I am making a golf leaderboard in which I take all the hole scores from a specific matchid and group them by the userid. This part works just fine.
I do so like this:
$playersArray = array();
$sql = "SELECT *, SUM(point) AS points, COUNT(*) AS holes, COUNT(*)*2-SUM(point) AS topar FROM fb_score WHERE matchid=$matchid GROUP BY userid";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()){
$playersArray[] = $row;
}
}
Now, my question is, is there a waythat I can create an array of all the "point" for each user and get that into the $row?
Lets say that the SUM(point) is summed by lets say 3 points (3, 5, 4). Can I get this out in the result. As it is now I only get the latest $row for each user, but with the added "points", "holes" and "topar".
Hope this question makes sense :-/
Any help is appreciated and thanks in advance :-)
May be a bit hacky but it works. Simply GROUP_CONCAT the values and you get them in your $row var and you will be able to explode them in an array.
select *, GROUP_CONCAT(CONVERT(point,CHAR)) as all_points from fb_score GROUP BY userid
Related
Basically, I am seeking to know if there is a better way to accomplish this specific task.
Basically, what happens is I query the db for a list of "project needs" -- These are each uniquer and only appear once.
Then, I search another table to find out how many members have the required "skills - which are directly correlated to the project needs".
I accomplished exactly what I was trying to do by running a second query and then inserting them into an array like this:
function countEachSkill(){
$return = array();
$query = "SELECT DISTINCT SKILL_ID, SKILL_NAME FROM PROJECT_NEEDS";
$result = mysql_query($query) or die(mysql_error());
$num_rows = mysql_num_rows($result);
while($row = mysql_fetch_assoc($result)){
$query = "SELECT COUNT(*) as COUNT FROM MEMBER_SKILLS WHERE SKILL_ID = '".$row['NEED_ID']."'";
$cResult = mysql_query($query);
$cRow = mysql_fetch_assoc($cResult);
$return[$row['SKILL_ID']]['Count'] = $cRow['COUNT'];
$return[$row['SKILL_ID']]['Name'] = $row['SKILL_NAME'];
}
arsort($return);
return $return;
}
But I feel like there has to be a better way (perhaps using some kind of join?) that would return this in a result set to avoid using the array.
Thanks in advance.
PS. I know mysql_ is depreciated. It is not my choice on which to use.
SELECT P.SKILL_ID, P.SKILL_NAME, COUNT(M.SKILL_ID) as COUNT FROM PROJECT_NEEDS P INNER JOIN MEMBER_SKILLS M
ON P.SKILL_ID=M.SKILL_ID
GROUP BY P.SKILL_ID, P.SKILL_NAME
I've adjusted Nriddens answer to accomodate for the select distinct, Im under the belief that his adjustment would be ok given SKILL_ID is a primary key
function countEachSkill(){
$return = array();
$query = "
SELECT
COUNT(*) AS COUNT,
PROJECT_NEEDS.SKILL_NAME,
PROJECT_NEEDS.SKILL_ID
FROM
(SELECT DISTINCT
SKILL_ID, SKILL_NAME
FROM
PROJECT_NEEDS) AS PROJECT_NEEDS
INNER JOIN
MEMBER_SKILLS
ON
MEMBER_SKILLS.SKILL_ID = PROJECT_NEEDS.SKILL_ID
GROUP BY PROJECT_NEEDS.SKILL_ID";
$result = mysql_query($query) or die(mysql_error());
$num_rows = mysql_num_rows($result);
while($row = mysql_fetch_assoc($result)){
$return[$row['SKILL_ID']]['Count'] = $row['COUNT'];
$return[$row['SKILL_ID']]['Name'] = $row['SKILL_NAME'];
}
arsort($return);
return $return;
I am subquerying on the select distinct because I dont believe you have a dedicated skills table with an auto inc primary key, if that was there I wouldn't be using a subquery.
Can you test this query
select project_needs.*,count(members_skills.*) as count from project_needs
inner join members_skills
on members_skills.skill_id=project_needs.skill_id Group by project_needs.skill_name, project_needs.skill_id
I was wondering if someone can help me with my problem that is as follows:
I want to pull once posts.text and uids which belongs to that posts.text but when I execute the code below it does this: eg. there are 4 uids that belongs to the post so I get the posts.text four times instead of once.
$query = mysqli_query($con,
"SELECT posts.text, relationships.uidb
FROM posts
LEFT JOIN relationships
ON posts.uid=relationships.uida
LIMIT 10");
if(mysqli_num_rows($query) > 0){
while($row = mysqli_fetch_assoc($query)){
echo $row['text']." ".$row['uidb']."<br>";
}
}
I would really appreciate any help.
