`.`wp_mytable` ( `employeeID`'
. ', `sourcename`, `sourceaddress`, `income`,`spousename`,`spouseAddress`,`spouseincome` )'
. ' VALUES ( ? , ? , ? , ? , ? , ? , ? )';
if( $sth = mysqli_prepare($conn,$sql) ) {
mysqli_stmt_bind_param($sth,'sssssss'
,$last_id
,$_POST["sourcename"]
,$_POST["sourceaddress"]
,$_POST["income"]
,$_POST["spousename"]
,$_POST["spouseAddress"]
,$_POST["spouseIncome"]
);
I also know that I need to do a FOR loop on these fields like this one below that I am passing as an array in hidden form.
<input type="hidden" name="sourcename[]" value="<?php echo $_POST['sourcename' . $id]; ?>">
How do incorporate a foreach loop on these hidden form fields on review.php so that users can store as many rows as possible without these errors getting in the way?
Thank you

How to get value from input with data from database

I am having a table with <input type="text" name="' . $r['0'] . '" value="' . $r['0'] . '"
populated from data that i fetch from database like this:
echo '<form id="actions" name="nonValidMainForm" method="post"><table border="2" width="100%">';
echo "<tr><td><b>Index</b></td><td><b>Email </b></td> <td><b>Date</b></td> <td><b>Name</b></td> <td><b>Surname</b></td> <td><b>Telephone Number</b></td> <td><b>Street Adress</b></td><br/>";
while($r = mysql_fetch_array($result)) {
$my[] = $r['0'];
echo '<tr>';
echo '<td>'.$roww++.'</td>';
echo '<td>
<input size="50%" type="text" name="' . $r['0'] . '" value="'.$r['0'].'">
<input type="submit" name="unsubscribe" value="Unsubscribe">
</td>';
echo '<td>'.$r['1'].'</td>';
echo '<td>'.$r['2'].'</td>';
echo '<td>'.$r['3'].'</td>';
echo '<td>'.$r['4'].'</td>';
echo '<td>'.$r['5'].'</td>';
echo '</tr>';
}
echo "<pre>";
print_r($my);
echo "</pre>";
if(isset($_POST['unsubscribe'])){
foreach($my as $key=>$value){
$email = $value;
}
echo "<script>console.log( 'Value is: " . $email . "' );</script>";
}
echo '<button style="position:fixed;bottom:5;left:5;">Change</button>';
echo '</table></form>';
The table looks like this:
I have tried this:
if(isset($_POST['unsubscribe'])){
$email = $POST['email'];
echo "<script>console.log( 'Value is: " . $email . "' );</script>";
}
But the value is empty
So each time i press unsubscribe button the corresponding email to be deleted. How is this possible?
Your form has many elements with the same name. How can the browser determine which element's value to send to the server when the form is posted? Generally the last one takes precedence, but I suspect that behavior may be undefined and browser-specific.
If each individual table row needs to be a separately post-able form, then each row needs its own form:
echo '<td>
<form method="POST" action="somePage.php">
<input size="50%" type="text" name="email" value="'.$r['0'].'">
<input type="submit" name="unsubscribe" value="Unsubscribe">
</form>
</td>';
That way when the browser posts the form to the server, it knows specifically which email and unsubscribe elements to use. Since there's only one of each for that form.
You have to wrap your inputs in a <form> tag.
echo '<form>';
while($r = mysql_fetch_array($result)) {
echo '<tr>';
echo '<td>'.$roww++.'</td>';
echo '<td>
<input size="50%" type="text" name="email" value="'.$r['0'].'">
<input type="submit" name="unsubscribe" value="Unsubscribe">
</td>';
echo '<td>'.$r['1'].'</td>';
echo '<td>'.$r['2'].'</td>';
echo '<td>'.$r['3'].'</td>';
echo '<td>'.$r['4'].'</td>';
echo '<td>'.$r['5'].'</td>';
echo '</tr>';
}
echo '</form>';
if(isset($_POST['unsubscribe'])){
$email = $POST['email'];
echo "<script>console.log( 'Value is: " . $email . "' );</script>";
}
Based on your code above it looks like it's a syntax error. Try the update below
if(isset($_POST['unsubscribe'])){
$email = $_POST['email'];
echo "<script>console.log( 'Value is: " . $email . "' ); </script>";
}

