how to fix pagination continuous number of page IN PHP - php

Here is my index.php code
My problem is my pagination has a continuous number of
pages.
<?php
$limit = 10;
$offset = (isset($_GET["page"]) ? $_GET["page"] - 1 : 0) * $limit;
$query = "SELECT * FROM employee ORDER BY employee_datecommenced ASC LIMIT
$offset,$limit ";
$list = getdata_inner_join($query);
?>
<?php
$total = $dbcon->query("SELECT count(*) FROM employee") or
die(mysqli_error());
$fetch = $total->fetch_assoc();
for($x = 0; $x < $fetch["count(*)"] / $limit ; $x ++){
$page = $x + 1;
if((isset($_GET["page"]) ? $_GET["page"] : 1) == $page)
$page = "<b>".$page."</b>";
echo ''.$page.' ';
}
?>
Click here to see the output photo
Thanks in advance

You say "My problem is my pagination has a continuous number of pages", but why is that a problem? What do you need to change?

in your for loop while printing the anchor tags, check the current page, if suppose the page is ($current), disable ($current-1), and print $current to ($current+5) and '....' and (current+1), if current is $min or $max manage the prev and next

Related

All Pagination numbers are displaying using PHP and Mysql

I am fetching username and Id from the database. I have more than 500 usernames. I have to display pagination number only 1 to 5 and last pagination number.
Example:- pagination number is:- 1 2 3 4 5...20(last number).
Now I am getting all numbers in horizontal. Would you help me in this?
Can anyone help me with NEXT and LAST in pagination?
include('../db/connection.php');
$reclimit = 3;
if(isset($_GET['page'])){
$page = $_GET['page'];
} else {
$page = 1;
}
$start = (($page-1) * $reclimit);
$sql = "SELECT * FROM request";
$records =$conn->query($sql);;
$total = $records->num_rows;
$tpages = ceil($total / $reclimit);
$search_sql="SELECT * FROM request LIMIT ".$start."," .$reclimit;
$search_result = $conn->query($search_sql);
HTML
<body>
<?php
if (isset($search_result->num_rows) > 0) {
?>
<h2 class="result-title">Results matching your need</h2>
<?php
while($search_ok = $search_result->fetch_assoc()) {
$user_id=$search_ok['Id'];
$user_name=$search_ok['Name'];
echo "
<div class='search-section'>
<div class='search-profile'>
<div class='s_user_id'>{$user_id}</div>
<div class='s_user_name'>{$user_name}</div>
</div>
</div>
";
}}
for($i=1;$i<=$tpages;$i++) {
echo "".$i."";
}
?>
</body>
The pagination which you are using is simple and working one. But the pagination which you are searching is smart way and you should achieve this by using some if conditions. Similar answer are there in SO. Go to the following, this may help you
Smart pagination algorithm
PHP pagination
Limit pagination page number
It's a simple idea, but I didn't test it. Edit foreach displaying numbers:
$pgStart = 1;
if (isset($_GET['page'])) { // get first showing number = current page - 2
$pg = $_GET['page'] - 2;
$pgStart = $pg + 5 > $tpages ? $tpages - 4 : $pg; //EDIT fix when reach pages end
$pgStart = $pg < 1 ? 1 : $pg; // This must be after ending correction (previous line)
}
if ($pgStart > 1) { // show 1
echo '1 ... ';
}
for($i = $pgStart; $i <= $tpages && $i < $pgStart + 5; $i++) { // show 5 pages
echo ' '.$i.' ';
}
if ($i < $tpages) { // show last
echo ' ... '.$tpages.'';
}
EDIT
Output of this script with $_GET['page'] = 7 and $tpages = 20 from php sandbox is (without linebreaks):
1 ...
5
6
7
8
9
... 20

how to Limit pagination pages links?

