I have an external PHP, located on a hosting server. The app that I want to build is using Cordova, so I have a HTML on my phone local storage. I have a login form that POSTS to that external php the name and the password of the user. I want that when I click on submit, to stay on my current page, and display the values recieved by the PHP below the form, in a <p> or <h1> tag.
I will be grateful if you can help me with this.
You can make use of Ajax to get the content/data to your view from an external file.
You will need jQuery to use $.ajax().
//Get form Data
var form_data = $('#form').serialize();
$.ajax({
url:'http://something.com/dosomthing.php',
type:'POST',
data: form_data,
success:function(data){
// See what data was returned
console.log(data);
if(data.success == "1"){
$('#err-element').html("User Authenticated");
// Fade in new Page
}else{
$('#err-element').html("User Not found");
}
}
});
It is good practice to return a JSON object from your back-end.
if($user_matches){
echo json_encode(["success"=>"1", "OtherInfo"=>"Kitty"]);
}
post the data to the same page using query or something, use post or get variable to store it in a variable and append with javascript.
//post using query
$.ajax({
type: "POST",
data:{ whatyouwant: yourdata }
})
//in php
$data = $_GET['whatyouwant'];
//in javascript
data = '<?php echo $data;?>'; // if it's a string or you can use json_encode for arrays and such
$('#targetDiv').html('<p>'+data+'</p>');
Related
I've read all the articles but cant seem to get my ajax response into a PHP variable. Please can you advice. I want to assign rowid to a PHP variable.
$(document).on('click', '#updateid', function() {
var vallab = $('#idval').val();
var rowid;
$.ajax({
url:'a.php',
type: 'POST',
async: false,
data: {labid: vallab},
success: function(data){
// console.log(data);
rowid = data;
}
});
console.log(rowid);
return rowid;
});
my a.php code is below
<?php
# Fetch the variable if it's set.
$lab_id = (isset($_POST["labid"])) ? $_POST["labid"] : null;
echo $lab_id;
?>
I am getting the response back with the id, and want to use it on that page
I want to pass rowid into a PHP function so I need to get the value of rowid.
Please can you advice?
I cant seem to get my ajax response into a PHP variable
Well, the AJAX response came FROM a PHP file, right? So why don't you do whatever you need to do with the response right in that PHP file?
$.ajax({
url:'THIS IS YOUR PHP FILE',
type: 'POST',
data: {THIS IS THE DATA YOU SEND TO PHP},
success: function(data){
console.log(data); //THIS IS THE RESPONSE YOU GET BACK
}
});
You can't use it. Javascript is a scripting language which run in browser when the dom is loaded and elements are visible.
PHP is a serverside language and run on server before the page is loaded.
You need to understand the lifecycle of your application. Your php code executes once, it runs the full script from top to bottom when the page loads. At the point the script starts if can only access the post that came with the request (e.g if you clicked submit on a form then the 'action' of the form receives the post). Any number of things can happen in your script, but once it's finished the php is gone, and so is the post (in basic terms). So you no longer have any access to the php which created this page.
Ajax allows you to update a section of your page - it sends a request to your sever and runs some php code - you must understand that this is a new and separate request, so the new post submission only exists in the lifecycle of this new execution and is in now way linked to the page that has already finished loading. Now you could ask Ajax to call your original script, but that wouldn't affect your page at all because the page does not reload. What you would get is a strange looking response which you (probably) couldn't do anything useful with.