PHP and mySQL "UPDATE" doesn't actually update

So me and my friend came to a conclusion that it's the $_email variable that screws everything up. As long as it's hard coded in, it works. But as soon as it's left as a $_email everywhere, it doesn't. The message goes through as "updated" but it doesn't update.
require_once('appVars6.php');
require_once('connectVars6.php');
$_dbc = mysqli_connect(DB_HOST, DB_USER, DB_PASSWORD, DB_NAME);
$_id = $_GET['id'];
$_queryOne = "SELECT * FROM midterm WHERE id = '$_id'";
$_resultOne = mysqli_query($_dbc, $_queryOne) or die ('Error Querying Database');
while ($_row = mysqli_fetch_array($_resultOne)) {
echo '<form class="update" method="post" action="MT_vjones_udpateRecord.php?id=' . $_id . '">';
echo '<input type="hidden" name="id" id="id" value="' . $_row['id'] . '" />';
echo '<input type="text" name="firstName" id="firstName" value="' . $_row['firstName'] . '" /><br />';
echo '<input type="text" name="lastName" id="lastName" value="' . $_row['lastName'] . '" /><br />';
echo '<input type="text" name="email" id="email" value="' . $_row['email'] . '" /><br />';
echo '</form>';
}
if ( isset($_GET['firstName']) && isset($_GET['lastName']) && isset($_GET['email'])) {
$_id = $_GET['id'];
$_firstName = $_GET['firstName'];
$_lastName = $_GET['lastName'];
$_email = $_GET['email'];
}
else if ( isset($_POST['firstName']) && isset($_POST['lastName']) && isset($_POST['email'])) {
$_id = $_POST['id'];
$_firstName = mysqli_real_escape_string($_dbc, trim($_POST['firstName']));
$_lastName = mysqli_real_escape_string($_dbc, trim($_POST['lastName']));
$_email = mysqli_real_escape_string($_dbc, trim($_POST['email']));
}
else {
echo '<br />';
echo '<p class="error">Sorry, no record was selected.</p>';
}
if(isset($_POST['submit'])) {
if ($_POST['confirm'] == 'Yes') {
//$_dbc = mysqli_connect(DB_HOST, DB_USER, DB_PASSWORD, DB_NAME);
$_query = "UPDATE midterm " .
"SET email = '$_email'" .
"WHERE id = $_id" ;
$_result = mysqli_query($_dbc, $_query) or die (mysqli_error($_dbc));
mysqli_close($_dbc);
echo '<p>The record of ' . $_firstName . ' ' . $_lastName . ' for ' . $_email . ' was successfully updated.';
}
else {
echo '<p class="error">The record was not updated.</p>';
}
}
else if (isset($_id) && isset($_firstName) && isset($_lastName) && isset($_email)) {
echo '<p>Are you sure you want to update the following record?</p>';
/*echo '<form class="update" method="post" action="MT_vjones_updateRecord.php">';
echo '<input type="text" name="firstName" id="firstName" value="' . $_firstName . '" /><br />';
echo '<input type="text" name="lastName" id="lastName" value="' . $_lastName . '" /><br />';
echo '<input type="text" name="email" id="email" value="' . $_email . '" /><br />';
echo '</form>';*/
echo '<form class="update" method="post" action="MT_vjones_updateRecord.php?id=' . $_id . '">';
echo '<div class="yesNo"><input class="radio" type="radio" name="confirm" value="Yes" /> Yes </div><br />';
echo '<div class="yesNo"><input class="radio" type="radio" name="confirm" value="No" checked="checked" /> No </div><br /><br />';
echo '<input class="applyBtn" type="submit" value="UPDATE" name="submit" />';
echo '<input type="hidden" name="id" value="' . $_id . '" />';
echo '<input type="hidden" name="firstName" value="' . $_firstName . '" />';
echo '<input type="hidden" name="lastName" value="' . $_lastName . '" />';
echo '<input type="hidden" name="email" value="*testBACK2FUN#test.com*" />';
}
echo '<p><< Back to the Admin Page</p>';
As you can see, we put in the email address in there for testing purposes...
