First of all, I am using Bootstrap Dual Listbox that I got from http://www.virtuosoft.eu/code/bootstrap-duallistbox/
After trying to implement it, I encounter a single problem. At first run, the options are not being displayed on either select box unless I click the Move All button.
So here is the structure as well as the codes.
Index.php
<!-- HTML -->
<select multiple="multiple" size="5" class="eItems" name="skillsTagged" id="skillsTagged">
</select>
<!-- Scripts-->
<script>
$(document).ready(function(){
var dlb1 = $('#skillsTagged').bootstrapDualListbox({
nonSelectedListLabel: 'Non-selected',
selectedListLabel: 'Selected',
preserveSelectionOnMove: 'moved',
moveOnSelect: false
});
getSkills();
});
function getSkills(){
var oldid = "1";
$.ajax({
type: "POST",
url: "get_selected_skills.php",
data: { specId : oldid }
}).done(function( res ) {
$("#skillsTagged").html(res);
});
}
</script>
get_selected_skills.php
<?php
echo "<option value='1'>1</option><option selected value='2'>2</option><option value='3'>3</option><option value='4'>4</option><option selected value='5'>5</option>";
?>
So it seems like the options are there but are not being displayed on first run. Tried it on a regular listbox and is working so if anyone already encountered this when using Dual Listbox, your help will be greatly appreciated! Thanks!
Try to set ajax async property to false...
İn method : async:false
Or globally:
$.ajaxSetup({
async:false
});
Related
I want to set selected value of a select input to a php variable. When I select a value from select box, then want to put that value in php variable and use echo select option value, but I can't get this value in select box inside php code. My Code is given below.
<body>
<select>
<?php
$test='<label id="output"></label>';
echo "<option>".$test."</option>";
?>
</select>
<select id="sel">
<option>--select--</option>
<option>amr</option>
<option>tomar</option>
</select>
</body>
<script type="text/javascript">
$(document).ready(function(){
$( "#sel" ).change(function() {
var ww = $( "#sel" ).val();
//alert(ww);
$( "#output" ).text(ww);
});
});
</script>
Use AJAX
$.ajax({
type: "POST",
url: "some.php",
data: { ww: ww}
})
.done(function( msg ) {
alert( "Data Saved: " + msg );
});
And in some.php using POST you can set $ww = $_POST['ww'];
Reference
http://api.jquery.com/jquery.ajax/
PHP is a server-side-language, so the php-code is executed before anything is showed on the screen.
That also means that when the page is loaded you can no longer interact with the php code.
For what it sounds like you're trying to do (a little hard to understand), it sounds like you need to use javascript to change the content on the page at runtime :)
You're select box hasn't got an id of sel, which is what the JS is listening for the change event on, I also can't see the div with the id output, which is where the results are going.<select id="sel"> And <div id="output"></div>
Hope someone can help me..
i made my program more simpler so that everybody will understand..
i want my program to get the value of the without submitting, i know that this can only be done by javascript or jquery so I use the onChange, but what I want is when i select an option the value should be passed immediately on the same page but using php..
<select id="id_select" name="name" onChange="name_click()">
<option value="1">one</option>
<option value="2">two</option>
</select>
<script>
function name_click(){
value_select = document.getElementById("id_select").value;
}
</script>
and then i should pass the value_select into php in post method.. i dont know how i will do it.. please help me..
You cannot do this using PHP without submitting the page. PHP code executes on the server before the page is rendered in the browser. When a user then performs any action on the page (e.g. selects an item in a dropdown list), there is no PHP any more. The only way you can get this code into PHP is by submitting the page.
What you can do however is use javascript to get the value - and then fire off an AJAX request to a php script passing the selected value and then deal with the results, e.g.
$(document).ready(function() {
$('#my_select').on('change', do_something);
});
function do_something() {
var selected = $('#my_select').val();
$.ajax({
url: '/you/php/script.php',
type: 'POST',
dataType: 'json',
data: { value: selected },
success: function(data) {
$('#some_div').html(data);
}
});
}
With this code, whenever the selected option changes in the dropdown, a POST request will be fired off to your php script, passing the selected value to it. Then the returned HTML will be set into the div with ID some_div.
not sure ..but i guess ajax is what you need..
<script>
function name_click(){
value_select = $("#id_select").val();
$.post('path/to/your/page',{"value":value_select},function(data){
alert('done')
})
}
</script>
PHP
$value=$_POST['value']; //gives you the value_select data
Post with ajax as Alex G was telling you (+1) and then handle the post with PHP. You can define a callback in Javascript which will run when the page responds.