I have my pagination page links like this.And the pagegrows like:
1 2 3 4 5 6 7 ,8,9,10 and goes on.
But i want to limit this so if there is more than 5 pages it shall only show 5 links like this:
1 2 3 4 5... 97 98 99
where 99 is the last page.
And if you go to next page it will only change the first pages like this:
3 4 5 ... 97 98 99
function pagination($current_page_number, $total_records_found, $query_string = null)
{
$page = 1;
echo "Page: ";
for ($total_pages = ($total_records_found/NUMBER_PER_PAGE); $total_pages > 0; $total_pages--)
{
if ($page != $current_page_number)
echo "<a href=\"?page=$page" . (($query_string) ? "&$query_string" : "") . "\">";
echo "$page ";
require_once('inc/database.php');
define("NUMBER_PER_PAGE", 5); //number of records per page of the search results
$page = ($_GET['page']) ? $_GET['page'] : 1;
$start = ($page-1) * NUMBER_PER_PAGE;
$sql = "SELECT * FROM members WHERE 1=1";
$total_records = mysql_num_rows(mysql_query($sql));
//we limit our query to the number of results we want per page
$sql .= " LIMIT $start, " . NUMBER_PER_PAGE;
// we display our pagination at the top of our search results
pagination($page, $total_records, "id=$id&username=$username&email=$email");
$loop = mysql_query($sql)
or die ('cannot run the query because: ' . mysql_error());
while ($record = mysql_fetch_assoc($loop))
echo "<br/>{$record['id']}) " . stripslashes($record['username']) . " - {$record['email']}";
echo "<center>" . number_format($total_records) . " search results found</center>";
if ($page != $current_page_number)
echo "</a>";
$page++;
Pagination is one of those things that has been done so many times that you're better off figuring out how to use a pre made class like this one http://code.tutsplus.com/tutorials/how-to-paginate-data-with-php--net-2928
The basics of what you need to do are calculate how many links you want to see on either side of the elipses ... and then make loops to create those links. The ceil() function may be new for you, but it returns a fraction always rounded up.
$buffer = 3;
$results_per_page = 5;
$page = ($_GET['page']) ? $_GET['page'] : 1;
$start = ($page-1) * $results_per_page;
$sql = "SELECT * FROM members WHERE 1=1";
$total_records = mysql_num_rows(mysql_query($sql));
$total_pages = ceil(intval($total_records) / $results_per_page);
for ($x = $page - $buffer; $x < $page; $x++){
echo " $x";
}
echo " ... ";
for ($x = $total_pages - $buffer; $x <= $total_pages; $x++){
echo " $x";
}
This quick little bit of code does not take in to consideration result sets small enough to fit all links in to one line. Which is why I suggest using the pagination classes that exist already.

PHP Pagination - having trouble detecting pages

I want to make a minimalistic pagination script that basically does three things:
On first page, just a next button.
On last page, just a previous button.
For all others in between, both.
I have most of the code worked out, but I'm just making some if/elseif statements that determine which page the user is on and I'm having a bit of trouble. (those at bottom) First, here's the query code:
$per_page = 10;
$pages_query = mysql_query("SELECT COUNT(idnum) FROM images");
$pages = ceil(mysql_result($pages_query, 0) / $per_page);
$page = (isset($_GET['page'])) ? (int)$_GET['page'] :1;
$start = ($page -1) * $per_page;
$query = mysql_query("SELECT * FROM images ORDER BY idnum DESC LIMIT $start, $per_page");
And here's the if statement part:
$nextend = $pages - 1;
$next = $page + 1;
$previous = $page - 1;
if ($pages >= 1 && $page = 1) {
echo 'next';
} elseif ($pages >= 1 && $page = 2) {
echo 'previous';
}
It always results in the next button, no matter what page I'm on. How do I detect the page number so I can display the pagination buttons the way I want to? By the way, I know I don't have the else statement for the middle pages (next and previous) yet.
You are assigning in your if statements rather than comparing. You don't want this in your if statement:
$page = 1
That just assigns 1 to $page.
You want this:
$page == 1
Or this:
$page === 1
$nextend = $pages - 1;
$next = $page + 1;
$previous = $page - 1;
$maxpages = ? //You need to have a variable with the last page number
if ($pages > 1) {
echo 'previous';
}
if ($page < $maxpages) {
echo 'next';
}
I don't understand what logic you are trying to do with your if/else statements, also when checking if a variable is equal to a number/other variable your "==" not "="
What you've got to do is way simple:
If you're not on the first page, you always have to show a back button.
If you're not on the last page you always have to show a next button.
Please note that both those conditions can happen at the same time so using an elseif between them won't work as it will only allow one of them to execute.
Example:
if ( $page > 1 )
{
echo( "Previous" );
}
if ( $page < $pages )
{
echo( "Next" );
}

