The title is so general mainly because I don't know what should be the appropriate title for it. Let me just explain the situation:
Say that I have two textboxes named LastName0 and FirstName0 and a button called addMore. When I click addMore, another two textboxes will be created through JavaScript. These textboxes will be named LastName1 and FirstName1. When I click the addMore button again, another two textboxes button will be created and named LastName2 and FirstName2 respectively. This will go on as long as the addMore button is clicked. Also, a button named deleteThis will be created alongside the textboxes. This simply deletes the created textboxes when clicked.
I also initialized a variable called counter. Every time the addMore button is clicked, the counter goes up by 1, and whenever the deleteThis button is clicked, the counter decreases by 1. The value of the counter is stored in a hidden input type.
When the user submits the form, I get the value of the counter and create a For loop to get all the values of the textboxes in the form. Here is the sample code:
//Suppose that the user decides to add 2 more textboxes. Now we have the following:
// LastName0 FirstName0
// LastName1 FirstName1
// LastName2 FirstName2
$ctr = $_POST['counter']; //the counter == 3
for ($x = 0; $x < $ctr; $ctr++)
{
$lastname = $_POST["LastName$x"];
$firstname = $_POST["FirstName$x"];
//This will get the values of LastName0,1,2 and FirstName0,1,2
//code to save to database…
}
On the code above, if the value of counter is equal to 3, then the values of textboxes LastName0,1,2 and FirstName0,1,2 will be saved. Now here is the problem: If the user decided to delete LastName1 and FirstName1, the For loop will not be able to iterate properly:
$ctr = $_POST['counter']; //the counter == 2
for ($x = 0; $x < $ctr; $ctr++)
{
//Only LastName0 and FirstName0 will be saved.
$lastname = $_POST["LastName$x"];
$firstname = $_POST["FirstName$x"];
//code to save to database…
}
Someone told me to use the "push and pop" concept to solve this problem, but I am not really sure on how to apply it here. So if anyone can tell me how to apply it, it'll be grand.
Add your input text boxes with name as array ie, <input type="text" name="FirstName[]" />
In php you can fetch them as a array. ie,
foreach($_POST["FirstName"] as $k=>$val){
echo $val; // give you first name
echo $_POST["LastName"][$k]; // will give you last ame
}
In this case even if one set of field is removed in HTML will not affect the php code.
One solution would be to use the isset function like this:
$ctr = $_POST['counter'];
for ($x = 0; $x < $ctr; $ctr++)
{
isset($_POST["LastName$x"])?$lastname = $_POST["LastName$x"]:;
isset($_POST["FirstName$x"])?$firstname = $_POST["FirstName$x"]:;
}
If it is possible, instead of using LastNameN and FirstNameN names try using LastName[N] and FirstName[N], this way the result is an array and you can iterate through it with a foreach, meaning you will not need the counter and the index of the value will not be important:
foreach ($_POST["LastName"] as $i=>$lastname) {
if (!isset($_POST["FirstName"][$i])) {
// This should only happen if someone messes with the client side before posting
throw new Exception("Last name input does not have a related First name input");
}
$firstname = $_POST["FirstName"][$i];
}
If not, then you may have to use your $counter in a different way
$current = 0;
while ($counter) { // Stop only when i found all
if (isset($_POST["LastName$current"]) {
$counter--; // Found one
$lastname = $_POST["LastName$current"];
$firstname = $_POST["FirstName$current"];
}
$current++;
}
A better way to solve this would be to use arrays for Firstname and Lastname. Instead of calling them Lastname0 and Firstname0, then Lastname1 and Firstname1, call them all Lastname[] and Firstname[]. Give them ID's of Lastname0 and Firstname0 and so on for the delete function, but keep the names as arrays.
When the form is submitted use the following:
foreach($_POST['Lastname'] as $i => $lastname) {
$firstname = $_POST['Firstname'][$i]
//... code to save into the database here
}
Be warned though that in IE if you have an empty field it will not be submitted, so if Lastname0 has a value, but Firstname0 does not, then $_POST['Firstname'][0] will in fact contain the value of Firstname1 (assuming it has a value in it). To get around this you can use javascript to check if a field is empty when submitting the form, and if so put the word EMPTY in it.
