When I want to input some Chinese character into my form,
<html>
<title>
Form
</title>
<head>
<meta http-equiv="Content-type" content="text/html; charset=utf-8"/>
</head>
<body>
<div id="wrapper">
<form action="form.php" method="post" accept-charset="UTF-8" >
<p>Input: <input type="text" name="input1" /></p>
<input type="submit" value="Submit" />
</form>
</div>
</body>
</html>`
and the form.php:
<?php
header('Content-Type: text/html; charset=utf-8');
define('DB_NAME','form1');
define('DB_USER','root');
define('DB_PASSWORD','');
define('DB_HOST','localhost');
$link= mysql_connect(DB_HOST,DB_USER,DB_PASSWORD);
if (!$link){
die('could not connect server'.mysql_error());
}
$db_selected = mysql_select_db(DB_NAME,$link);
if(!$db_selected){
die('Cannot connect'.DB_NAME.': '.mysql_error());
}
$value=$_POST['input1'];
$sql="INSERT INTO form (input1) VALUES ('$value')";
if (!mysql_query($sql)){
die('Error: '.mysql_error());
}
mysql_close();
header("Location: form.htm");
?>
Mysql sheet output something strange like 早਽
Why?
Should I do something on the code or on Mysql?
Please help!!!!
Thanks!!!!!!
Did you try to use this line after your database connection ?
mysql_query("SET NAMES utf8");
You can try this.
mysql_set_charset('utf8', $link);
Like this...
<?php
header('Content-Type: text/html; charset=utf-8');
define('DB_NAME','form1');
define('DB_USER','root');
define('DB_PASSWORD','');
define('DB_HOST','localhost');
$link= mysql_connect(DB_HOST,DB_USER,DB_PASSWORD);
mysql_set_charset('utf8', $link);
if (!$link){
die('could not connect server'.mysql_error());
}
...
...
Related
I have this error when i try to submit to my demo database:
Can't use demo: Unknown database 'demo' How do i get the server going?
Basic form:
<form action="demo.php" method="post" />
<p>Input 1: <input type="text" name="input1" /></p>
<p>Input 2: <input type="text" name="input2" /></p>
<input type="submit" value="Submit" />
</form>
Server communication setup:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<title>Untitled Document</title>
</head>
<body>
<?php
define('DB_NAME', 'demo');
define('DB_USER', 'root');
define('DB_PASSWORD', 'root');
define('DB_HOST', 'localhost');
$link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD);
if (!$link) {
die('Could not connect: ' . mysql_error());
}
$db_selected = mysql_select_db(DB_NAME, $link);
if (!$db_selected) {
die('Can\'t use ' . DB_NAME . ': ' . mysql_error());
}
$value = $_POST['input1'];
$value2 = $_POST['input2'];
$sql = "INSERT INTO demo (input1, input2) VALUES ('$value', '$value2')";
if (!mysql_query($sql)) {
die('Error: ' . mysql_error());
}
mysql_close();
?>
</body>
</html>
All my code should work and is from this tutorial: Tutorial video link
Here is download link to the original php files i have used:
Original from tutorial: Basic php form
Orignial from tutorial: Communication with server php-file
Your database is called "forms1" not "demo".. table is called "forms1".
Change define('DB_NAME', 'demo'); to define('DB_NAME', 'forms1');
Your database name is forms1 not demo. demo is your table name
Try this code
define('DB_NAME', 'forms1');//Your database name is forms1 not demo
define('DB_USER', 'root');
define('DB_PASSWORD', 'root');
define('DB_HOST', 'localhost');
$link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD);
if (!$link) {
die('Could not connect: ' . mysql_error());
}
$db_selected = mysql_select_db(DB_NAME, $link);
if (!$db_selected) {
die('Can\'t use ' . DB_NAME . ': ' . mysql_error());
}
Change this code because in your table column input2 not available
$sql = "INSERT INTO demo (input1) VALUES ('$value')";
You need to define your Database on mysql_connect
$link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD, DB_NAME);
I'm starting to study php and mysql, I start with this simple module that include:
Create a Database connection; (run)
Connect to DataBase; (not give output message, probably not work)
Insert data; (not work)
Question:
Why it is not working correctly?
