Here, there is a example string "XjYAKpR" .. how to create all new string possibility with that string ??
I've tried before
function containAllRots($s, $arr) {
$n = strlen($s);
$a = array();
for ($i = 0; $i < $n ; $i++) {
$rotated = rotate(str_split($s), $i);
$a[] = $rotated;
}
print_r($a);die();
if (array_diff($arr, $a)) {
return True;
}
else
{
return False;
}
}
I make 2 function rotate and generate
function rotate($l, $n) {
$b = $l[$n];
$sisa = array_values(array_diff($l, array($b)));
for ($i = 0; $i < count($sisa) ; $i++) {
$random[] = generate($sisa, $b);
}
print_r($random);die();
$hasil = $l[$n] . implode("",$random);
return $hasil;
}
function generate($sisa, $b) {
$string = implode("",$sisa);
$length = count($sisa);
$size = strlen($string);
$str = '';
for( $i = 0; $i < $length; $i++ ) {
$str .= $string[ rand( 0, $size - 1 ) ];
}
Here there is a pair of functions that lets you calculate a permutation set
(no repetitions are taken in account)
function extends_permutation($char, $perm) {
$result = [];
$times = count($perm);
for ($i=0; $i<$times; $i++) {
$temp = $perm;
array_splice($temp, $i, 0, $char);
array_push($result, $temp);
}
array_push($result, array_merge($perm, [$char]));
return $result;
}
function extends_set_of_permutations($char, $set) {
$step = [];
foreach ($set as $perm) {
$step = array_merge($step, extends_permutation($char, $perm));
}
return $step;
}
you can use them to generate the required set of permutations. Something like this:
$seed = "XjYAKpR";
// the first set of permutations contains only the
// possible permutation of a one char string (1)
$result_set = [[$seed[0]]];
$rest = str_split(substr($seed,1));
foreach($rest as $char) {
$result_set = extends_set_of_permutations($char, $result_set);
}
$result_set = array_map('implode', $result_set);
sort($result_set);
At the end of the execution you will have the 5040 permutations generated by your string in the result_set array (sorted in alphabetical order).
Add a char and you will have more than 40000 results.
The functions are quite naive in implementation and naming, both aspects can be improved.
Related
I have a string composed by many letters, at some point, one letter from a group can be used and this is represented by letters enclosed in []. I need to expand these letters into its actual strings.
From this:
$str = 'ABCCDF[GH]IJJ[KLM]'
To this:
$sub[0] = 'ABCCDFGIJJK';
$sub[1] = 'ABCCDFHIJJK';
$sub[2] = 'ABCCDFGIJJL';
$sub[3] = 'ABCCDFHIJJL';
$sub[4] = 'ABCCDFGIJJM';
$sub[5] = 'ABCCDFHIJJM';
UPDATE:
Thanks to #Barmar for the very valuable suggestions.
My final solution is:
$str = '[GH]DF[IK]TF[ADF]';
function parseString(string $str) : array
{
$i = 0;
$is_group = false;
$sub = array();
$chars = preg_split('//', $str, -1, PREG_SPLIT_NO_EMPTY);
foreach ($chars as $key => $value)
{
if(ctype_alpha($value))
{
if($is_group){
$sub[$i][] = $value;
} else {
if(!isset($sub[$i][0])){
$sub[$i][0] = $value;
} else {
$sub[$i][0] .= $value;
}
}
} else {
$is_group = !$is_group;
++$i;
}
}
return $sub;
}
The recommended function for combinations is (check the related post):
function array_cartesian_product($arrays)
{
$result = array();
$arrays = array_values($arrays);
$sizeIn = sizeof($arrays);
$size = $sizeIn > 0 ? 1 : 0;
foreach ($arrays as $array)
$size = $size * sizeof($array);
for ($i = 0; $i < $size; $i++) {
$result[$i] = array();
for ($j = 0; $j < $sizeIn; $j++)
array_push($result[$i], current($arrays[$j]));
for ($j = ($sizeIn - 1); $j >= 0; $j--) {
if (next($arrays[$j]))
break;
elseif (isset($arrays[$j]))
reset($arrays[$j]);
}
}
return $result;
}
Check the solution with:
$combinations = array_cartesian_product(parseString($str));
$sub = array_map('implode', $combinations);
var_dump($sub);
Convert your string into a 2-dimensional array. The parts outside brackets become single-element arrays, while each bracketed trings becomes an array of single characters. So your string would become:
$array =
array(array('ABCCDF'),
array('G', 'H', 'I'),
array('IJJ'),
array('K', 'L', 'M'));
Then you just need to compute all the combinations of those arrays; use one of the answers at How to generate in PHP all combinations of items in multiple arrays. Finally, you concatenate each of the resulting arrays with implode to get an array of strings.
