how to use like operator in array laravel 5.2? - php

I want to add Like operator in array but it gives me error:
Unknown column '0' in 'where clause (admin_id = 2 and 0 = name and Like = %zdgbdsh%) order by id asc limit 10 offset 0)
Here is my query:-
$conditions = array();
if(!empty($data['name'])) {
$conditions = array_merge($conditions,array('name','Like'=>'%'.$data['name'].'%'));
}
And here is my final query:-
$querys = DB::table('users')
->where($conditions)
->skip($iDisplayStart)->take($iDisplayLength)
->OrderBy($orderby,$dir)
->get();
Note: I don't want directly in query like
where('users.name','like','%'.$data['name'].'%');**
I want to do in conditions variable
I am using laravel framework 5.2

It should be:
$conditions=array_merge($conditions,array('name' => 'Like %'.$data['name'].'%'));
Update
I've just realised that will produce name = Like %data%
You can change it to:
$conditions=array_merge($conditions,array('name', '%'.$data['name'].'%'));
and in where use:
->where(join(' LIKE ', $conditions))

This is not the greatest way of applying multiple conditions, But you can always user the whereRaw
so loop through a array with your conditions eg.
$conditions = [];
if (!empty($data['name'])) {
$conditions = array_merge(
$conditions,
["name LIKE '%".$data['name']."%'"]
);
}
$query = DB::table('users');
// apply add raw conditions
foreach($conditions as $condition){ $query->whereRaw($condition); }
$query->skip($iDisplayStart)->take($iDisplayLength)
->OrderBy($orderby,$dir)
->get();
you could also find some packages that will help you out with things like this.
Hope it helps

Related

Multiple where conditions with 'AND' & 'OR' operators in laravel

in my laravel controller i'm trying to perform the following query for the user search.
$data = User::orderBy('id','DESC')
->where('email','LIKE','%'.$request->search."%")
->orwhere('first_name','LIKE','%'.$request->search."%")
->orwhere('last_name','LIKE','%'.$request->search."%")
->WHERE('role_id','=','3')
->paginate(12);
return view('admins.participants.results',compact('data'))
->with('i', ($request->input('page', 1) - 1) * 12 );
What I really want to perform is,
SELECT * FROM USERS WHERE role_id='3' AND email LIKE '%search_string%' OR first_name LIKE '%search_string%' OR last_name LIKE '%search_string%' ;
But the above laravel query outputs all the users without considering the `role_id=3
You can use where callback
$data = User::orderBy('id','DESC')
->where('role_id',3)
->where(function($query)use($request){
$query->where('email','LIKE','%'.$request->search."%");
$query->orwhere('first_name','LIKE','%'.$request->search."%");
$query->orwhere('last_name','LIKE','%'.$request->search."%");
})->paginate(12);
also you can change
'%'.$request->search."%"
to
"%{$request->search}%"
You need to pass OR clauses to a Closure to group them, otherwise the query doesn't really understand which clauses are optional and which are not.
$data = User::orderBy('id','DESC')
->where('role_id','=','3')
->where(function($query) use ($request) {
$query->where('email','LIKE','%'.$request->search."%")
->orwhere('first_name','LIKE','%'.$request->search."%")
->orwhere('last_name','LIKE','%'.$request->search."%");
})
->paginate(12);

Laravel multiple count in 1 Query

Im new to this Framework, i dont know how to optimize it using db::raw count and aliases and display it to my blade.php using #foreach
im trying to optimize my code, my goals is to count pallet_conditions and store it to my aliases, i dont want to count it one by one like what i did on this code
this is my code not optimize:
//computing the total rapairable
$repairable_total = DB::table('liip_psrm_items')
->where('psrm_items_id', '=' , $psrm_maintenance->id)
->where('pallet_condition', '=', 1)
->count();
//REPAIRABLE
//computing the total good pallets
$good_total = DB::table('liip_psrm_items')
->where('psrm_items_id', '=' , $psrm_maintenance->id)
->where('pallet_condition', '=', 0)
->count();
//GOOD
this is the code, what i wanted to learn. just to minimize, and use aliases
$result = DB::table('liip_psrm_items')
->select(DB::raw('COUNT(liip_psrm_items.pallet_condition = 0 ) AS condition_1',
'COUNT(liip_psrm_items.pallet_condition = 1 ) AS condition_2'))
->where('psrm_items_id', '=' , $psrm_maintenance->id)
->get();
You can't use single query for two different results, which has totally opposite conditions.
Case 1. You are trying to count the items where pallet_condition = 1;
Case 2. You are trying to count the items where pallet_condition = 0;
Now you want to merge these two cases into single query, which is impossible...
So, For these two cases, you have to use either separate queries ( what you did already )
or you can use single query to grab all the items and then use PHP to separate them.
Like:
$total_items = DB::table('liip_psrm_items')
->where('psrm_items_id', '=' , $psrm_maintenance->id)
->get();
$repairable_count = count(array_filter($total_items, function($item){
return (bool)$item->pallet_condition;
}));
$good_count = count(array_filter($total_items, function($item){
return !(bool)$item->pallet_condition; //just inverse of the above condition
}));
i hope this might help.
To count at multiple condition I used this approach
$lastMonthInvoices = Invoice::select(DB::raw("(COUNT(*)) as count"), DB::raw('SUM(total) as total'),'status')
->whereDate('created_at', '>', Carbon::now()->subMonth())
->groupBy('status')
->get();
i got the result with groupBy Status and in each group total number of records as count & also their sum as total
these two snaps are of one query result
You can, first group by, then get count
Like :
DB::table('liip_psrm_items')
->groupBy('pallet_condition')
->select('pallet_condition', DB::raw('count(*) as total'))
->get();
Try to pass a closure like so:
$results = DB::table('liip_psrm_items')
->where('psrm_items_id', '=' , $psrm_maintenance->id)
->where(function($query){
$query->where('pallet_condition', 1)
->orWhere('pallet_condition', 0);
})->count();

