I am trying to check and see if the user has inputted something inside of the HTML page by using PHP and for some reason nothing is coming up on my screen when I test it.
...
<form>
<label for="age">Enter your age: </label>
<input type="text" name="age" id="age">
</br></br>
<input type="button" name="submit" id="submit" value="submit">
</form>
</body>
<?php
$theAge;
if(isset($_GET["submit"])){
$theAge = $_GET["age"];
if($theAge == "")
{
echo("<p>Please enter an age</p>");
}
?>
</html>
Your input type should be submit and not button.
<html>
<script src="https://code.jquery.com/jquery-3.2.0.min.js"></script>
<body>
<form>
<label for="age">Enter your age: </label>
<input type="text" name="age" id="age">
</br></br>
<input type="submit" name="submit" id="submit" value="submit">
</form>
</body>
</html>
First off, you're not setting a method on the form, and your check is redundant and not really working either. First off, you need to decide if you want GET or POST. Here's a version using POST:
<form method="POST" action="#">
<label for="age">Enter your age: </label>
<input type="text" name="age" id="age">
<input type="button" name="submit" id="submit" value="submit">
</form>
<?php
if(isset($_POST['submit'])){
$theAge = $_POST['age'] ?? '';
if($theAge == '') {
echo('<p>Please enter an age</p>');
} else {
// do something here
}
?>
If you rather wanna use GET, just change the POST to GET in the code.
Note that his uses PHP 7.x notation - if you're using an older version of PHP (you shouldn't), then you'll have to change this line: $theAge = $_POST['age'] ?? ''; to $theAge = isset($_POST['age']) ? $_POST['age'] : '';
Related
I would like to store an user input from a textbox into an external php array by clicking a button. Also, there is a dependency from two radio buttons.
This is my current attempt:
At first, I include the external php array:
<?php
include ('../array.php');
?>
The input form:
<form action="" method="post">
<input type="text" name="textfield" id="txt1" value="">
<input type="radio" name="name" id="id" value="Type1">Type1<br>
<input type="radio" name="name" id="id" value="Type2">Type2<br>
<button id="submit" name="send" type="submit">Save</button>
</from>
Insert the value into the array:
<?php
if (isset($_POST['send'])){
if (isset ($_POST['name'])){
if ($_POST['name']=='Type1'){
$newword = $_POST['textfield'];
$array[] = $newword;
}
}
}
?>
But the values don't "stack", meaning that the array isn't growing with each button click.
Can anyone help please? :D
Thanks in advance!
If you want to stack values, you need to store them somewhere to keep values between each requests to server.
Values can be stored in session (for current user only) or in any database supported by PHP.
Here an example with session :
index.php :
<?php
include ('./array.php');
?>
<form action="" method="post">
<input type="text" name="textfield" value="">
<input type="radio" name="name" value="Type1">Type1<br>
<input type="radio" name="name" value="Type2">Type2<br>
<button id="submit" name="send" type="submit">Save</button>
</from>
array.php :
<?php
session_start();
if (!is_array($_SESSION['persistentValues'])) {
$_SESSION['persistentValues'] = array();
}
if (isset($_POST['send']) && isset($_POST['name']) && $_POST['name']=='Type1') {
$_SESSION['persistentValues'][] = $_POST['textfield'];
}
print_r($_SESSION['persistentValues']);
?>
<form action="" method="post">
<input type="text" name="textfield" id="txt1" value="">
<input type="radio" name="name" id="id" value="Type1">Type1<br>
<input type="radio" name="name" id="id" value="Type2">Type2<br>
<button id="submit" name="send" type="submit">Save</button>
</from>
in the file php put this
<?php
if (isset($_POST['send']) && $_POST['textfield'] && $_POST['name']){
if ($_POST['name']=='Type1'){
array = require('./array.php');
$newword = $_POST['textfield'];
$array[] = $newword;
}
}
?>
Id basically like the below submission to place text at the end of the url
example of what i want
http://example.com/(text) -- without the () obviously
example of what i don't want -- http://www.example.com/index.php?firstname=text
<form action="(end of current url)">
<fieldset>
search name
<br>
<input type="text" name="search" value="name">
<br>
<input type="submit" value="Submit"></fieldset>
</form>
id like to fix this via html or php either will do aslong as it submits the request to that :)
thank you in advance.