Ajax allows small specific changes to the page, so when you get your response (which I assume you get in a format you want since you don't ask about it and you have a console.log) you then need to do something with jQuery/javascript. Instead of returning rowid write a javascript function like :
function printRowId(rowid) {
$('#your html div id here').text('Row id is ' + rowid);
}
and then call it in your response:
$.ajax({
url:'a.php',
type: 'POST',
async: false,
data: {labid: vallab},
success: function(data){
// console.log(data);
rowid = data;
}
});
printRowId(rowid);
return rowid;
You can use Ajax to update your data, update your database and then reflect the changes on the current page, but you cannot use it to pass directly to the php that has already finished executing
just wondering how i save the value from the "var vname" to "$data" so that i can use the value in my php. Assuming this is pretty easy, but i'm new to this :P
<script id="source" language="javascript" type="text/javascript">
//Call the yourAjaxCall() function every 1000 millisecond
setInterval("yourAjaxCall()",1000);
function yourAjaxCall()
{
//-----------------------------------------------------------------------
// 2) Send a http request with AJAX http://api.jquery.com/jQuery.ajax/
//-----------------------------------------------------------------------
$.ajax({
url: 'api.php', //the script to call to get data
data: "", //you can insert url argumnets here to pass to api.php
//for example "id=5&parent=6"
dataType: 'json', //data format
success: function(data) //on recieve of reply
{
var id = data[0]; //get id
var vname = data[1]; //get name
$data = vname; //HOW AND WHERE??????? :P
}
});
};
</script>
/EDIT - want my var vname which is a color, to be placed in the style.
<body>
<div id="kvadrat1" style="width:200px; height:200px; position:relative; background-color:'HERE I WANT MY VALUE'">
</div>
Greatful for quick answers! :)
Seems to me like you're just trying to fetch a name and an ID, but can't imagine why you'd need to do that every 1000 milliseconds - just seems like a lot of requests for data that isn't going to change?
Personally I'd just suggest making the API call in your PHP before the page loads and you can var name = "<?=echo $name?>"; as avalkab has said in order to access the variables in JavaScript after the page has been loaded.
Should be able to use
$data = json_decode(file_get_contents("api.php?id=5&parent=6")); // Specify or build query however you intended
If you are waiting for the user to interact (onclick or something) to call your javascript then if you expect to use data retrieved by AJAX to change data on the whole page - you might just want to reload the page, or revise your AJAX to make use of the data returned?
EDIT:
Since you are trying to change a colour you can simply use this line with jQuery
$("#kvadrat1").css({"background-color": vname});
So your code would be like so:
//Call the yourAjaxCall() function every 1000 millisecond
setInterval("yourAjaxCall()",1000);
function yourAjaxCall() {
//-----------------------------------------------------------------------
// 2) Send a http request with AJAX http://api.jquery.com/jQuery.ajax/
//-----------------------------------------------------------------------
$.ajax({
url: 'api.php', //the script to call to get data
data: "", //you can insert url argumnets here to pass to api.php
//for example "id=5&parent=6"
dataType: 'json', //data format
success: function(data) //on recieve of reply
{
var id = data[0]; //get id
var vname = data[1]; //get name
$("#kvadrat1").css({"background-color" : vname});
}
});
};
Take a read here : Pass javascript variable to php with ajax and the result doesn't show anything
This will explain you to use javascript varaiables with PHP. Great answer from Zladuric.
You can not save it in php.
You can save it to HTML element
If you need it in php variable send it to other page using ajax or header redirection
PHP code is executed once when a page is loaded by the user. JS is executed while the user is on the page. This is why it is impossible to bind values generated by JS to PHP variables.
You cant use php code when page loaded or in js.
javascript works only browser base. php works only server before
loading page.
// you can
var name = "<?=echo $name?>";
//you CANT!
var name = "joe";
$name = name;
you can not store it in php rather than you can use any html element to store it
you can keep data in html element by using $("#id").html(data[0]);
I want to retrieve a value from a HTML selection drop-down and store it into a PHP variable. I'm sure this has to be done in AJAX, but I'm not sure on the details. Is it possible to get that value of the option field and store it into a PHP variable this way?
$("#files").change(function() {
$.ajax({
type: "POST",
url: "parse.html",
data: {$'files'= $(this).val()},
success: function(response) {
//lolwut?
}
});
});
I want to store it in a php variable $x is what I just labeled it. The selection is title files.
Thanks.
You're pretty close. The data portion of the AJAX call should contain a key/value pair. Example:
data: {selectVal : this.value},
Now on your PHP backend, you can retrieve the variable with:
$selectValue = $_POST['selectVal'];
Do with it what you want, and you can return whatever you want to the client-side as well with echo. Whatever you echo back can now be picked up in the AJAX success callback under your variable response.
Also, set your url to your PHP page url.
i am new to php and mysql.
