PHP capture data and join together - php

Question

Okay so I need to parse two parts. Here is the code im trying to parse.
<input type="hidden" name="10528935" value="12-1-D33D19A3F048E845A9AA885220729B98" />
I would like it to parse and output like this once done.
10528935=12-1-D33D19A3F048E845A9AA885220729B98
Here is the site I'm trying to do this for
https://www.payqwiq.com/login?uid=582063bd-1973-42e4-8235-b28f5addf8bf
All I need is that data to be parsed and joined like above so I can continue with my program :)
Would appreciate some help if possible :)
I'm completely new in PHP.

Answer 1

Php is a back-end language. Since you are attempting to get data stored in a document object on the front-end, you should use a front-end language to parse the document object, then send the data to a php handler to do what you want with it on the back-end.
Using jQuery you can achieve the desired output with one line of code, then build an ajax call to send the output data to the desired php handler.
// when document is loaded
$(document).ready(function() {
// get data from document object to send to php handler
var combinedData = $('input').attr('name') + '=' + $('input').val();
// execute ajax method to send data to php handler
sendData(combinedData);
});
function sendData(data) {
// ajax method to send data to php handler
$.ajax({
url: 'pageToSendTo.php',
type: 'POST',
data: {
"data": JSON.stringify(data)
},
dataType: 'JSON',
success: function(data) {
console.log(data);
},
error: function(xhr) {
console.log('error: ' + xhr.responseText);
}
});
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="hidden" name="10528935" value="12-1-D33D19A3F048E845A9AA885220729B98" />
<!-- this is the "pageToSendTo.php" php handler. -->
<?php
if ($_POST['data']) {
//echo 'received data!';
$data = json_decode($_POST['data']);
// do stuff with data
print_r(json_encode($data));
}
?>