Using the POST method instead of GET.
<form action="" method="POST">
<fieldset>
search name
<br>
<input type="text" name="search" value="name">
<br>
<input type="submit" value="Submit"></fieldset>
</form>
In short you do the following:
<?php
// Get posted text
$text = strtolower(mysql_real_escape_string($_POST['text']));
// Do some cleanup here
// Redirect to page
if ($text != ''){
header( 'Location: http://www.example.com/' . $text );
}
// HTML output below (not before)
?>
<form method="post" action="">
<fieldset>
Search name<br />
<input type="text" name="text" /><br />
<input type="submit" value="Submit" />
</fieldset>
</form>
I am trying to find a basic input where user enters one number and the second number and then multiplies it.
I got it to work without the isset function, but now I am trying to echo out the error line when the page first starts up. If you see the input it is named, name and name2 so I call them in PHP.
My original code did not use isset and it worked but I got error before any input. This is my PHP code:
<html>
<style>
<?php include 'style.css';?>
</style>
<body>
<form method="post">
<p> Enter Value 1:<input type="text" name="name"> <br>
<p> Enter Value 2:<input type="text" name="name2"><br>
<input type="submit" value="send">
</form>
<br>
<h3>Your input:</h3><br>
<?php
if (isset($_POST['name'])) && (isset($_POST['name2'])){
$num=$_POST['name'];
$num2=$_POST['name2'];
echo $num*$num2;
}
else{
echo '';
}
?>
</body>
</html>
You have closed your IF parentheses too soon. The line should be like this:
if (isset($_POST['name']) && isset($_POST['name2'])) {
This is working code you have some extra parenthesis. If you are multiplying integer values from user always use intval function so that you always have integer value. If user enters string or characters it intval will change to zero
<html>
<style>
<?php include 'style.css';?>
</style>
<body>
<form method="post">
<p> Enter Value 1:<input type="text" name="name"> <br>
<p> Enter Value 2:<input type="text" name="name2"><br>
<input type="submit" value="send">
</form>
<br>
<h3>Your input:</h3><br>
<?php
if (isset($_POST['name']) && isset($_POST['name2'])){
$num = intval($_POST['name']);
$num2 = intval($_POST['name2']);
echo $num*$num2;
}
else{
echo '';
}
?>
Try this I think it is helpful to you:
<form method="POST">
<input type="text" name="value1" placeholder="Enter 1st Value" required>
<input type="text" name="multiply" value="*" readonly>
<input type="text" name="value2" placeholder="Enter 2nd Value" required>
<input type="submit" name="submit" value="Calculate">
</form>
<?php
if(isset($_POST['submit'])){
$value1 = $_POST['value1'];
$multiply = $_POST['multiply'];
$value2 = $_POST['value2'];
if($multiply == "*"){
echo $value1*$value2;
}
}
?>
The main problem is paranthesis are not closed properly it is
if(condition1)&& (condition2){
}
it should be
if((condition1)&&(condition2)){
}
you can use single condition for this also as shown in below code
<style>
<?php include 'style.css';?>
</style>
<body>
<form method="post">
<p> Enter Value 1:<input type="text" name="name"> <br>
<p> Enter Value 2:<input type="text" name="name2"><br>
<input type="submit" value="send" name="send">
</form>
<br>
<h3>Your input:</h3><br>
<?php
//if (isset($_POST['name'])) && (isset($_POST['name2'])){ problem is here your paranthesis are not closed properly
if (isset($_POST['send'])){ //use this as this will ensure that your send button is clicked for submitting form
$num=$_POST['name'];
$num2=$_POST['name2'];
echo $num*$num2;
}
else{
echo '';
}
?>
</body>
</html>
I want to place both register and login form on the same page.