How can i extract a VALUE from a JAVASCRIPT VARIABLE(i set) then send it to a PHP page that can read it and process it , the PHP will then insert the value into a table in MySQL database.
var A = "somevalue"
I have been researching but none of it give me a simple and direct answer . I saw some people uses JSON(which i am unfamiliar with) to do this.
Hopes someone can give me an example of the javascript/jquery , php code to this. Thanks!
You've asked for... a lot. But, this tutorial looks like it could help you.
(FYI -- I swapped out the original tutorial for one on ibm.com. It's better but far more wordy. The original tutorial can be found here)
I'm not pretty sure if it works but just try this. Your jQuery script shoul be like this:
$(function(){
var hello = "HELLO";
$.post(
"posthere.php",
{varhello: hello},
function(response){ alert(response); }
)
});
and "posthere.php" is like this:
$varhello = $_POST['varhello'];
echo $varhello . ' is posted!';
you should then get an alert box saying "HELLO is posted!"
What you need is Ajax. This is an example jQuery to use:
function sendData(data) {
$.ajax({
type: 'POST',
data: data,
url: "/some/url/which/gets/posts",
success: function(data) {
}
});
}
This will send post data to that url, in which you can use PHP to handle post data. Just like in forms.
If you have a form:
<form id="theformid">
<input type="text">
</form>
Then you can use jQuery to send the form submit data to that sendData function which then forwards it to the other page to handle. The return false stops the real form from submitting:
$("#theformid").submit(function(){
sendData($(this).serializeArray());
return false;
});
If you though want to send just a variable, you need to do it like this:
function sendData(data) {
$.ajax({
type: 'POST',
data: {somekey: data},
url: "/some/url/which/gets/posts",
success: function(data) {
}
});
}
Then when you are reading $_POST variable in PHP, you can read that data from $_POST['somekey'].
Inside the success callback function you can do something with the data that the page returns. The whole data that the page returns is in the data variable for you to use. You can use this for example to check whether the ajax call was valid or not or if you need to something specific with that return data then you can do that aswell.
I have a table that outputs all my contacts via a while loop from my database.
my syntax is like this:
SELECT * FROM contacts WHERE id = $_SESSION['user_id'] ORDER BY name ASC LIMIT 5
that pulls out all my data and only gives me 5 results.
Now my goal is to have a little button that opens up a model box with jquery (this I can manage on my own) with a form asking the user to input a number then that number will be sent via post or get to $PHP_SELF and update a local variable with the number the user inputed, then that variable will be used to update the database to increase or decrease the LIMIT value.
I have looked all over the web (with google) to look for submitting a form using AJAX but all the examples i've found don't work for me.
When the user submits the number and the sql query is executed and updated for the outputed table to dynamically update according to the new LIMIT value all without ever refreshing the page to the user.
my jquery code is:
(document).ready(function(){
$("form#form").submit(function() {
// we want to store the values from the form input box, then send via ajax below
var val = $('input[name=new_value]').attr('value');
$.ajax({
type: "post",
url: "process.php",
data: "val="+ val,
cache: false,
success: function(){
$('form#form').hide(function(){$('.success').fadeIn();});
}
});
return false;
});
});
$(document).ready(function(){ $("form#form").submit(function() {
// we want to store the values from the form input box, then send via ajax below
var val = $('input[name=new_value]').attr('value');
$.ajax({ type: "post", url: "process.php", data: "val="+ val, cache: false, success:
function(){
$('form#form').hide(function(){$('.success').fadeIn();});
} }); return false; }); });
then my php code is:
$new_val = $_POST['new_val'];
$_val = "UPDATE `settings` SET `display_limit` = {$new_val} WHERE `user_id` = {$_SESSION['user_id']}";
mysql_query($_val) or die(mysql_error());
and my form is simple:
any suggestions? I haven't come to how to have my outputed table dynamically update yet so if anyone can point me in the right direction or provide some help that would be awesome.
thanks
EDIT:
Here is an updated jquery script I was working on, I'm able to submit the form successfully! but my only problem is that I can't see the changes until the page is refreshed with defeats the purpose of the AJAX usage... sigh
how can I now have my #results div updated and refreshed with the form submission content?
