i want to create table with php variable + name - php

Question

i want to create table with php variable+ name
like.
here is my code
if($conn->query($sql1)===TRUE){
$_SESSION['username'] = $x;
$sql = "CREATE TABLE $x
(
ID int NOT NULL AUTO_INCREMENT,
image blob,
date datetime,
status longtext,
PRIMARY KEY (ID)
)";
$sql2 = "CREATE TABLE ".$x."_frnd
(
ID int NOT NULL AUTO_INCREMENT,
myfrndname varchar(255),
myfrndusername varchar(255),
PRIMARY KEY (ID)
)";
$result= mysqli_query($conn,$sql,$sql2);
if ($conn->query($result) === TRUE) {
}
here ($x) is a variable and frnd is mannual name-
i want result table like this.
[ adminfrnd ].
please suggest me.

Answer 1

Try something like this:
CREATE TABLE IF NOT EXISTS `{$x}frnd` (
`id` mediumint(6) unsigned zerofill NOT NULL auto_increment,
`myfrndname` varchar(255) NOT NULL,
`myfrndlastname` varchar(255) NOT NULL,
`myfrndusername` varchar(255) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=MyISAM DEFAULT CHARSET=utf8 COLLATE=utf8_bin
by the way
Why do you want to make own table for each admin ?

Answer 2

What you have to do is to append text like this:
$sql = "CREATE TABLE " . $x . "frnd
( ID int NOT NULL AUTO_INCREMENT,
myfrndname varchar(255),
myfrndlastname varchar(255),
myfrndusername varchar(255),
PRIMARY KEY (ID) )";

Answer 3

In your example $x should be string.
Your code will look like:
$x="admin";
$sql = "CREATE TABLE ".$x."_frnd
( ID int NOT NULL AUTO_INCREMENT,
myfrndname varchar(255),
myfrndlastname varchar(255),
myfrndusername varchar(255),
PRIMARY KEY (ID) )";
$result= mysqli_query($conn,$sql);
if ($conn->query($result) === TRUE) {
}
Note: its never good habit to use .(dot) in table name use _(underscore) instead