check the id matches what you are intending to update.
To be sure print the $_id and $_email prior to the update and after.
#user710502: You don't need to segregate quotes with double-quotes in PHP. It reads it anyway, the only time you might bother is if you are reading from an array
eg:
"UPATE midterm SET email='".$POST['email']."'"
$_query = "UPDATE midterm " .
"SET email = '$_email' WHERE id = '$_id'" ;
should be
$_query = "UPDATE midterm " .
"SET email = $_email".
"WHERE id = $_id " ;
Reason is you are using $_ before variable which is not a valid variable declaration.
Because $_ is reserved for SUPER GLOBAL in php (i.e $_SESSION,$_SERVER,$_POST,$_GET,$_COOKIE etc).
if its not a issue for you then you need to concat your variable as below.
$_query = "UPDATE midterm SET email = '".$_email."' WHERE id = '".$_id."'" ;
SOLVED! Form issues.
SHOULD BE:
<?php
require_once('appVars6.php');
require_once('connectVars6.php');
$_dbc = mysqli_connect(DB_HOST, DB_USER, DB_PASSWORD, DB_NAME);
$_id = $_GET['id'];
$_queryOne = "SELECT * FROM midterm WHERE id = '$_id'";
$_resultOne = mysqli_query($_dbc, $_queryOne) or die ('Error Querying Database');
while ($_row = mysqli_fetch_array($_resultOne)) {
echo '<form class="update" method="post" action="MT_vjones_udpateRecord.php?id=' . $_id . '">';
echo '<input type="hidden" name="id" id="id" value="' . $_row['id'] . '" />';
echo '<input type="hidden" name="firstName" id="firstName" value="' . $_row['firstName'] . '" />';
echo '<input type="hidden" name="lastName" id="lastName" value="' . $_row['lastName'] . '" />';
echo '<input type="hidden" name="email" id="email" value="' . $_row['email'] . '" />';
echo '</form>';
}
if ( isset($_GET['firstName']) && isset($_GET['lastName']) && isset($_GET['email'])) {
$_id = $_GET['id'];
$_firstName = $_GET['firstName'];
$_lastName = $_GET['lastName'];
$_email = $_GET['email'];
}
else if ( isset($_POST['firstName']) && isset($_POST['lastName']) && isset($_POST['email'])) {
$_id = $_POST['id'];
$_firstName = mysqli_real_escape_string($_dbc, trim($_POST['firstName']));
$_lastName = mysqli_real_escape_string($_dbc, trim($_POST['lastName']));
$_email = mysqli_real_escape_string($_dbc, trim($_POST['email']));
}
else {
echo '<br />';
echo '<p class="error">Sorry, no record was selected.</p>';
}
if(isset($_POST['submit'])) {
if ($_POST['confirm'] == 'Yes') {
$_query = "UPDATE midterm " .
"SET email = '$_email'" .
"WHERE id = $_id" ;
$_result = mysqli_query($_dbc, $_query) or die (mysqli_error($_dbc));
mysqli_close($_dbc);
echo '<p>The record of ' . $_firstName . ' ' . $_lastName . ' for ' . $_email . ' was successfully updated.';
}
else {
echo '<p class="error">The record was not updated.</p>';
}
}
else if (isset($_id) && isset($_firstName) && isset($_lastName) && isset($_email)) {
echo '<p>Are you sure you want to update the following record?</p>';
echo '<form class="update" method="post" action="MT_vjones_updateRecord.php?id=' . $_id . '">';
echo '<div class="yesNo"><input class="radio" type="radio" name="confirm" value="Yes" /> Yes </div><br />';
echo '<div class="yesNo"><input class="radio" type="radio" name="confirm" value="No" checked="checked" /> No </div><br /><br />';
echo '<input type="hidden" name="id" value="' . $_id . '" />';
echo '<input type="text" name="firstName" value="' . $_firstName . '" /><br />';
echo '<input type="text" name="lastName" value="' . $_lastName . '" /><br />';
echo '<input type="text" name="email" value="' . $_email . '" />';
echo '<input class="applyBtn" type="submit" value="UPDATE" name="submit" />';
}
echo '<p><< Back to the Admin Page</p>';
?>