Do not use counter if not required
A much easier way is to add array name when admore clicked.
Give a name like first_name[] in textbox
if you create form like that you can use foreach through $_POST['first_name']
try var_dump($_POST) in you php code to see how things goes on.
Inside your for loop, maybe you could try...
if ((isset($_POST["LastName$x"])) && (isset($_POST["FirstName$x"]))){
$lastname = $_POST["LastName$x"];
$firstname = $_POST["FirstName$x"];
//code to save to database…
}
This will check if the variables exists before you try to do anything with them.
Hey guy i have following problem:
I have this line of code which includes a checkbox:
echo('<td bgcolor="'.$Color.'"><input type="checkbox" name="altgeraet" value="'.$resultarray['Status_Altgeraet'].'"></td');
Now i want when the checkbox is selected the mysql value of Status_Altgeraet is set to OK if not it should be set to NOK. At the bottom of my page there is a button when then someone klicks it it goes to my next php file where all data is processed. Here is the point where the mysql value shoul be updated. I have tried following to get the checkbox in to an variable to work with it but it seems not to work:
$Altgeraet = $REQUEST['Status_Altgeraet']));
I am no php expert just an beginner. Hope you guys can give me some tips to solve it :)
$Altgeraet = isset($REQUEST['altgeraet']) ? 'OK' : 'NOK';
Or in a more familiar syntax:
if (isset($_REQUEST['altgeraet'])) {
$Altgeraet = 'OK';
} else {
$Altgeraet = 'NOK';
}
If the checkbox is not checked, it will not be present in $_REQUEST/$_GET/$_POST at all.
Hi so have form with a vote and what i want to do is what ever options they tick, when they click submit it the posts all the values of the check boxes ticked to the same page allowed me to echo them
i have tried just doing this
if(isset($_POST['submitted'])) {
$list = $_POST['vote'];
echo $list;
}
but that only echos the last value selected
Thanks,
Ben
ok so i have a fix by changing the name to an array but i got a problem because i used javascript functions like this
checkAll(document.form.vote)
so what do i change it to?
When you name the inputs you can give it a name like name="checkboxes[]" and that will throw it in an array when it posts to the next page. Hope that helps!
In your form set name attribut like this:
<input type="checkbox" name="vote[]" />
Then you can:
foreach($_POST['vote'] as $vote){
echo $vote;
}
I have been working on this one topic for weeks. I'm creating a webpage that pulls information from MsSQL server. My problem is where there is a section with few check boxes.
The checkboxes are suppose to be checked if they are found in the SQL database.
If the borrower used money from "Savings", "Checking" and "Stock" those checkboxes should be checked in HTML page. In my case it is only checking whatever is on the first row of the SQL search list. So if the list has "Saving" on the first row, only the "Saving" checkbox will be checked not the rest on the list. I tried using loop (while($r->EOF)), but then it picks whatever is on the end of the list. Here is what I am using to pull data from the SQL server. Thank you in advance for your help. Really appreciate it!
function __construct($_ldid, $_lrid)
$this->ldid = $_ldid;
$this->lrid = $_lrid;
//$loan is defined in the PHP.class (which is shown below).
$q = ("SELECT * FROM Tabel_name where loan_id = 885775")
$v = array($_ldid, $_lrid);
$r = $db->Execute($q, $v);
$this->downpaymenttype = $r->fields; //<- I think I have this line done wrong because it is suppose to store the outputs to an array.
//So wherever the "$loan" is in HTML page, it will take the outputs from the above statement.
//The above code, which is in PHP.class file, outputs the following(or suppose to):
1 885775 Checking
2 885775 Saving
3 885775 Gift
In the HTML webpage, the following codes should check mark the boxes according to the outputs:
<input type="checkbox" name="DPS1[]" id="DPS1-{$key}" {if $loan-> downpaymenttype.downpaymentsource == "Checking"} checked {/if}/>
<input type="checkbox" name="DPS2[]" id="DPS2-{$key}" {if $loan-> downpaymenttype.downpaymentsource == "Saving"} checked {/if}/>
<input type="checkbox" name="DPS3[]" id="DPS3-{$key}" {if $loan-> downpaymenttype.downpaymentsource == "Gift"} checked {/if}/>
Only the "checking" checkbox is getting checked because that's the one on the first row.