They both starts with:
if (!empty($_POST)) ...
so, I need something like:
if (!empty($_POST_01))... // regForm
and
if (!empty($_POST_02))... //loginForm
Also how to prevent executing first form if the second is busy, and vice versa (user clicks on both)
My idea is to create a simple variable on starting process, for example $x = 1 and at the end of process $x = 0, so:
if ((!empty($_POST_01)) And $x = 0)...
Probably, there is a better way.
You could make two forms with 2 different actions
<form action="login.php" method="post">
<input type="text" name="user">
<input type="password" name="password">
<input type="submit" value="Login">
</form>
<br />
<form action="register.php" method="post">
<input type="text" name="user">
<input type="password" name="password">
<input type="submit" value="Register">
</form>
Or do this
<form action="doStuff.php" method="post">
<input type="text" name="user">
<input type="password" name="password">
<input type="hidden" name="action" value="login">
<input type="submit" value="Login">
</form>
<br />
<form action="doStuff.php" method="post">
<input type="text" name="user">
<input type="password" name="password">
<input type="hidden" name="action" value="register">
<input type="submit" value="Register">
</form>
Then you PHP file would work as a switch($_POST['action']) ... furthermore, they can't click on both links at the same time or make a simultaneous request, each submit is a separate request.
Your PHP would then go on with the switch logic or have different php files doing a login procedure then a registration procedure
Well you can have each form go to to a different page. (which is preferable)
Or have a different value for the a certain input and base posts on that:
switch($_POST['submit']) {
case 'login':
//...
break;
case 'register':
//...
break;
}
Give the submit buttons for both forms different names and use PHP to check which button has submitted data.
Form one button - btn1
Form two button -btn2
PHP Code:
if($_POST['btn1']){
//Login
}elseif($_POST['btn2']){
//Register
}
You can use this easiest method.
<form action="validator.php" method="post" id="form1">
<input type="text" name="user">
<input type="password" name="password">
<input type="submit" value="submit" form="form1">
</form>
<br />
<form action="validator.php" method="post" id="form2">
<input type="text" name="user">
<input type="password" name="password">
<input type="submit" value="submit" form="form2">
</form>
Here are two form with two submit button:
<form method="post" action="page.php">
<input type="submit" name="btnPostMe1" value="Confirm"/>
</form>
<form method="post" action="page.php">
<input type="submit" name="btnPostMe2" value="Confirm"/>
</form>
And here is your PHP code:
if (isset($_POST['btnPostMe1'])) { //your code 1 }
if (isset($_POST['btnPostMe2'])) { //your code 2 }
Hope this will help you. Assumed that login form has: username and password inputs.
if(isset($_POST['username']) && trim($_POST['username']) != "" && isset($_POST['password']) && trim($_POST['password']) != ""){
//login
} else {
//register
}
I'm trying to create a BMI calculator. This should allow people to use either metric or imperial measurements.
I realise that I could use hidden tags to solve my problem, but this has bugged me before so I thought I'd ask: I can use $_POST['variableName'] to find the submitted variableName field-value; but...I don't know, or see, how to verify which form was used to submit the variables.