Thanks is advance.
Peter
Update:
Desired output would be like this:
postsArray[0]->text = //post text
postsArray[1]->text = //another post text
postsArray[0]->uids[0] = //approved uid for first post
postsArray[0]->uids[1] = //another approved uid for first post
now it outputs this:
text 10
text 15
text 12
and I want this:
text 10, 15, 12
One way is to use Mysql's GROUP_CONCAT which provides comma separated values list for each group i.e (p.uid)
$query = mysqli_query($con,
"SELECT p.text, GROUP_CONCAT(r.uidb SEPARATOR ', ') uidbs
FROM posts p
LEFT JOIN relationships r
ON p.uid=r.uida
GROUP BY p.uid
LIMIT 10");
if (mysqli_num_rows($query) > 0) {
while ($row = mysqli_fetch_assoc($query)) {
echo $row['text'].' '.$row['uidbs'];
/*$uidbs= explode($row['uidbs'],',');
foreach ($uidbs as $key => $val) {
echo $val.' ';
}*/
echo '</br>';
}
}
GROUP_CONCAT
According to docs The result is truncated to the maximum length that
is given by the group_concat_max_len system variable, which has a
default value of 1024. The value can be set higher, although the
effective maximum length of the return value is constrained by the
value of max_allowed_packet.
Maybe this might work for you:
$query = mysqli_query($con,
"SELECT posts.text, relationships.uidb
FROM posts
LEFT JOIN relationships
ON posts.uid=relationships.uida
GROUP BY posts.uid
LIMIT 10");
if(mysqli_num_rows($query) > 0){
while($row = mysqli_fetch_assoc($query)){
echo $row['text']." ".$row['uidb']."<br>";
}
}
SELECT posts.text, relationships.uidb
FROM posts
LEFT JOIN relationships
ON posts.uid=relationships.uida
GROUP BY posts.primary_key_of_your_post
LIMIT 10
You should call 2 queries. In your first query, call the text, and then call uids.
You should not write complex queries because this will make your business more complex and you will not maintain your code in future.
I got a little problem, I've got a database, in that database are different names, id, and coins. I want to show people their rank, so your rank has to be 1 if you have the most coins, and 78172 as example when your number 78172 with coins.
I know I can do something like this:
SELECT `naam` , `coins`
FROM `gebruikers`
ORDER BY `coins` DESC
But how can I get the rank you are, in PHP :S ?
You can use a loop and a counter. The first row from MySql is going the first rank,I.e first in the list.
I presume you want something like:
1st - John Doe
2nd - Jane Doe
..
..
right?
See: http://www.if-not-true-then-false.com/2010/php-1st-2nd-3rd-4th-5th-6th-php-add-ordinal-number-suffix
Helped me a while ago.
You could use a new varariable
$i = "1";
pe care o poti folosi in structura ta foreach,while,for,repeat si o incrementezi mereu.
and you use it in structures like foreach,while,for,repeat and increment it
$i++;
this is the simplest way
No code samples above... so here it is in PHP
// Your SQL query above, with limits, in this case it starts from the 11th ranking (0 is the starting index) up to the 20th
$start = 10; // 0-based index
$page_size = 10;
$stmt = $pdo->query("SELECT `naam` , `coins` FROM `gebruikers` ORDER BY `coins` DESC LIMIT {$start}, {$page_size}");
$data = $stmt->fetchAll();
// In your template or whatever you use to output
foreach ($data as $rank => $row) {
// array index is 0-based, so add 1 and where you wanted to started to get rank
echo ($rank + 1 + $start) . ": {$row['naam']}<br />";
}
Note: I'm too lazy to put in a prepared statement, but please look it up and use prepared statements.
If you have a session table, you would pull the records from that, then use those values to get the coin values, and sort descending.
If we assume your Session table is sessions(session_id int not null auto_increment, user_id int not null, session_time,...) and we assume that only users who are logged in would have a session value, then your SQL would look something like this: (Note:I am assuming that you also have a user_id column on your gebruikers table)
SELECT g.*
FROM gebruikers as g, sessions as s WHERE s.user_id = g.user_id
ORDER BY g.coins DESC
You would then use a row iterator to loop through the results and display "1", "2", "3", etc. The short version of which would look like
//Connect to database using whatever method you like, I will assume mysql_connect()
$sql = "SELECT g.* FROM gebruikers as g, sessions as s WHERE s.user_id = g.user_id ORDER BY g.coins DESC";
$result = mysql_query($sql,$con); //Where $con is your mysql_connect() variable;
$i = 0;
while($row = mysql_fetch_assoc($result,$con)){
$row['rank'] = $i;
$i++;
//Whatever else you need to do;
}
EDIT
In messing around with a SQLFiddle found at http://sqlfiddle.com/#!2/8faa9/6
I came accross something that works there; I don't know if it will work when given in php, but I figured I would show it to you either way
SET #rank = 0; SELECT *,(#rank := #rank+1) as rank FROM something order by coins DESC
EDIT 2
This works in a php query from a file.
