is it possible in php loop without nested loop [closed] - php

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I want to print like this using loop without nested loop:
1
2 3
4 5 6 7
8 9 10 11 12 13 14 15
first line start from 1 and print only one integer
second line start from 2 and print two integer
third line start from 4 and print four integer
fourth line start from 8 and print eight integer
(same condition in other line if exist)

Answer 1

A pair of counters should do the trick;
$threshold = 1;
$x = 1;
for($i = 1; $i <= 15; $i++) {
echo $i . ' ';
if($x == $threshold) {
echo "<br>\n";
$threshold = $threshold * 2;
$x = 0;
}
$x++;
}
Will keep on working till infinity, or your script runs out of memory. Whatever comes first :)

Answer 2

You can achieve with single while and some array functions. Try this.
<?php
$start=1;
while($start<=10){
$array = range($start,($start+$start-1));
echo implode(' ',$array)."<br>";
$start=$start*2;
}
?>

Answer 3

something like this?
$i=1;
$t=1;
while($i<1000)
{
if($i==$t)
{
if($t!=1) echo "<br />";
$t=$t*2;
}
echo $i." ";
$i++;
}

Answer 4

same thing but with log($i,2).
<?php
$i=1;
while($i<20)
{
echo $i;
$i++;
if(filter_var(log($i,2), FILTER_VALIDATE_INT))
echo PHP_EOL;
else
echo "\t";
}

Answer 5

You can even do it without any for and some recursion ;-)
<?php
$elements = range(1,15);
display($elements);
function display(array $parts, $step = 1) {
if(! count($parts)) {
return;
}
$elements = array_splice($parts, 0, $step);
echo implode("\t", $elements)."\n";
display($parts, $step * 2);
}
See the working code on https://eval.in/755277