This is the JSON
{
"circuit_list": [
{
"_id": "58c0f378a986f808cdaf94cf",
"aggregation": {
"dev_name": "ME2-D2-BOO",
"port": {
"desc": "AKSES_SITE_SITE-TSEL_ME2-D2-BOO#1/2/5_200M_BOO082#CIPAKUBOO534",
"name": "1/2/5"
}
},
"area": "AREA 2",
"site_id": "N/A",
"site_name": "N/A"
},
{
"_id": "58c0f378a986f808cdaf94d0",
"aggregation": {
"dev_name": "ME2-D2-BOO",
"port": {
"desc": "AKSES_SITE_SITE-TSEL_ME2-D2-BOO#1/2/5_200M_BOO082#CIPAKUBOO534",
"name": "1/2/5"
}
},
"area": "AREA 2",
"site_id": "N/A",
"site_name": "N/A"
}
}
I already try with this code
$json = json_decode($url, true);
foreach($json as $value)
{
$_id = $value->_id;
}
it didn't work. Please help, I need to get the value to show them on the view. Did I do this wrong? this json is difficult because i didn't understand the structure.
I usually decode json with format
[{"id":"1","name":"faisal"}]
like this and with my foreach it's working.
If the second parameter of json_decode is true, the function will return an array instead of an object. Also, you would need to loop over the circuit_list property of the object.
$json = json_decode($url); // <- remove the parameter
foreach($json->circuit_list as $value) // <- loop over circuit_list
{
$_id = $value->_id;
}
<?php
$json = json_decode($url,true);
foreach($json['circuit_list'] as $value)
{
$id = $value['_id'];
}
?>
Related
This question already has answers here:
Get data from JSON file with PHP [duplicate]
(3 answers)
Closed 6 years ago.
I want print specific vars from array inside a document.
JSON structure:
{
"return": {
"string": "2222",
"contacts": [
{
"contact": {
"id": "09890423890"
}
},
{
"contact": {
"id": "2423444"
}
},
{
"contact": {
"id": "24242423"
}
},
etc
]
}
}
I am trying to do this in PHP (and already decoded that json). How can I access and print all ids using foreach or for?
I can not understand how I can manage "return" scope.
You can decode the json contents and use it like an array. This should work:
$json = json_decode($string, true);
$contacts = $json['return']['contacts'];
foreach($contacts as $contact){
echo $contact['contact']['id'];
}
Json decode to array:
$json = json_decode($strjson, true); // decode the JSON into an associative array
and
echo "<pre>";
print_r($json);
And foreach:
foreach ($json as $key => $value) {
echo $key . " ". $value. "<br>";
}
Working example:
$json = '{
"return": {
"string": "2222",
"contacts": [
{
"contact": {
"id": "09890423890"
}
},
{
"contact": {
"id": "2423444"
}
},
{
"contact": {
"id": "24242423"
}
}
]
}
}';
$json = json_decode($json, true);
print_r($json);
foreach ($json['return']['contacts'] as $val) {
echo $val['contact']['id']."<br>";
}
Try this code:
$json ='
{
"return": {
"string": "2222",
"contacts": [
{
"contact": {
"id": "09890423890"
}
},
{
"contact": {
"id": "2423444"
}
},
{
"contact": {
"id": "24242423"
}
},
etc
]
}
}
';
$array = json_decode($json,TRUE);
foreach($array['return']['contacts'] as $value ){
echo $value['id'];
}
Use file_get_contents function if you want to pull data from file.
I have a code that outputs the json result below:
{
"Ghost in the Shell": {
"id": 1203,
"Pipeline": {
"id": 6144,
"name": "Pipeline",
"status": "New",
"item_id": 5962,
"TotalTasksOpen": 2
}
}
}
Now how can I format it in the my desired json format below:
Note* I have to remove some result.
{
"Ghost in the Shell":
"id": 6144,
"name": "Pipeline",
"status": "New",
"item_id": 5962,
"TotalTasksOpen": 2
}
Will appreciate if anyone can help me please.
I am not sure what is your purpose , but here is what you need
<?php
$json = '{
"Ghost in the Shell": {
"id": 1203,
"Pipeline": {
"id": 6144,
"name": "Pipeline",
"status": "New",
"item_id": 5962,
"TotalTasksOpen": 2
}
}
}';
$array = json_decode($json, true);
$newArray = array();
foreach($array as $key=>$value) {
$newArray[$key] = '';
foreach($value as $k=>$v) {
if(is_array($v)) {
$newArray = array_merge($newArray,$v);
}
}
}
$newJson = json_encode($newArray);
echo $newJson;
?>
I am trying to decode JSON data to PHP then output it to the site. If I have the following:
{
"name": "josh",
"type": "human"
{
I can do this (within PHP), to display or output my type:
$file = "path";
$json = json_decode($file);
echo $json["type"]; //human
So, if I have the following:
{
"name": "josh",
"type": "human",
"friends": [
{
"name": "ben",
"type": "robot"
},
{
"name": "tom",
"type": "alien"
}
],
"img": "img/path"
}
How can I output what type my friend ben is?