My code's below (though I'm not sure it's strictly relevant to the question):
<?php
$bmiSubmitted = $_POST['bmiSubmitted'];
if (isset($bmiSubmitted)) {
$height = $_POST['height'];
$weight = $_POST['weight'];
$bmi = floor($weight/($height*$height));
?>
<ul id="bmi">
<li>Weight (in kilograms) is: <span><?php echo "$weight"; ?></span></li>
<li>Height (in metres) is: <span><?php echo "$height"; ?></span></li>
<li>Body mass index (BMI) is: <span><?php echo "$bmi"; ?></span></li>
</ul>
<?php
}
else {
?>
<div id="formSelector">
<ul>
<li>Metric</li>
<li>Imperial</li>
</ul>
<form name="met" id="metric" action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post" enctype="form/multipart">
<fieldset>
<label for="weight">Weight (<abbr title="Kilograms">kg</abbr>):</label>
<input type="text" name="weight" id="weight" />
<label for="height">Height (<abbr title="metres">m</abbr>):</label>
<input type="text" name="height" id="height" />
<input type="hidden" name="bmiSubmitted" id="bmiSubmitted" value="1" />
</fieldset>
<fieldset>
<input type="reset" id="reset" value="Clear" />
<input type="submit" id="submit" value="Submit" />
</fieldset>
</form>
<form name="imp" id="imperial" action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post" enctype="form/multipart">
<fieldset>
<label for="weight">Weight (<abbr title="Pounds">lbs</abbr>):</label>
<input type="text" name="weight" id="weight" />
<label for="height">Height (Inches):</label>
<input type="text" name="height" id="height" /
<input type="hidden" name="bmiSubmitted" id="bmiSubmitted" value="1" />
</fieldset>
<fieldset>
<input type="reset" id="reset" value="Clear" />
<input type="submit" id="submit" value="Submit" />
</fieldset>
</form>
<?php
}
?>
I verified that it worked (though without validation at the moment -I didn't want to crowd my question too much) with metric; I've added the form but not the processing for the imperial yet.
To identify the submitted form, you can use:
A hidden input field.
The name or value of the submit button.
The name of the form is not sent to the server as part of the POST data.
You can use code as follows:
<form name="myform" method="post" action="" enctype="multipart/form-data">
<input type="hidden" name="frmname" value=""/>
</form>
You can do it like this:
<input type="text" name="myform[login]">
<input type="password" name="myform[password]">
Check the posted values
if (isset($_POST['myform'])) {
$values = $_POST['myform'];
// $login = $values['login'];
// ...
}
The form name is not submitted. You should just add a hidden field to each form and call it a day.
In the form submitting button (id method of form is post):
<input type="submit" value="save" name="commentData">
In the PHP file:
if (isset($_POST['commentData'])){
// Code
}
For some reason, the name of the submit button is not passed to the superglobal $_POST when submitted with Ajax/jQuery.
Use a unique value on the submit button for each form like so
File index.html
<form method="post" action="bat/email.php">
<input type="text" name="firstName" placeholder="First name" required>
<input type="text" name="lastName" placeholder="Last name" required>
<button name="submit" type="submit" value="contact">Send Message</button>
</form>
<form method="post" action="bat/email.php">
<input type="text" name="firstName" placeholder="First name" required>
<input type="text" name="lastName" placeholder="Last name" required>
<button name="submit" type="submit" value="support">Send Message</button>
</form>
File email.php
<?php
if (isset($_POST["submit"])) {
switch ($_POST["submit"]) {
case "contact":
break;
case "support":
break;
default:
break;
}
}
?>
As petervandijck.com pointed out, this code may be susceptible to XSS attacks if you have it behind some kind of log-in system or have it embedded in other code.
To prevent an XSS attack, where you have written:
<?php echo "$weight"; ?>
You should write instead:
<?php echo htmlentities($weight); ?>
Which could even be better written as:
<?=htmlentities($weight); ?>
You can use GET in the form's action parameter, which I use whenever I make a login/register combined page.
For example: action="loginregister.php?whichform=loginform"
I had a similar problem which brought me to this question. I reviewed all the preceding answers, but ultimately I ending up figuring out my own solution:
<form name="ctc_form" id="ctc_form" action='' method='get'>
<input type="hidden" name="form_nm" id="form_nm">
<button type="submit" name="submit" id="submit" onclick="document.getElementById('form_nm').value=this.closest('form').name;">Submit</button>
</form>
It seamlessly and efficiently accomplishes the following:
Passes the form name attribute via a hidden input field, without using the fallible value attribute of the submit button.
Works with both GET and POST methods.
Requires no additional, independent JavaScript.
You could just give a name to the submit button and do what needs to be done based on that. I have several forms on a page and do just that. Pass the button name and then if button name = button name do something.
Only the names of the form fields are submitted, but the name of the form itself is not. But you can set a hidden field with the name in it.