Invalid argument supplied for foreach() - Yet output is showing

I am working to show editable fields based on query results. I know the query is functioning properly, and it is returning an array. The array is populating the form fields properly, however, I am getting the "Invalid argument supplied for foreach()" warning. I am new at this, and at a loss as to what is happening. I appreciate any suggestions.
Here is the code:
// Grab the profile data from the database
$query8 = "SELECT * FROM EDUCATION WHERE ID_NUM = '" . $_SESSION['IDNUM'] . "' ORDER BY RECORD";
$data = mysqli_query($dbc, $query8);
echo '<pre>' . print_r($data, true) . '</pre>';
$rowcount = 1;
while ($row = mysqli_fetch_assoc($data))
{
if (is_array($row))
{
echo '<p> It is an Array</p>';
}
foreach($row as &$item)
{
$record = $row['RECORD'];
$school = $row['SCHOOL'];
$type = $row['TYPE'];
$degree = $row['DEGREE'];
$major = $row['MAJOR'];
$grad = $row['GRAD'];
?>
<form enctype="multipart/form-data" method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>">
<fieldset>
<legend>Education History </legend>
<?php
echo '<input type="hidden" id="record" name="record" value="' . $record . '">';
echo 'Rowcount' . $rowcount. '</br>';
// Insert Listbox here
$queryschool = "SELECT * FROM SCHOOL";
$list = mysqli_query($dbc, $queryschool);
if($list)
{
echo 'School Type? ';
echo '<select name="school_code">';
while($row = mysqli_fetch_assoc($list))
{
echo "<option value={$row['CODE']}>{$row['TYPE']}" ;
echo '</option>';
}
echo '</select>';
}
echo '<br />';
echo '<label for="school">School Name:</label>';
echo '<input type="text" id="school" name="school" size="40" maxlength="40" value="' . ( (!empty($school)) ? $school : "") . '" /><br />';
// Insert Listbox here
$querydegree = "SELECT * FROM DEGREE";
$list = mysqli_query($dbc, $querydegree);
if($list)
{
echo 'Degree Type? ';
echo '<select name="degree_code">';
while($row = mysqli_fetch_assoc($list))
{
echo "<option value={$row['CODE']}>{$row['DEGREE']}";
echo '</option>';
}
echo '</select>';
}
echo '<br />';
echo '<label for="major">Field of study:</label>';
echo '<input type="text" id="major" name="major" size="40" maxlength="40" value="' . ( (!empty($major)) ? $major : "") . '" /><br />';
echo '<label for="grad">Did you graduate?:</label>';
echo '<input type="radio" id="grad" name="grad" value="Y" ' . ($grad == "Y" ? 'checked="checked"':'') . '/>Yes ';
echo '<input type="radio" id="grad" name="grad" value="N" ' . ($grad == "N" ? 'checked="checked"':'') . '/>No<br />';
?>
</fieldset>
<?php
$rowcount++;
}
}
;
echo '<label for="another">Do you need to enter more educational experience?:</label>';
echo '<input type="radio" id="another" name="another" value="Y" ' . ($another == "Y" ? 'checked="checked"':'') . '/>Yes ';
echo '<input type="radio" id="another" name="another" value="N" ' . ($another == "N" ? 'checked="checked"':'') . '/>No<br />';
?>
<input type="submit" value="Save Profile" name="submit" />
</form>
foreach ($row as &$item)
replace this with:
foreach ($row as $item)
And then for each variable you should probably change
$record = $row['RECORD'];
to
$record = $item['RECORD'];
foreach($row as &$item) should be
foreach($row as $item)
there is no need to use the foreach here you can just do this like like
while ($row = mysqli_fetch_assoc($data))
{
$record = $row['RECORD'];
$school = $row['SCHOOL'];
$type = $row['TYPE'];
$degree = $row['DEGREE'];
$major = $row['MAJOR'];
$grad = $row['GRAD'];
}
You're not changing the row item, so don't pass by reference to the foreach. Also, shouldn't you be using $item instead of $row? Do this:
foreach($row as $item)
{
$record = $item['RECORD'];
$school = $item['SCHOOL'];
....
Don't do This:
foreach($row as &$item)
{
$record = $row['RECORD'];
$school = $row['SCHOOL'];
....

Categories