$combinations = combinations($array);
$sub = array_map('implode', $combinations);
I have a array
$new_array=array('c','a','m','t','p');
Now I want to find the words combination which exists in the words table.
I have tried to achieve but not succeeded.
this is my php code .
$words = array();
$set = powerSet($new_array,2);
$mysql = new mysqli("localhost","root","","startup");
$sql = "SELECT wordid from words WHERE lemma = '%s'" ;
foreach ($set as $key => $value)
{
$word = implode("", $value);
$wordPermutation = permute($word);
foreach($wordPermutation as $keyWord)
{
if(!in_array($keyWord, $words))
{
if($result = $mysql->query(sprintf($sql,$keyWord)))
{
var_dump(sprintf($sql,$keyWord));
if($result->num_rows > 0)
{
$words[] = $keyWord;
}
}
}
}
}
print_r($words);
function powerSet($in, $minLength = 1, $max = 10) {
$count = count ( $in );
$members = pow ( 2, $count );
$return = array ();
for($i = 0; $i < $members; $i ++) {
$b = sprintf ( "%0" . $count . "b", $i );
$out = array ();
for($j = 0; $j < $count; $j ++) {
if ($b {$j} == '1')
$out [] = $in [$j];
}
if (count ( $out ) >= $minLength && count ( $out ) <= $max) {
$return [] = $out;
}
}
return $return;
}
function permute($str) {
if (strlen($str) < 2) {
return array($str);
}
$permutations = array();
$tail = substr($str, 1);
foreach (permute($tail) as $permutation) {
$length = strlen($permutation);
for ($i = 0; $i <= $length; $i++) {
$permutations[] = substr($permutation, 0, $i) . $str[0] . substr($permutation, $i);
}
}
return $permutations;
}
I want to find only those combination from the array which exists in the table .
My code is fetching all the combination
I might have mis-understood this but couldn't you use a single database query for this?
Such as:
SELECT wordid FROM `words` WHERE lemma LIKE ("%c%") OR lemma LIKE ("%a%") OR lemma LIKE ("%m%") OR lemma LIKE ("%t%") OR lemma LIKE ("%p%")
That way you'll get an array of wordids for any words containing any of the specified characters.
I'd add it as a comment but not enough rep yet.
already look around but cant find what i want for PHP.
just say i have a number : 1234 ( can be splitted first into array )
and i want to get how many number combination possible for 2 digits, 3 digits , and 4 digits
for example :
possible 4 digits will be :
1234,1243,1324,1342, and so on. ( i dont know how many more )
possible 2 digits will be :
12,13,14,21,23,24,31,32,34,41,42,43
the closest one i get is :
$p = permutate(array('1','2','3','4'));
$result = array();
foreach($p as $perm) {
$result[]=join("",$perm);
}
$result = array_unique($result);
print join("|", $result);
function permutate($elements, $perm = array(), &$permArray = array()){
if(empty($elements)){
array_push($permArray,$perm); return;
}
for($i=0;$i<=count($elements)-1;$i++){
array_push($perm,$elements[$i]);
$tmp = $elements; array_splice($tmp,$i,1);
permutate($tmp,$perm,$permArray);
array_pop($perm);
}
return $permArray;
}
but how can i edit this so i can display for 3 and 2 digits ?
Thanks
i got what i want
it's from #mudasobwa link. and i edit to what i want.