My suggestion go with jquery. Try with this
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.9.1/jquery.min.js">
<script>
$(document).ready(function(){
$("#id_select").change(function(){
var url = 'http:\\localhost\getdata.php'; //URL where you want to send data
var postData = {'value' : $(this).value};
$.ajax({
type: 'POST',
url: url,
data : postData,
dataType: 'json',
success: function(data) {
//
},
error: function(e) {
console.log(e.message);
}
});
})
})
</script>
In getdata.php
<?php
var $value = $_POST['value'];
// you can do your logic
?>
I'm trying to get a drop down box to alter a second drop down box through the use of a jquery/ajax script. Firebug is showing Jquery is working but my script isn't showing at all.
<script type="text/javascript">
function ajaxfunction(parent)
{
$.ajax({
url: '../functions/process.php?parent=' + parent;
success: function(data) {
$("#sub").html(data);
}
});
}
</script>
process.php is just a MySQL query (which works)
My initial drop down box is populated by a MySQL query
<select name="front-size" onchange="ajaxfunction(this.value)">
//Query
</select>
And then the second drop down box is just
<select name = "front-finish" id="sub">
</select>
How can I solve this?
calling inline function is not good at all... as web 2.0 standards suggest using unobtrusive JS rather than onevent attributes....check out why here..
other thigs..correct way to use ajax is by using type and data ajax option to send values in controller..
<script type="text/javascript">
$(function(){
$('select[name="front-size"').change(function()
{
$.ajax({
url: '../functions/process.php',
type:'get',
data:{'value' : $(this).val()},
dataType:"html", //<--- here this will take the response as html...
success: function(data) {
$("#sub").html(data);
}
});
});
});
</script>
and your proces.php should be..
<?php
//db query ...thn get the value u wanted..
//loop through it..
$optVal .= "<option value="someDbValue">some DDB values</option>";
// end loop
echo $optValue;exit;
updated
looks like you still have onchange="ajaxfunction(this.value)" this in your select remove that it is not needed and the ajaxfunction in javascript too...
<select name="front-size" >
//----^ here remove that
use jQuery.on() that will allow us to add events on dynamically loaded content.
$('select[name^="front-"]').on('change',function(e){
e.preventDefault();
var value = $(this).val();
ajaxfunction(value);
});
[name^="front-"] this will select all the SELECT box having name starts with front-.
In your process.php give like this
echo "<select name='front-finish' id='sub' onchange='ajaxfunction(this.value)'>";
like this you need to add the "onchange" function to the newly created select box through ajax
or you can remove onchange function and write like
$("select[name^='front-']").live('change',function(){
//Do your ajax call here
});
I have two dropdown boxes, actually I have done this functionality by using jquery and ajax by calling an id that if I select one thing it will appear on second select box but the main problem I am facing is that I am using a template where a select box uses some class name called "cho" as if I don't use this class obviously my select box look wired so I like the style of it .So if I use this class in my second select box where the result display then the functionality wont work but if I don't use the class then it will work so what I want is:
I want to use the css class and implement the functionality too I checked in every css file but I cant find cho class so what I think that if I cant change the css file may be there is the way in jquery that I'll resolve this issue.
This is my first select box ,where select box and css working fine.
<?php echo form_dropdown('cat_id', $records2, '#', 'id="category" class = "cho"');?>
2nd select box -without css ..functionality successfull
<?php echo form_dropdown('item_id', $records3, '#', 'id="items"'); ?>
With css--functionality wont work but css do:
<?php echo form_dropdown('item_id', $records3, '#', 'id="items" class = "cho"'); ?>
My javascript:
<script type="text/javascript">// <![CDATA[
$(document).ready(function(){
$('#category').change(function(){
$("#items > option").remove();
var category_id = $('#category').val();
$.ajax({
type: "POST",
url: "stockInController/get_Items/"+category_id,
success: function(items)
{
$.each(items,function(item_id,item_name)
{
var opt = $('<option />');
opt.val(item_id);
opt.text(item_name);
$('#items').append(opt);
});
}
});
});
});
</script>
html file source of two dropdown
<div class="controls">
<select name="cat_id" id="category" class = "cho">
<option value="1">jeans</option>
<option value="2">shirts</option>
</select>
<br />
</div>
</div>
Items:
sdf
bello
gamer
dsf
blue
Have you tried firebug or any other similar tool to find out your 'cho' class. Try this code also
$("#items").addClass("cho");
OK try selecting through name:
<script type="text/javascript">// <![CDATA[
$(document).ready(function(){
$('#category').change(function(){
$('select[id="items_chzn"] > option').remove();
var category_id = $('#category').val();
$.ajax({
type: "POST",
url: "stockInController/get_Items/"+category_id,
success: function(items)
{
$.each(items,function(item_id,item_name)
{
var opt = $('<option />');
opt.val(item_id);
opt.text(item_name);
$('select[id="items_chzn"]').append(opt);
});
}
});
});
});
</script>
If you are still having an issue try using an alert in the function after the ajax call.