pagination fixing php mysql

this pagination only for next and previous wallpaper/ query , but its show also empty rows,
how to fix it?
<?php
// Figure out the limit for the query based
// on the current page number.
$from = (($walpaperid * $max_results) - $max_results);
// Figure out the total number of results in DB:
$total_results = mysql_result(mysql_query("SELECT COUNT( * ) AS `Rows` , `wallpaperid`
FROM `wallpaper` ORDER BY `wallpaper`.`wallpaperid` ASC"),0) or die(mysql_error());
// Figure out the total number of pages. Always round up using ceil()
$total_pages = ceil($from / $max_results);
// Build Page Number Hyperlinks
// Build Previous Link
if($wallpaperid > 1){
$prev = ($wallpaperid - 1);
echo "<Previous Page ";
}
for($i = 1; $i <= $total_pages; $i++){
if(($pagenum) == $i){
echo "<strong>$i</strong> ";
} else {
echo "<a class = 'mlnk' href=\"$siteurl3/$cat_url-$catid-$i.php\">$i</a> |";
}
}
// Build Next Link
if($wallpaperid < $total_pages){
$next = ($wallpaperid + 1);
echo "Next Page>";
}
?>
Correct your code to figure out the number of pages:
$total_pages = ceil($total_results / $max_results);

pagination incrementing problem

I have the following code, which is the basis for pagination in a larger application. However, it does not work, as although I should be obtaining the value of pg from the url, pg never goes higher than 2. For some reason, next = pg+1; seems to always see pg as 1, regardless of what is passed on the url. It is a similar problem with last. I assume I am overriding the value obtained from GET, but I am unsure where.
The problem seems to be in how I am working out $max and the limit, as instead of 0, 10, -10, 10 gets passed. Also the ifcode before $max does not seem to succeed in stopping pg from being 0.
<?php
if (isset($_GET["pg"])) {
$pg = $_GET["pg"];
} else $pg = 1;
$con = mysql_connect("localhost","","");
if(!$con) {
die('Connection failed because of' .mysql_error());
}
mysql_select_db("ebay",$con);
if ($pg < 1) {
$pg = 1;
} elseif ($pg > $last) {
$pg = $last;
}
$table = 'AUCTIONS';
$page_rows = 10;
$max = ' limit ' .($pg - 1) * $page_rows .', ' .$page_rows;
$rows = getRowsByArticleSearch($query, $table, $max);
$rowcount = count($rows);
echo $rowcount;
$last = ceil($rowcount/$page_rows);
$page_rows = 10;
$rowcount = 2;
// Would normally obtain the number of rows returned, but database stuff is snipped for brevity
$last = ceil($rowcount/$page_rows);
if ($pg < 1) {
$pg = 1;
} elseif ($pg > $last) {
$pg = $last;
}
$self = htmlspecialchars($_SERVER['PHP_SELF'],ENT_QUOTES,'utf-8');
echo " <a href='$self?pg=1'> <<-First</a> ";
$previous = $pg-1;
echo " <a href='$self?pg=$previous'> <-Previous</a> ";
echo "---------------------------";
$next = $pg+1;
echo " <a href='$self?pg=$next'>Next -></a> ";
echo " <a href='$self?pg=$last'>Last ->></a> ";
The code is correct, however, the data is wrong.
When you have
$page_rows = 10;
$rowcount = 2;
it actually means, that you have 2 rows displayed on pages which will display 10 rows each. This makes it 1 page in total.
Change it to
$page_rows = 10;
$rowcount = 200;
and voila, you will get your pagination.
Here's your problem:
$last = ceil($rowcount/$page_rows);
That's setting $last to be 1, and then you have:
if ($pg > $last) {
$pg = $last;
}
Edit: I wonder if you meant this, instead:
$last = ceil($page_rows/$rowcount);
Edit again: as per Cassy's answer, you probably really just need to set the right values for these variables:
$page_rows = 10;
$rowcount = 2;
based on the now revised question:
$rowcount = count($rows);
will naturally always return 10, as you're limiting the result
... LIMIT 10;
But this might help:
SQL CALC FOUND ROWS
Example:
mysql> SELECT SQL_CALC_FOUND_ROWS * FROM tbl_name
-> WHERE id > 100 LIMIT 10;
mysql> SELECT FOUND_ROWS();
The first query will still return your articles, while the second will return the number of rows the previous select would have had if not using the LIMIT clause.
Hope that helps.

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