<?php
$in = array(1,2,3,4,5,6);
$te = power_perms($in);
// print_r($te);
$thou=0;
$hun =0;
$pu = 0;
for($i=0;$i<count($te);$i++)
{
$jm = count($te[$i]);
for($j=0;$j<$jm;$j++)
{
$hsl[$i] = $hsl[$i] . $te[$i][$j];
}
if($hsl[$i] >=100 && $hsl[$i] < 1000 )
{
$ratus[$hun] = intval($hsl[$i]);
$hun = $hun + 1;
}
if($hsl[$i] <100 && $hsl[$i] >=10)
{
$pul[$pu] = intval($hsl[$i]);
$pu = $pu + 1;
}
if($hsl[$i] >=1000 && $hsl[$i] < 10000)
{
$th[$thou] = intval($hsl[$i]);
$thou = $thou + 1;
}
}
$th=array_unique($th);
$pul = array_unique($pul);
$ratus = array_unique($ratus);
sort($ratus);
sort($pul);
sort($th);
print_r($th);
function power_perms($arr) {
$power_set = power_set($arr);
$result = array();
foreach($power_set as $set) {
$perms = perms($set);
$result = array_merge($result,$perms);
}
return $result;
}
function power_set($in,$minLength = 1) {
$count = count($in);
$members = pow(2,$count);
$return = array();
for ($i = 0; $i < $members; $i++) {
$b = sprintf("%0".$count."b",$i);
$out = array();
for ($j = 0; $j < $count; $j++) {
if ($b{$j} == '1') $out[] = $in[$j];
}
if (count($out) >= $minLength) {
$return[] = $out;
}
}
// usort($return,"cmp"); //can sort here by length
return $return;
}
function factorial($int){
if($int < 2) {
return 1;
}
for($f = 2; $int-1 > 1; $f *= $int--);
return $f;
}
function perm($arr, $nth = null) {
if ($nth === null) {
return perms($arr);
}
$result = array();
$length = count($arr);
while ($length--) {
$f = factorial($length);
$p = floor($nth / $f);
$result[] = $arr[$p];
array_delete_by_key($arr, $p);
$nth -= $p * $f;
}
$result = array_merge($result,$arr);
return $result;
}
function perms($arr) {
$p = array();
for ($i=0; $i < factorial(count($arr)); $i++) {
$p[] = perm($arr, $i);
}
return $p;
}
function array_delete_by_key(&$array, $delete_key, $use_old_keys = FALSE) {
unset($array[$delete_key]);
if(!$use_old_keys) {
$array = array_values($array);
}
return TRUE;
}
?>
I am trying to create function that allows me to get all combinations of an array to later generate a list.
But my problem is that currently my function treat "ab" as different from "ba". I dont know how to explain it in words but I guess the picture below exemplify what I try to achieve.
function everyCombination($array) {
$arrayCount = count($array);
$maxCombinations = pow($arrayCount, $arrayCount);
$returnArray = array();
$conversionArray = array();
foreach ($array as $key => $value) {
$conversionArray[base_convert($key, 10, $arrayCount)] = $value;
}
for ($i = 0; $i < $maxCombinations; $i++) {
$combination = base_convert($i, 10, $arrayCount);
$combination = str_pad($combination, $arrayCount, "0", STR_PAD_LEFT);
$returnArray[] = strtr($combination, $conversionArray);
}
return $returnArray;
}
$a = everyCombination(array('a', 'b', 'c','d'));
print_r($a);
The desired ouput would be
a
ab
abc
abcd
b
bc
bcd
c
cd
d
What you need to do is iterate through the array recursively, for each recursion you should only iterate through all the greater elements. Like so:
function everyCombination($arr) {
$combos = array();
$len = count($arr);
for( $i=0; $i<$len; $i++) {
for( $j=$i+1; $j<=$len; $j++) {
$combos[] = implode("",array_slice($arr,$i,$j-$i));
}
}
return $combos;
}
Example call:
everyCombination(['a','b','c','d']);
Returns:
['a','ab','abc','abcd','b','bc','bcd','c','cd','d']
It seems that you're after consecutive results, so a double loop would be a better choice here; recursion requires more control.
function combos($array)
{
if (!$array) {
return [];
}
$n = count($array);
$r = [];
for ($i = 0; $i < $n; ++$i) {
$prefix = '';
for ($j = $i; $j < $n; ++$j) {
$r[] = $prefix . $array[$j];
$prefix .= $array[$j];
}
}
return $r;
}
print_r(combos([1, 2, 3, 4]));
I have tried to write a basic merge sort in PHP involving a small array, yet the problem is it takes about a minute or so to execute, and returns:
Fatal error: Allowed memory size of 536870912 bytes exhausted (tried
to allocate 35 bytes) in /Users/web/www/merge.php on line 39
Does anyone have an idea where the code might be going wrong (if at all)? I've been staring at this for a good hour now.