Sorry in advance everyone for this question as I know the cascading select boxes has been done to death but I can't seem to find any good help. I've tried various things but it all seems to fail and I'm not understanding why.
Here's the jquery I have currently:
function tester() {
$("select#type").attr('disabled', 'disabled');
$("select#cat").change(function(){
var vid = $("select#cat option:selected").attr('value');
var request = $.ajax({
url: "show_type.php",
type: "POST",
data: {id : vid}
});
request.done(function(msg) {
$("#result").html( msg );
});
request.fail(function(jqXHR, textStatus) {
alert( "Request failed: " + textStatus );
});
});
}
Don't mind the first section of the code with the select#type and select#cat as these are for what I was trying to get the code to populate at first, however the .change is my trigger for the .ajax request. The rest of the code I'm merely trying to dump a simple return message into an empty div#result upon a successful ajax request.
I ran a test, and the var vid populates correctly.
Here's the simple PHP file I'm trying to call with the ajax:
<?php
$requ;
if (isset($_POST['id'])) {
$requ = 'Worked';
} else {
$requ = "didn't work";
}
echo $requ;
?>
I thought perhaps the problem was the id wasn't being passed properly so I altered the PHP script to give me any valid output regardless of whether the $_POST was set or not.
I won't post the HTML as I'm just trying to dump this all into a div while I test it. When I run the script I get the 'Request Failed' error message with a message of "error".
Here is the other jquery & PHP I have also tried, using the .post instead of the .ajax:
function tester() {
$("select#type").attr('disabled', 'disabled');
$("select#cat").change(function(){
$("select#type").html("<option>wait...</option>");
var vid = $("select#cat option:selected").attr('value');
$.post("show_type.php", {id:vid}, function(data){
$("#result").empty().append(data);
}, "json");
});
}
And the PHP to accompany this particular jquery:
$requ = $_POST['id'];
$ret = 'You selected: ' . $requ;
echo json_encode($ret);
Again, it all failed. I also tried the above code without using the json encoding/parameters. All I want to do is a simple (so I would think) cascading select dropboxes. The second box to be dependent of the first boxes selection. I'm beginning to think that this all just may not be worth it and just sticking strictly to PHP with links to resubmit the page with a GET and populate a new section or div with the results of the first click. Any help or suggestions you might have would be greatly appreciated, I've spent 2 solid days trying to figure this all out. Thanks in advance
Alright, I got it fixed. Thanks to Mian_Khurram_ljaz for making me take a different look at the hierarchical structure of the file. I was assuming that since the js was calling the php file, by placing the php file in the same folder as the js, I could call the php by using the url: show_type.php but that was actually wrong. The structure is considered from the actual page invoking the js and php, and therefore the url should have been js/show_type.php since I had the show_type.php file in my js folder.
It's always the little mistakes that take you days to figure. For those in the future looking to find decent code for cascading select drop boxes, here is my functioning and fully expanded code (which also includes a tri-level cascade)
jQuery:
function project() {
$("select#model2").attr('disabled', 'disabled');
$("select#brand2").attr('disabled', 'disabled');
$("select#project").change(function(){
$("select#model2").attr('disabled', 'disabled'); // if changed after last element has been selected, will reset last boxes choice to default
$("select#model2").html('<option selected="selected">Choose...</option>');
$("select#brand2").html("<option>Please wait...</option>");
var pid = $("select#project option:selected").attr('value');
$.post("handler/project.php", {id:pid}, function(data){
$("select#brand2").removeAttr("disabled");
$("select#brand2").html(data);
});
});
$("select#brand2").change(function(){
$("select#model2").html("<option>Please wait...</option>");
var bid = $("select#brand2 option:selected").attr('value');
var pid = $("select#project option:selected").attr('value');
$.post("handler/projBrand.php", {proj: pid, bran: bid}, function(data){
$("select#model2").removeAttr("disabled");
$("select#model2").html(data);
});
});
}
Just call the function in the $(document).ready of your js.
Notice the comment, having this 'redundant' call to disable and force the last box to select the default is just in case the user makes a selection in all 3 boxes but goes back to the first box and changes the selection.
Here is the php handler file:
<?php
include_once('../includes/file.inc');
$request = $opt -> getModelvBrand();
echo $request;
?>
The other handler file for the jQuery is nearly exactly the same, only invoking a different method in the class file.
And lastly, the HTML:
<form action="" method="post">
<select id="project">
<option value="0">Choose...</option>
<?php echo $opt -> getProject();?> //populates first box on page load
</select>
<select id="brand2">
<option value="0">Choose...</option>
</select>
<select id="model2">
<option value="0">Choose...</option>
</select>
<br /><br />
<input class="like-button" type="submit" title="Submit" value="" />
</form>
Thanks again Mian for making me take a different look at my file(s).
Hope this code helps someone else in the near future.