I also tried to loop, but it is not storing in array (I guess I don't know how to use the array for session)
$q = ("SELECT Tabel_name FROM loan_downpaymentsource where loan_id = 885775");
$v = array($_ldid, $_lrid));
$r = $db->Execute($q, $v);
while(!$r->EOF) {
$this->downpaymenttype = $r->fields;
$r->MoveNext();
}
Add a loop to go through your results before displaying and set flags. $r->fields is only going to grab the fields for the current row. You need to go through your entire rowset to see if the others are set.
Something like (It looks like you're using adodb or something like that)
$checking = false;
$saving = false;
$gift = false;
while(!$r->EOF){
$row = $r->fields;
switch($row->downpaymenttype){
case 'Checking':
$checking=true;
break;
case 'Saving':
$saving=true;
break;
case 'Gift':
$gift=true;
break;
default:
break;
}
$r->moveNext();
}
Now on your view check the flags. I've not used smarty but you'll have to pass those flags to your template as well as I'm sure you know, and then change your checkbox lines to check if each flag is true/false.
Hope that helps!
I have two forms
a) post.php
b) edit.php
I am using the checkbox in both the form to set the binary value (0 and 1) to set the status for approve.
to process the value from the checkbox in the post.php I am using the code which checks and assume that if the checkbox is checked then the value will be 1 other wise it is 0 by default
if (isset($_POST['ad_approve'])) $ad_approve = htmlspecialchars(strip_tags(mysql_real_escape_string($_POST['ad_approve'])));
else { $ad_approve = 0; }
Now in the edit.php form I retrieve the data from the database and set the checkbox accordingly . if the approve has the value 1 then it is checked by default . look onto the following code
<input name="ad_approve" type="checkbox" value="1" <?php if($approve==1) echo 'checked="checked"';?> />
in the above code I cannot apply the same logic to catch the value from ad_approve i.e(by checking isset()) because if the value is 1 by default and if I try unchecking the checkbox then automatically the program assume that the value is set because it has been changed from checked to unchecked. now in the edit.php how do I again process the value from it such that if the checkbox is checked hold the value as 1 otherwise 0, ??
to be honest your question does not make a whole lot of sense but I can understand that you wish to check if check boxes are actually set.
firstly you don't need a value attribute on a check box because its the browser that decide what value if any to send via the GP headers.
http://www.w3.org/TR/html401/interact/forms.html
Checkboxes (and radio buttons) are
on/off switches that may be toggled by
the user. A switch is "on" when the
control element's checked attribute is
set. When a form is submitted, only
"on" checkbox controls can become
successful.
So basically if a checkbox is not selected then the entity will not be sent via the headers, there for isset() would be a perfectly usable check.
The way your using real escape is totally wrong, you should never user real escape for html, DATABASE ONLY.
Take this code for example
if(isset($_POST['some_check']))
{
echo $_POST['some_check']; //on
}else
{
echo 'some_check has not been checked';
}
Your code:
if (isset($_POST['ad_approve'])) $ad_approve = htmlspecialchars(strip_tags(mysql_real_escape_string($_POST['ad_approve'])));
else { $ad_approve = 0; }
Can you give me a good excuse why your using htmlspecialchars,strip_tags and mysql_real_escape_string on an entity that can be done like so:
$ad_approve = isset($_POST['ad_approve']) ? true : false;
for issues like this its not that hard to refer to the documentation to get a better understand of what exactly is being sent from the browser.
if you wish to add values to to the checkboxes that you would do this with hidden fields, example follows.
<input type="checkbox" name="check_box" />
<input type="hidden" name="check_box_value" value="01100001" />
And within the php server side.
if(isset($_POST['check_box']))
{
echo $_POST['check_box_value']; //01100001
}else
{
echo 'some_check has not been checked';
}
by adding another html input thats hidden you can hide elements from the user and then use as data holders, the reason why you should use the exact same name but append it with _value is just for best practises.
EDIT
if(isset($_POST['some_check_box']))
{
mysql_query('UPDATE profile SET receive_mail = 1');
}else
{
mysql_query('UPDATE profile SET receive_mail = 0');
}