<?php
$array = array(8,1,2,5,6,7);
print_array($array);
merge_sort($array);
print_array($array);
function merge_sort(&$list){
if( count($list) <= 1 ){
return $list;
}
$left = array();
$right = array();
$middle = (int) ( count($list)/2 );
// Make left
for( $i=0; $i < $middle; $i++ ){
$left[] = $list[$i];
}
// Make right
for( $i = $middle; $i < count($list); $i++ ){
$right[] = $list[$i];
}
// Merge sort left & right
merge_sort($left);
merge_sort($right);
// Merge left & right
return merge($left, $right);
}
function merge(&$left, &$right){
$result = array();
while(count($left) > 0 || count(right) > 0){
if(count($left) > 0 && count(right) > 0){
if($left[0] <= $right[0]){
$result[] = array_shift($left);
} else {
$result[] = array_shift($right);
}
} elseif (count($left) > 0){
$result[] = array_shift($left);
} elseif (count($right) > 0){
$result[] = array_shift($right);
}
}
print_array($result);exit;
return $result;
}
function print_array($array){
echo "<pre>";
print_r($array);
echo "<br/>";
echo "</pre>";
}
?>
In your merge function, you call count on right instead of $right. PHP assumes this is a string constant (at least in 5.3.9) and when casted into an array that always has one element. So count(right) is always one, and you never exit the first merge.
Try this approach. Instead of shifting it, slice.
Also, for in while loop for the merge function, you need to do an and && comparison instead
of ||
function mergeSort($array)
{
if(count($array) == 1 )
{
return $array;
}
$mid = count($array) / 2;
$left = array_slice($array, 0, $mid);
$right = array_slice($array, $mid);
$left = mergeSort($left);
$right = mergeSort($right);
return merge($left, $right);
}
function merge($left, $right)
{
$res = array();
while (count($left) > 0 && count($right) > 0)
{
if($left[0] > $right[0])
{
$res[] = $right[0];
$right = array_slice($right , 1);
}
else
{
$res[] = $left[0];
$left = array_slice($left, 1);
}
}
while (count($left) > 0)
{
$res[] = $left[0];
$left = array_slice($left, 1);
}
while (count($right) > 0)
{
$res[] = $right[0];
$right = array_slice($right, 1);
}
return $res;
}
Have a look at this, the algorithm is already implemented, using array_push and array splice instead of just array_shift.
http://www.codecodex.com/wiki/Merge_sort#PHP
I implement merge sort this way
function mergeSort($Array)
{
$len = count($Array);
if($len==1){
return $Array;
}
$mid = (int)$len / 2;
$left = mergeSort(array_slice($Array, 0, $mid));
$right = mergeSort(array_slice($Array, $mid));
return merge($left, $right);
}
function merge($left, $right)
{
$combined = [];
$totalLeft = count($left);
$totalRight = count($right);
$rightIndex = $leftIndex=0;
while ($leftIndex < $totalLeft && $rightIndex < $totalRight) {
if ($left[$leftIndex] > $right[$rightIndex]) {
$combined[]=$right[$rightIndex];
$rightIndex++;
}else {
$combined[] =$left[$leftIndex];
$leftIndex++;
}
}
while($leftIndex<$totalLeft){
$combined[]=$left[$leftIndex];
$leftIndex++;
}
while ($rightIndex<$totalRight){
$combined[] =$right[$rightIndex];
$rightIndex++;
}
return $combined;
}
Here is the class in PHP to implement the Merge Sort -
<?php
class mergeSort{
public $arr;
public function __construct($arr){
$this->arr = $arr;
}
public function mSort($l,$r){
if($l===null || $r===null){
return false;
}
if ($l < $r)
{
// Same as ($l+$r)/2, but avoids overflow for large $l and $r
$m = $l+floor(($r-$l)/2);
// Sort first and second halves
$this->mSort($l, $m);
$this->mSort($m+1, $r);
$this->merge($l, $m, $r);
}
}
// Merges two subarrays of $this->arr[]. First subarray is $this->arr[$l..$m]. Second subarray is $this->arr[$m+1..$r]
