Replace div contents with content from PHP file - php

Question

This is the php file containing the new content, to replace .hotels when the form is submitted.
<?php
if(isset($_POST['submit'])){
$pdo = new PDO('mysql:host=localhost;dbname=CSV_DB', 'root', 'root');
$inputType = $_POST['type'];
$inputCategory = $_POST['category'];
$type = $pdo->query("SELECT * FROM Hotels WHERE Type LIKE '%$inputType%' AND Price_Range= '$inputCategory'");
foreach($type as $row){
echo"<div id='newHotels'>";
echo "<div class='hotelImage'></div>";
echo'<h4>'.$row['Hotel_Name']." ".$row['Rating']."*".'</h4>'." ".'<p>'.$row['Description'].'</p>'." "."Location: ".$row['Location']." ".'<h4 style="font-weight: bold">'."£".$row['Price']."p/p".'</h4>';
echo "</div>";}
}
?>
Here is the original div that displays all the hotels in the database when the page loads and that I want to replace with the new content when the form is submitted:
<div id="hotels">
<?php
$pdo = new PDO('mysql:host=localhost;dbname=CSV_DB', 'root', 'root');
$display = $pdo->query('SELECT Hotel_Name, Description, Location, Rating, Price FROM Hotels');
foreach ($display as $row){
if($row)
echo"<div id='hotel'>";
echo "<div class='hotelImage'></div>";
echo'<h4>'.$row['Hotel_Name']." ".$row['Rating']."*".'</h4>'." ".'<p>'.$row['Description'].'</p>'." "."Location: ".$row['Location']." ".'<h4 style="font-weight: bold">'."£".$row['Price']."p/p".'</h4>';
echo "</div>";}
?>
</div>
And here is the Ajax that is supposed to change the content
$(function () {
$('form').on('submit', function (e) {
e.preventDefault();
$.ajax({
type: 'post',
url: 'form.php',
data: $('form').serialize(),
success: function(data) {
$(".hotels").html(data);
}
});
});
});
I need help replacing the contents of .hotels with the search results of my form when the form submits however the div just becomes empty. I think I need to make data equal to the search results but not sure how to go about it.

Answer 1

submitted the console log says data is not defined.
You need to define data in the success function.
$(function () {
$('form').on('submit', function (e) {
e.preventDefault();
$.ajax({
type: 'post',
url: 'form.php',
data: $('form').serialize(),
success: function(data) { /* you missed variable data here */
$("#hotel").html(data);
}
});
});
});

Answer 2

The console log saying "data" is not defined means there is no variable named "data". to solve this issue, you could either create a global variable called "data", or pass "data" as an argument to the success function. This would then look somewhat like this:
$(function () {
$('form').on('submit', function (e) {
e.preventDefault();
$.ajax({
type: 'post',
url: 'form.php',
data: $('form').serialize(),
success: function(data) {
$("#hotel").html(data);
}
});
});
});