How to add value to row by id sql - php

Question

I have two arrays with ID and description.
In database I have same ID but doesn't have description.
How I can add each description form array to current ID?
This is full code
foreach($product->find('.block-d .btns-d .btn-buy') as $productId) {
if(!empty($productId)) {
dataId = $productId->{'data-offerid'};
}
}
foreach($product->find('.description div div p') as $description) {
if(!empty($description)) {
$query = "UPDATE snowcore_parser_products SET description = " . $description . " WHERE remote_id = " . $dataId . " ';";
$sql = mysqli_query($db, $query);
}
}
If I try to use just simple value without array it works. For example
$query = "UPDATE snowcore_parser_products SET description = '1';";

Answer 1

I think your query is malformed. It doesn't have quotes around the description to indicate it is a string. For example, if the value for description is "stackoverflow" and the id is "1", your query would look like so:
UPDATE snowcore_parser_products SET description = stackoverflow WHERE remote_id = 1 ';
So to fix this, the last quote should disappear and the value for description should be surrounded with quotes. Like this:
$query = "UPDATE snowcore_parser_products SET description = '" . $description . "' WHERE remote_id = " . $dataId . ";
Also I recommend you to read this article on SQL injection, as this query isn't safe.

Answer 2

just use foreach and that`s all, try this:
$ids = [1,2,3];
$descriptions = [1,2,3];
foreach($ids as $key => $id) {
$query = "UPDATE snowcore_parser_products SET description = " . $descriptions[$key] . " WHERE remote_id = " . $id . " ';";
$sql = mysqli_query($db, $query);
}