PHP - Create multiple arrays based on value - php

Question

I have an array like this:
$r = array();
$r[] = ['name' => 'Test', 'supplierId' => 34];
$r[] = ['name' => 'Test2', 'supplierId' => 31];
$r[] = ['name' => 'Test3', 'supplierId' => 32];
$r[] = ['name' => 'Test4', 'supplierId' => 34];
$r[] = ['name' => 'Test5', 'supplierId' => 30];
$r[] = ['name' => 'Test6', 'supplierId' => 32];
Now I want to take $r and get multiple arrays back, differenced by supplierId. So I am looking for this result:
$r30 = ['name' => 'Test5', 'supplierId' => 30];
$r32 = [
['name' => 'Test3', 'supplierId' => 32],
['name' => 'Test6', 'supplierId' => 32]
];
I tried it with, but here I do not have access to $sup in array_filter.
$supplier = array(30, 31, 32, 34);
$finalArray = [];
foreach ($supplier as $sup) {
$finalArray[] = array_filter($r, function($value, $sup) {
echo $sup;
if ($value['supplierId'] == $sup) {
return true;
}
});
}//foreach
Any idea how I can solve it? Is there no native function that accomplishes this - something like create_array_based_on('supplierId');?
Thanks

Answer 1

You can pass $sup to your anonymous function:
foreach ($supplier as $sup) {
$finalArray[] = array_filter($r, function($value) use ($sup) {
^^^^^^^^^^ you need to pass
it like this
echo $sup;
if ($value['supplierId'] == $sup) {
return true;
}
});
}//foreach
But personally I would probably just loop over the original array and use the supplier ID as a key.
Something like:
$results = [];
foreach ($r as $value) {
$results[$value['supplierId']][] = $value;
}

Answer 2

Try this out
$r = array();
$r[] = ['name' => 'Test', 'supplierId' => 34];
$r[] = ['name' => 'Test2', 'supplierId' => 31];
$r[] = ['name' => 'Test3', 'supplierId' => 32];
$r[] = ['name' => 'Test4', 'supplierId' => 34];
$r[] = ['name' => 'Test5', 'supplierId' => 30];
$r[] = ['name' => 'Test6', 'supplierId' => 32];
$supplier = array(30, 31, 32, 34);
$finalArray = [];
$i=0;
foreach ($supplier as $sup) {
$value =$r[$i]['supplierId'];
if($value==$sup)
{
$finalArray[] = $value;
}
$i++;
}//foreach
$finalArray is a new array with all values you need

Answer 3

You can combine array_filter and in_array as following:
$finalArray[] = array_filter($r, function($value) use ($supplier) {
return in_array($value['supplierId'], $supplier);
});
Without foreach loop.

Answer 4

It would be much easier, instead of wanting new variables for each of them, like $r32, $r35, etc... if you just used the array keys to store the supplierid, e.g.
$r = array();
$r[] = ['name' => 'Test', 'supplierId' => 34];
$r[] = ['name' => 'Test2', 'supplierId' => 31];
$r[] = ['name' => 'Test3', 'supplierId' => 32];
$r[] = ['name' => 'Test4', 'supplierId' => 34];
$r[] = ['name' => 'Test5', 'supplierId' => 30];
$r[] = ['name' => 'Test6', 'supplierId' => 32];
$newArray = array();
foreach($r as $key => $element)
{
if (!isset($newArray[$element['supplierId']])){
$newArray[$element['supplierId']] = array();
}
$newArray[$element['supplierId']][] = $element;
}
That would give you an output of:
<pre>Array
(
[34] => Array
(
[0] => Array
(
[name] => Test
[supplierId] => 34
)
[1] => Array
(
[name] => Test4
[supplierId] => 34
)
)
[31] => Array
(
[0] => Array
(
[name] => Test2
[supplierId] => 31
)
)
[32] => Array
(
[0] => Array
(
[name] => Test3
[supplierId] => 32
)
[1] => Array
(
[name] => Test6
[supplierId] => 32
)
)
[30] => Array
(
[0] => Array
(
[name] => Test5
[supplierId] => 30
)
)
)
</pre>

Answer 5

It's about simple grouping nested arrays by some key value:
$finalArr = [];
foreach ($r as $arr) {
$finalArr[$arr['supplierId']][] = $arr;
}
print_r($finalArr);
DEMO link