Use a loop like foreach and do something like the following:
//specify the name of the friend like this:
$name = "ben";
$friends = $json["friends"];
//loop through the array of friends;
foreach($friends as $friend) {
if ($friend["name"] == $name) echo $friend["type"];
}
To get the decoded data in array format you would supply true as the second argument to json_decode otherwise it will use the default which is object notation. You could easily create a function to shorten the process when you need to find a specific user
$data='{
"name": "josh",
"type": "human",
"friends": [
{
"name": "ben",
"type": "robot"
},
{
"name": "tom",
"type": "alien"
}
],
"img": "img/path"
}';
$json=json_decode($data);
$friends=$json->friends;
foreach( $friends as $friend ){
if( $friend->name=='ben' )echo $friend->type;
}
function finduser($obj,$name){
foreach( $obj as $friend ){
if( $friend->name==$name )return $friend->type;
}
}
echo 'Tom is a '.finduser($friends,'tom');
try this,
$friend_name = "ben";
$json=json_decode($data);
$friends=$json->friends;
foreach( $friends as $val){
if($friend_name == $val->name)
{
echo "name = ".$val->name;
echo "type = ".$val->type;
}
}
DEMO
I;m trying to get data from a website using the following code:
<?php
$url = 'http://services.runescape.com/m=itemdb_oldschool/api/catalogue/detail.json?item=4798';
$content = file_get_contents($url);
var_dump($content);
$json = json_decode($content, true);
var_dump($json);
for ($idx = 0; $idx < count($json); $idx++) {
$obj = (Array)$json[$idx];
echo 'result' . $obj["name"];
}
?>
Which is getting me this result:
string(0) "" NULL
<?php
$url = 'http://services.runescape.com/m=itemdb_oldschool/api/catalogue/detail.json?item=4798';
$content = file_get_contents($url);
echo "<pre>";
//print_r($content);
$data = json_decode($content);
print_r($data); //Show the json decoded data comes form $url
##Parse this array {$data} using foreach loop as your use
?>
There are no numeric keys in the json returned from the url you posted in your question. So iterating through the associative array with numeric keys returns nothing.
This is the structure of the json you are working with:
{
"item": {
"icon": "http://services.runescape.com/m=itemdb_oldschool/5122_obj_sprite.gif?id=4798",
"icon_large": "http://services.runescape.com/m=itemdb_oldschool/5122_obj_big.gif?id=4798",
"id": 4798,
"type": "Default",
"typeIcon": "http://www.runescape.com/img/categories/Default",
"name": "Adamant brutal",
"description": "Blunt adamantite arrow... ouch.",
"current": {
"trend": "neutral",
"price": 529
},
"today": {
"trend": "neutral",
"price": 0
},
"members": "true",
"day30": {
"trend": "negative",
"change": "-9.0%"
},
"day90": {
"trend": "negative",
"change": "-20.0%"
},
"day180": {
"trend": "negative",
"change": "-31.0%"
}
}
}
Try accessing $json["item"]. That should give you something more meaningful to work with. If you want to iterate over the key/value pairs in the item, use a foreach loop:
foreach($json["item"] as $key => $value) {
echo $key . ":";
print_r($value);
}
I have web page which get Json responce like this
{
'hotel_1page':[
{
'id':'10',
'name':'fsf',
'telephone':'233333'
},
{
'id':'11',
'name':'setttttt',
'telephone':'213123123'
},
{
'id':'12',
'name':'fsdfsdf',
'telephone':'122212121'
},
{
'id':'13',
'name':'xxcvcxv',
'telephone':'2147483647'
},
{
'id':'14',
'name':'dssdfg',
'telephone':'2147483647'
},
{
'id':'15',
'name':'dfsdfsdf',
'telephone':'21312321'
},
{
'id':'16',
'name':'fx_test_nw1',
'telephone':'23232323'
},
{
'id':'17',
'name':'fx_test_nw2',
'telephone':'31313131'
}
]
}
and i want to loop through this data and get this data to array and display as html how can i achieve this
this is where i get get json responce,and when i var_dump json encoded variable it says null,where $json variable shows the json responce,
$json = file_get_contents('http://www.example.com/hotel_list.php');
var_dump($json);
$array = json_decode($json, true);
var_dump($array);
The json that you are trying to parse is invalid. Change the single quotes to double quotes and you should be able to parse it to an array.
The JSON documentation says
A value can be a string in double quotes, or a number, or true or false or null, or an object or an array. These structures can be nested.
This should work:
$json = '{ "hotel_1page": [ { "id": "10", "name": "fsf", "telephone": "233333" }, { "id": "11", "name": "setttttt", "telephone": "213123123" }, { "id": "12", "name": "fsdfsdf", "telephone": "122212121" }, { "id": "13", "name": "xxcvcxv", "telephone": "2147483647" }, { "id": "14", "name": "dssdfg", "telephone": "2147483647" }, { "id": "15", "name": "dfsdfsdf", "telephone": "21312321" }, { "id": "16", "name": "fx_test_nw1", "telephone": "23232323" }, { "id": "17", "name": "fx_test_nw2", "telephone": "31313131" } ] }';
echo '<pre>';
var_dump(json_decode($json, true));
echo '</pre>';
I replaced all single quotes with double quotes, that did the trick.
I used single quotes before which caused json_decode to return null
[Edit for usage]
To use the data, you could use something like this:
$obj = json_decode($json, true);
foreach($obj as $row)
{
foreach($row as $key => $item)
{
// $item['id']
// $item['name']
// $item['telephone']
}
}
I'm using a nested foreach() because the id, name and telephone are an array within the hotel_page1 array