how to get all values into a single variable from query? - php

Question

I want to display all the values present in ftext field i want to
display all values into single variable like $spd.
When i print this variable $spd it displays only one (ftext)value.but ftext
contains multiple values.
so please help me how to display all values using $spd variable
Thanks in advance...!
$query = mysqli_query($link, "SELECT id, ftext from projectfield");
while($row = mysqli_fetch_array($query))
{
$spd = $row['ftext'];
}

Answer 1

Every time variable updates so it contains only last values. Below approaches resolve it:-
#Either print all values
$query = mysqli_query($link, "SELECT id, ftext from projectfield");
while($row = mysqli_fetch_array($query)){
echo $spd = $row['ftext'];
}
or
# or hold ftext in array and then use this
$spd = array();
$query = mysqli_query($link, "SELECT id, ftext from projectfield");
while($row = mysqli_fetch_array($query)){
$spd[] = $row['ftext'];
}
foreach($spd as $val){
echo $val;
}

Answer 2

you can use id as index
$spd = array();
$query = mysqli_query($link, "SELECT id, ftext from projectfield");
while($row = mysqli_fetch_array($query)){
$spd[$row['id']] = $row['ftext'];
}
foreach($spd as $key =>$value){
echo $key." ".$value;
}

Answer 3

You are getting a single value because you are running a loop on the row that came out in the query. and saving it in the $spd. so only the last ftext is saved as all other are rewritten every time the loop runs.
What you can do is append the data to $spd with a delimiter instead of assigning it.
$query = mysqli_query($link, "SELECT id, ftext from projectfield");
while($row =mysqli_fetch_array($query)){
$spd .= $row['ftext'].",";
}
and echo it.