Laravel change relationship where clause if not rows are returned

I have the following query in my controller.
$items = Item::with(['subitems' => function($query) {
$query->where('language_id', '=', 1);
}])->get();
This is correctly getting me all items including subitems that have a language id of 1.
There are two things I would like to do with this though
Firstly, I need to return all subitems that have a distinct 'ref_id' value.
Secondly, I would like to give preference to the language id 1 but if none exist, use any language id.
So for example, I know this code won't work, but the sort of thing I am looking for is:
$items = Item::with(['subitems' => function($query) {
$subItems = $query->where('language_id', '=', 1)
->where('ref_id', 'is', 'distinct');
if($subItems->count() <= 0) {
$subItems = $query->where('ref_id', 'is', 'distinct');
}
}])->get();
Is this possible or is it a bit too complicated for Query Builder? Even if one of the two requests was possible, that would be great.
Try this:
$items = Item::with(['subitems' => function($query) {
$join = Subitem::select('ref_id', DB::raw('MIN(language_id) language_id'))
->groupBy('ref_id');
$sql = '(' . $join->toSql() . ') subitems_distinct';
$query->join(DB::raw($sql), function($join) {
$join->on('subitems.ref_id', 'subitems_distinct.ref_id')
->on('subitems.language_id', 'subitems_distinct.language_id');
});
}])->get();
We can use the fact that your preferred language_id is the lowest value and select the minimum.

Get all elements of array in query laravel

I am trying to loop in an array but when it comes to the query it gets only the first element, so a little help would be very important.
$data = Offers::whereIn('id_business', $business_id_array)
->where([
'visible' => 'yes',
'delete' => 'no'
])
->where('end_date', '>=', date('Y-m-d h:m:i'))
->orderBy('id', 'desc')
->get();
$data=array($data);
foreach($data as $key => $item) {
$offers = DB::select('the data i need to get WHERE o.`id` = ' . $item[$key]['id']);
}
and this is my problem in here, It gets only the id of the first element
o.`id` = ' . $item[$key]['id']
because you have return the view in side the foreach loop, so it only loop through the first item and return. What you can do with this case is
$data = Offers::whereIn('id_business', $business_id_array)...->get()->toArray();
$offers = array_map(function($item){
$offer = DB::select('the data i need to get WHERE o.`id` = ?', [$item->id]);
return $offer;
},$data);
return view(....,['offers' =>$offers]);
First, you do not need to cast the $data to an array - it will get returned as a collection, which you can iterate through like an array. So you'll be able to use something like this
$offers = Offers::whereIn('id_business', $business_id_array)...->get();
foreach ($offers as $offer) {
$moreData = DB::select('the data i need to get WHERE o.`id` = ?', [$offer->id]);
}
This looks like you are using the id from one table, to get the associated data from another table.
Should there not be a relationship in place, between the two tables?
The answer from #Chris G looks correct, maybe dd($offers) to be certain what is in there.
Mick

Using array as a condition in where clause codeigniter

I have the problems using the array input as a value in WHERE clause.
But don't want to use more than once in WHERE clause code.
In my case, this is what I want :
$cond = array('job_id' => $job_id_var, 'job_name' => $job_name_var);
//WHERE clause
$this->where($cond); //only using once WHERE clause code like this, array as input
//which means
WHERE job_id = '$job_id_var' AND job_name = '$job_name_var'
is it possible to do that in codeigniter?
Yes, the ->where() method can support that.
Since you do not want to cascade it:
$this->db->where('job_id', $job_id_var);
$this->db->where('job_name', $job_name_var);
->where() can handle array input as well:
$cond = array('job_id'=>$job_id_var, 'job_name'=>$job_name_var);
$this->db->where($cond); // here, only used once.
$query = $this->db->get('hello_table');
$result = $query->result_array();
return $result;

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