public function merge($l, $m, $r)
{
if($l===null || $m===null || $r===null){
return false;
}
$n1 = $m - $l + 1;
$n2 = $r - $m;
/* create temp arrays */
$L=array();
$R=array();
/* Copy data to temp arrays $L[] and $R[] */
for ($i = 0; $i < $n1; $i++)
$L[$i] = $this->arr[$l + $i];
for ($j = 0; $j < $n2; $j++)
$R[$j] = $this->arr[$m + 1+ $j];
/* Merge the temp arrays back into $this->arr[$l..$r]*/
$i = 0; // Initial index of first subarray
$j = 0; // Initial index of second subarray
$k = $l; // Initial index of merged subarray
while ($i < $n1 && $j < $n2)
{
if($L[$i] <= $R[$j])
{
$this->arr[$k] = $L[$i];
$i++;
}
else
{
$this->arr[$k] = $R[$j];
$j++;
}
$k++;
}
/* Copy the remaining elements of $L[], if there are any */
while($i < $n1)
{
$this->arr[$k] = $L[$i];
$i++;
$k++;
}
/* Copy the remaining elements of $R[], if there are any */
while($j < $n2)
{
$this->arr[$k] = $R[$j];
$j++;
$k++;
}
}
}
$arr = array(38, 27, 43, 5, 9, 91, 12);
$obj = new mergeSort($arr);
$obj->mSort(0,6);
print_r($obj->arr);
?>
I was looking for a optimized Mergesort algorithm in PHP. There are 5 algorithms in the answers, so I tested those, and mine too. Using PHP 7.2.7, these are the times:
Sorting 1000 random numbers:
Avanche 1 0.0396 seconds
Avanche 2 0.0347 seconds
Kartik 0.0291 seconds
Kripa 0.0282 seconds
Samuel 0.0247 seconds
Mine 0.0144 seconds
Sorting 10 random numbers:
Avanche 1 0.000222 seconds
Kartik 0.000216 seconds
Kripa 0.000159 seconds
Avanche 2 0.000144 seconds
Samuel 0.000128 seconds
Mine 0.000098 seconds
So, although I encourage to whom read it to make it faster (that was I was looking for, and I believe it can be done), I let you my implementation too, cause seems to be faster than the other answers:
//This function needs start and end limits
function mergeSortRec(&$a,$start,$end){
if($start<$end){
$center=($start+$end)>>1; //Binary right shift is like divide by 2
mergeSortRec($a, $start, $center);
mergeSortRec($a, $center+1, $end);
//Mixing the 2 halfs
$aux=array();
$left=$start; $right=$center;
//Main loop
while($left<$center && $right<=$end){
if($a[$left]<$a[$right]){
$aux[]=$a[$left++];
}else{
$aux[]=$a[$right++];
}
}
//Copy the rest of the first half
while($left<$center) $aux[]=$a[$left++];
//Copy the rest of the second half
while($right<=$end) $aux[]=$a[$right++];
//Copy the aux array to the main array
foreach($aux as $v) $a[$start++]=$v;
}
}
//This is the function easier to call
function mergeSort(&$a) {
mergeSortRec($a,0,count($a)-1);
}
If you post a new answer, let me a comment to test it and add it.
Edit: I did some new optimizations, for those looking for a better implementation.
Your merge sort accepts a list by reference
function merge_sort(&$list)
So you need to assign it the new merged and sorted list. So instead of
return merge($left, $right);
do
$list = $this->merge($left, $right);
That should do it, just remove the exit and fix the count variable
MergeSort in PHP
<?php
class Solution
{
function mergeSort(&$arr)
{
if(count($arr) > 1) {
$mid = floor(count($arr)/2);
$left = array_slice($arr, 0, $mid);
$right = array_slice($arr, $mid);
$this->mergeSort($left);
$this->mergeSort($right);
// Merge the results.
$i = $j = $k = 0;
while(($i < count($left)) && ($j < count($right))) {
if($left[$i] < $right[$j]) {
$arr[$k] = $left[$i];
$i++;
} else {
$arr[$k] = $right[$j];
$j++;
}
$k++;
}
while($i < count($left)) {
$arr[$k] = $left[$i];
$i++;
$k++;
}
while($j < count($right)) {
$arr[$k] = $right[$j];
$j++;
$k++;
}
}
}
}
$s = new Solution();
$tmp = [12, 7, 11, 13, 5, 6, 7];
$s->mergeSort($tmp);
print_r($tmp);