SELECT #rank:=#rank as rank,
g.*
FROM
(SELECT #rank:=0) as z,
gebruikers as g
ORDER BY coins DESC
If you want to get the rank of one specific user, you can do that in mysql directly by counting the number of users that have more coins that the user you want to rank:
SELECT COUNT(*)
FROM `gebruikers`
WHERE `coins` > (SELECT `coins` FROM `gebruikers` WHERE `naam` = :some_name)
(assuming a search by name)
Now the rank will be the count returned + 1.
Or you do SELECT COUNT(*) + 1 in mysql...
I'm struggling with a MYSQL query, when using COUNT and GROUP together it's excluding any rows that have a count of 0. I understand why this is happening but can't work out how to get around it. I've read up on potential solutions presented to those with a similar problem but I cannot see the link between the two that would allow me to solve it.
Can anybody help?
$query = "SELECT id, class_date, class_id, COUNT(*) AS reserve_count
FROM bookings
WHERE booking_status='#RESERVE#'
GROUP BY class_date, class_id
ORDER BY class_date ASC, class_id ASC" ;
$result = mysqli_query($sql,$query);
while($row = mysqli_fetch_assoc($result)) {
$bookings[$row['id']] = array('class_date' => $row['class_date'], 'class_id' => $row['class_id'], 'reserve_count' => $row['reserve_count']);
}
Logically, there shouldn't be any row with zero count because booking table should only have classes that are booked.
Hi i have such table information:
what i want to do with php with while or just in mysql, is to SUM (time_used) of the rows with status 44 until its reached row with status 55. after that it should begin from start with new summing.
first query should return 37, second 76 (keep in mind it should be universal, for unlimited occurrences of 55 status row)
i thought of a way with time/date filtering and have this:
select sum(time_used) as sumed
from timelog
where start_time > (select end_time from timelog where (status='55')
ORDER BY id DESC LIMIT 1) ORDER BY id DESC
but this works only for last combination of 44 and 55
i know i will need two way filtering( < end_time and > end_time) so it will work for all cases, but cant think of a way to do it in php
can anyone help me?
EDIT:
sqlfiddle whoever want it:
http://sqlfiddle.com/#!2/33820/2/0
There are two ways to do it: Plain SQL or PHP. If you treat thousands of rows, it may be interresting to choose between the two by testing performance.
Plain SQL
select project_id, task_id, user_id, sum(time_used) as time_used,
min(start_time) as start_time, max(end_time) as end_time, max(comment) as comment from
(select t.id, t.project_id, t.task_id, t.user_id, t.time_used,
count(t2.id) as count55, t.start_time, t.end_time, t.comment
from timelog t
left join timelog t2 on t.id>t2.id and t2.status=55 and t.task_id=t2.task_id
group by t.id) as t
group by count55;
I assume here that a task can belong to one user only
SQL and PHP
$link = mysqli_connect( ... );
$query = "select id, project_id, task_id, user_id, time_used, start_time, end_time, status
from timelog order by id";
$result = mysqli_query($link, $query);
$table = array();
$time_used = 0;
$start_sum = true;
$i = 0;
while($row = mysqli_fetch_assoc ($result)){
if($start_sum){
$table[$i] = $row;
$start_sum = false;
} else {
$table[$i]['time_used'] += $row['time_used'];
$table[$i]['end_time'] += $row['end_time'];
}
if($row['state'] == 55){
$i++;
$start_sum = true;
}
}
If two tasks can run in simultaneously, solution 1 will work, but solution 2 will need to be adapted in order to take this in account.
here is my intepretation:
http://sqlfiddle.com/#!2/33820/45
set #n=0;
select project_id, task_id, user_id,sum(time_used) from (
SELECT time_used,project_id, task_id, user_id,
#n:=if(status=55,#n+1,#n),
if(status=55,-1,#n) as grouper FROM timelog
) as t
where grouper>-1
group by grouper;
I'm neither a php nor MySQL programmer, but I can explain the logic you want to follow. You can then code it.
First, query your db and return the results to php.
Next, set two sum variables to 0.
Start looping through your query results. Increment the first sum variable until you reach the first row that has status 55. Once you do, start incrementing the second variable.
The tricky part will be to sort your query by the row number of the table. Here is a link that will help you with that part.