I create this simple PHP page (filename: inizio.php):
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta content="it" http-equiv="Content-Language" />
<meta content="text/html; charset=utf-8" http-equiv="Content-Type" />
<title>Pagina di inizio</title>
</head>
<body style="width: 672px; height: 289px">
<p class="auto-style1" style="width: 293px; height: 24px">Titolo centrato della pagina</p>
<form method="post" action="inserimento.php" style="width: 674px; height: 130px">
Inserisci il nome:<input name="nome" type="text" /><br />
Inserisci il cognome:<input name="cognome" type="text" /> <br />
<br />
<input name="Submit1" type="submit" value="Invia" /><br />
</form>
</body>
</html>
After I create this php script (filename inserimento.php):
<?php
$host='localhost';
$user='root';
$password='root';
$database='test_youtube';
// 1. Create a database connection
$connection = mysqli_connect($host,$user,$password);
if (!$connection)
{
die("Database connection failed: " . mysqli_error());
}
else
{
die("...Connesso con successo al Server!");
}
// 2. Select a database to use
$db_select = mysqli_select_db($connection, $database);
if (!$db_select)
{
die("Database selection failed: " . mysqli_error());
}
else
{
die("...Connesso con successo al Database!");
}
$query="insert into users(firstname, lastname)VALUES('".$_REQUEST['nome']."','".$request['cognome']."')";
if (!mysqli_query($query,$db_select))
{print("errore inserimento dati");
}
?>
Try die() like following in your php file:
$connection = mysqli_connect($host,$user,$password,$database);
/* check connection */
if (mysqli_connect_errno()) {
die("Connect failed: ", mysqli_connect_error());
}
$query="insert into users(firstname, lastname)VALUES('".$_REQUEST['nome']."','".$_REQUEST['cognome']."')";
if ($result = mysqli_query($connection ,$query))
{
print("Success!");
}
$con=mysqli_connect("localhost","root","root","test_youtube");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
// Perform queries
mysqli_query($con,"INSERT INTO data_entry_users (user_name,user_password) VALUES ('".$_REQUEST['nome']."','".$_REQUEST['cognome']."')");
mysqli_close($con);
I am new working on a project that has me connecting a database and a webpage and before doing the official database, I wanted to test a basic database.
I test to make sure everything is working by using phpMyAdmin. I can tell that I formed SOME kind of connection between my html and php, but that's where the issue is. whenever I press the submit button on my site, instead of getting a message telling me that everything works, I instead get a white page with all of my php code. I have tried making sure all my syntax is correct and all the variables are labeled correctly, but nothing is going through.
<!DOCTYPE php>
<?php
define('DB_NAME', 'training');
define('DB_USER', 'root');
define('DB_PASSWORD', '********');
define('DB_HOST', 'localhost');
$link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD);
if(!link){
die('Could not connect: ' .mysql_error);
}
$db_selected = mysql_select_db(DB_NAME, $link);
if (!db_selected){
die('Error: ' .mysql_error());
}
$Name = $_POST=['name'];
$Job = $_POST['job'];
$sql = "INSERT INTO employee (name,job) VALUES ('$Name', '$Job')";
if (!mysql_query($sql)){
die('Error: ' .mysql_error());
}
echo 'Success!';
mysql_close();
?>
<!DOCTYPE html>
<html>
<h1 style="text-align:center">Undergrad Sign-up</h1>
<style>
#body {background-color:#001b38;}
</style>
<body id="body" style="color:white;text-align:center" >
<form action="DBconnect.php" method="post" />
Name<br>
<input type="text" name="name" maxlength=20 required/>
<br>
Job<br>
<input type="text" name="job" maxlength=20 required/>
<br>
<button type="submit" value="submit">Submit</button>
</form>
</body>
</html>
I've been trying to learn PHP and have been given a simple task to help me.
I'm trying to get a user to complete a form which has their email address in it, then save it to a database.
Here's my code so far:
<html>
<body>
<form action="postemail.php" method="post"> Email Address: <input type="text" name="emailaddress" /> <input type="submit" />
</form>
</body>
</html>
<?php
$connection = mysql_connect("localhost","edwardHost","password");
if (!$connection) {
die('Could not connect: ' . mysql_error());
}
mysql_select_db("my_database", $connection);
$sql="INSERT INTO Subscribers (EmailAddress) VALUES ('$_POST[emailaddress]')";
if (!mysql_query($sql,$connection)) {
die('Error: ' . mysql_error());
}
mysql_close($connection);
?>
Thanks in advance!
Change your query to this
One more thing i forget last time you are missing single quete around $_POST[emailaddress]. In your query
$sql="INSERT INTO Subscribers (EmailAddress) VALUES ('".$_POST['emailaddress']."')";
Dont use mysl function as the are deprciated
Learn mysqli_ function or PDO Or both
Check this link for mysql identifier http://dev.mysql.com/doc/refman/5.0/en/identifier-qualifiers.html
Try this example using PDO in your postemail.php
define('DB_TYPE', 'mysql');
define('DB_HOST', '127.0.0.1');
define('DB_NAME', 'dbname');
define('DB_USER', 'root');
define('DB_PASS', 'password');
try {
// create a new instance of a PDO connection
$db = new PDO(DB_TYPE.':host='.DB_HOST.';dbname='.DB_NAME, DB_USER, DB_PASS);
$db->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
}
catch(PDOException $e) {
// if the connection fails, display an error message
echo 'ERROR: ' . $e->getMessage();
}
if(isset($_POST['emailaddress']) && !empty($_POST['emailaddress'])) {
$emailaddress = $_POST['emailaddress'];
$sql = 'INSERT INTO Subscribers (EmailAddress) VALUES (:emailaddress )';
$stmt = $db->prepare($sql);
$stmt->bindValue('emailaddress ', $emailaddress);
$stmt->execute();
}
After you have totaly filled in the form, it first needs to check if the submit button is clicked, then it has to send it to a database.
