I want to pass multiple parameters through GET method in URL of ajax call but its not working.any kind help would be appreciated Thankyou
$.ajax({
type: "GET",
contentType: "text/xml",
dataType: 'json',
async:true,
cache: false,
headers:{ 'Access-Control-Allow-Origin': '*'},
iurl: "http://maps.googleapis.com/maps/api/distancematrix/xml?origins="+dest_lat+"&"+dest_lon+"|"+data[i][3]+"&"+data[i][4],
success: function(msg) {
alert(msg);
}
});
Related
I want to fetch some data using ajax request in Opencart Admin panel. I have simply created a controller which only returns data in json format. Using below code:
$.ajax({
type: 'post',
url: 'index.php?route=common/ajaxdata/functionName&token=<?php echo $token; ?>',
data: data,
dataType: 'json',
success: function(json) {
if (json['success']) {
alert(json['success']);
}
}
});
Can anybody please let know whether this is correct or any other built in functionality available in Opencart for ajax requests? So that I can proceed and implement this in my rest of the pages.
Thanks
$.ajax({
type: "POST",
url: "http://your url write hare",
contentType: "application/json",
dataType: "json",
data: JSON.stringify({
"propertytypename": property,
"propertytypecreatedby": property_name
}),
success: alert("success"),
error: alert("Fail")
});
I want to retrieve parameter passes from ajax in Controller in Codeigniter but did not know how to use it my ajax function is below
function sendVideoData(frm_id)
{
var data = new FormData(document.getElementById("post_video_"+frm_id));
// make the AJAX request
jQuery.ajax({
type: "POST",
url: "<?php echo base_url(); ?>"+"dashboard/do_upload",
data: data+'&form_id='+frm_id,
mimeType:"multipart/form-data",
contentType: false,
cache: false,
processData:false,
dataType: 'json',
success: function (data) {
alert(data);
},
});
return false;
}
</script>
I want to retrieve
form_id
in my controller and use it
It's pretty simple,
echo $this->input->post('form_id')
or simple php
echo $_POST['form_id']
inside your controller dashboard and method do_upload
You can get all list of post variables using print_r($this->input->post()) as well.
Your AJAX request can be:
jQuery.ajax({
type: "POST",
url: "<?php echo base_url() ?>dashboard/do_upload",
data: 'form_id=' + frm_id + '&data=' + data,
mimeType: "multipart/form-data",
contentType: false,
cache: false,
processData:false,
dataType: 'json',
success: function (data) {
alert(data);
},
});
And in ur controller: $this->input->post('form_id');
I am noob at using jquery and ajax. I need to change the form from $.post to $.ajax .
var disqus_config = function() {
this.callbacks.onNewComment = [function(comment) {
$.post("sendnotification", { comment: comment.id, post: $post->id,author:$author->id}, function(result){
alert(result);
});
}];
};
I know I need to end something like here but I am stuck how to use post datas(comment,post,author) inside this function
$.ajax({
url: 'sendnotification',
type: 'POST',
data: 'query=' + query ,
dataType: 'JSON',
async: true,
success: function(data){
process(data)
}
Thanks
Just use the same object literal you did for $.post, eg (gotta assume that's some PHP or something in there)
$.ajax({
url: 'sendnotification',
type: 'POST',
data: { comment: comment.id, post: {$post->id}, author: {$author->id} },
dataType: 'json',
async: true,
success: function(data){
process(data)
}
});
I believe dataType: 'JSON' should be changed to dataType: 'json'
Also, use the same data array as you used in your $.post variant.
$.ajax({
url: 'sendnotification',
type: 'POST',
data: { comment: comment.id, post: $post->id,author:$author->id } ,
dataType: 'json',
async: true,
success: function(data){
process(data)
}
});
I am attempting to get our knockout form to submit to a php script and am getting undefinedIndex errors. I am pretty sure it is the way we are sending the data over in our ajax function.
Here is the ajax:
$.ajax({
url: '/orders/add',
type: 'post',
data: {payload:ko.toJSON(allModel)},
contentType: 'application/json',
success: function (result) {
alert(result);
}
});
Here is the PHP (we use laravel)
return json_decode($_POST["payload"]);
Pete is correct. You need to use just one data field. If you want a variable, define it before the $.ajax post
var dataPayload = ko.toJSON(allModel);
$.ajax({
url: '/orders/add',
type: 'post',
data: {payload: dataPayload},
contentType: 'application/json',
success: function (result) {
alert(result);
}
});
All,
I want to send a variable "itemId" via GET to a controller action through AJAX. In the Controller Action, I should be able to retrieve the value using $_GET["itemId"];
Can I send the querystring with "data" tag instead of appending it to the "url"?
I have the following code:
$.ajax({
type: 'GET',
url: "/controller/controlleraction",
data: itemId,
cache: false,
dataType: "html",
success: function(html_input)
{
alert(html_input);
}
});
How can I do this?
data: {itemId: itemId},
$.ajax({
type: 'GET',
url: "/controller/controlleraction",
data: ({itemId: itemId}),<------change it to this
cache: false,
dataType: "html",
success: function(html_input)
{
alert(html_input);
}
});
Make itemId a JavaScript object before making the AJAX request. For example:
var itemId = {'itemId': 1000};
data: {itemId: "you info"},
or
data: "itemId=you info",