$(document).ready(function() {
var options = {
url: 'process.php',
type: 'post',
//dataType: 'json',
target: '#last_five_sellers',
success: success
};
// bind to the form's submit event
$('#form').submit(function() {
// inside event callbacks 'this' is the DOM element so we first
// wrap it in a jQuery object and then invoke ajaxSubmit
$(this).ajaxSubmit(options);
// !!! Important !!!
// always return false to prevent standard browser submit and page navigation
return false;
});
function success(responseText, $form) {
$("form#form").hide();
$(".success").fadeIn();
}
});
In your php code where you do the update, You could echo your contacts in html-format. That would then return to your success function in jquery.
success: function(){
$('form#form').hide(function(){$('.success').fadeIn();});
}
The function have a parameter data, which is the html-format you echoed in php.
Example
success: function(data){
$('form#form').hide(function(){$('.success').fadeIn();});
$(data).appendTo('#result');
}
You need to understand the flow of a request. Once the php script runs, that is it, it is done. If you plan on submitting back to that same page, it'll be a new request and a new execution of that script. Now, you could add a special case to that script to return the necessary data to your jQuery code, but that's messy IMO. I would rather have a separate script to handle that functionality. This can be looked at as a web service.
So, when a you go to that page in a browser, it will intially display 5 contacts (or w/e the default you have in the LIMIT clause). When you click the icon to display more contacts, you employ jQuery to submit a GET request to that 'web service' page (it really should be GET, since you're retrieving data, not submitting new data). This would then be a list of contacts that you use to update the display on the page, using jQuery/JavaScript.
As noted by Codler, the output from that 'web service' can be HTML which you simply use to replace the existing HTML which displays the contacts. (This would be the preferred way. You almost always want do as much on the server as you reasonably can.)
It looks like your jQuery code is duplicated — there's no need to bind the form's submit event twice. Additionally, the first jQuery block is missing the opening dollar-sign ("$"). And as far as I know, .hide() does not support passing a callback through the first parameter. In the jQuery API documentation, it's written as .hide( duration, [ callback ] ).
I would write:
$(function(){
$("form#form").submit(function(){
// we want to store the values from the form input box, then send via ajax below
$.ajax({
type: "post",
url: "process.php",
data: "val=" + $("input[name=new_value]").val(),
cache: false,
success: function(){
$("form#form").hide();
$('.success').fadeIn();
}
});
return false;
});
});
Now, if you want to update your results table dynamically, the simplest way is just to replace the entire thing with the updated HTML. So for instance, if you modified your PHP script (process.php) so that, after updating display_limit, it outputted the new results table, you could then write something like (assuming your results table is table#results):
$(function(){
$("form#form").submit(function(){
// we want to store the values from the form input box, then send via ajax below
$.ajax({
type: "post",
url: "process.php",
data: "val=" + $("input[name=new_value]").val(),
cache: false,
success: function(data){
$("form#form").hide();
$(".success").fadeIn();
$("#results").replaceWith(data);
}
});
return false;
});
});
You just have to make sure your script only outputs HTML.
Contrary to what George answers above, HTML will definitely work for this purpose, but I think the ideal method is to send purely the data alone (minus structure/presentation) in either JSON or XML format, and then use JavaScript to build the HTML; you can save a lot of bandwidth this way, and ultimately build a much more responsive application.
EDIT
Here's a mini JSON-based example.
JavaScript:
$(function(){
$("#form").submit(function(){
var val = $("input[name=new_value]").val();
$.getJSON("process.php?val=" + val, function(data){
$("#results").empty();
$(data.rows).each(function(){
$("#results").append('<tr><td>' + this.column_a + '</td><td>' + this.columbn_b + '</td></tr>');
});
});
return false;
});
});
PHP (process.php):
[assuming you already have a result/rows called $result]
$json = array('rows' => array());
while ($row = mysql_fetch_assoc($result)) {
$json['rows'][] = $row;
}
echo json_encode($json);
Now, granted, I haven't tested this code at all, but it should give you the gist of it.