You also need to give you submit button a name=""
HTML code:
<html>
<body>
<form action="postemail.php" method="post">
Email Address: <input type="text" name="emailaddress" />
<input type="submit" name="submit" value="add to database" />
</form>
</body>
</html>
PHP code:
<?php
if(isset($_POST['submit'])){
$connection = mysqli_connect("localhost","edwardHost","password","my_database");
if (!$connection) {
die('Could not connect: ' . mysql_error());
}
$email = $_POST['emailaddress'];
$sql = "INSERT INTO Subscribers (EmailAddress) VALUES ('$email')";
if (!mysqli_query($connection,$sql)) {
die('Error: ' . mysql_error());
}
mysql_close($connection);
}
?>
<html> <body>
<form action="postemail.php" method="post">
Email Address: <input type="text" name="emailaddress" />
<input type="submit" />
</form>
</body> </html>
<?php $connection = mysql_connect("localhost","username","password");
if (!$connection) { die('Could not connect: ' . mysql_error());
}
mysql_select_db("my_database", $connection);
$sql="INSERT INTO Subscribers (EmailAddress) VALUES ('$_POST[emailaddress]')";
if (!mysql_query($sql,$connection)) { die('Error: ' . mysql_error()); }
mysql_close($connection);
?>
I have a HTML form handled by php. The form has various text input fields and one of those asks the user to input a link containing http://.
The problem is when I submit a link like http://www.google.com/ the form fails badly by displaying random content from different php files on my website.
Here's a resume of my code:
<form action="add.php" method="post">
<input type="text" name="link" />
<input type="submit" value="submit" />
<?php
if (isset($_POST['link']))
{
$link = mysql_escape_string($_POST['link']);
mysql_query("INSERT INTO mytable(link) values($link)");
}
?>
Works just fine when not submitting a string that contains http://. Anyone has any idea why this happens?
Sidenote: You will find an mysqli_* based version further down.
Assuming you are connected to your DB, you did not wrap $link in VALUES with quotes.
Change this line:
mysql_query("INSERT INTO mytable(link) values( $link )");
^ ^ <- missing quotes
to:
mysql_query("INSERT INTO mytable(link) values('$link')");
Tested and working with this example: (form is set to self) and using http://www.google.com/ as an input and a few others containing http://
<?php
define('DB_NAME', 'xxx');
define('DB_USER', 'xxx');
define('DB_PASS', 'xxx');
define('DB_HOST', 'xxx');
$dbh = mysql_connect(DB_HOST, DB_USER, DB_PASS);
if(!$dbh)
{
die('Could not connect to database: ' . mysql_error());
}
$db_select = mysql_select_db(DB_NAME);
if(!$db_select)
{
die('Can\'t use ' . DB_NAME . ': ' . mysql_error());
}
if(isset($_POST['submit']) && !empty($_POST['link'])){
$link = mysql_real_escape_string($_POST['link']);
mysql_query("INSERT INTO mytable (link) values('$link')");
if(!mysql_query)
{
die("sorry");
}
else{ echo "Success"; }
mysql_close();
}
?>
<!DOCTYPE html>
<html>
<body>
<title></title>
<h3>Place your Link Below:</h3>
<form action="" method="post">
<input type="text" name="link" />
<input type="submit" name="submit" value="submit" />
</body>
</html>
Footnotes:
Do consider switching to mysqli_* functions with prepared statements or PDO. The mysql_* functions are deprecated and will be removed from future releases.
Here is an mysqli_* based version:
<?php
define('DB_NAME', 'xxx');
define('DB_USER', 'xxx');
define('DB_PASS', 'xxx');
define('DB_HOST', 'xxx');
$dbh = mysqli_connect(DB_HOST, DB_USER, DB_PASS);
if(!$dbh)
{
die('Could not connect to database: ' . mysqli_error());
}
$db_select = mysqli_select_db($dbh,DB_NAME);
if(!$db_select)
{
die('Can\'t use ' . DB_NAME . ': ' . mysqli_error());
}
if(isset($_POST['submit']) && !empty($_POST['link'])){
$link = mysqli_real_escape_string($dbh,$_POST['link']);
mysqli_query($dbh,"INSERT INTO mytable (link) values('$link')");
if(!mysqli_query)
{
die("sorry");
}
else{ echo "Success"; }
mysqli_close($dbh);
}
?>
<!DOCTYPE html>
<html>
<body>
<title>Home Page</title>
<h3>Please Place your Order Below:</h3>
<form action="" method="post">
<input type="text" name="link" />
<input type="submit" name="submit" value="submit" />
</body>
</html>