I want to retrieve the values from a database table and show them in a html table in a page.
I already searched for this but I couldn't find the answer, although this surely is something easy (this should be the basics of databases lol). I guess the terms I've searched are misleading.
The database table name is tickets, it has 6 fields right now (submission_id, formID, IP, name, email and message) but should have another field called ticket_number.
How can I get it to show all the values from the db in a html table like this:
<table border="1">
<tr>
<th>Submission ID</th>
<th>Form ID</th>
<th>IP</th>
<th>Name</th>
<th>E-mail</th>
<th>Message</th>
</tr>
<tr>
<td>123456789</td>
<td>12345</td>
<td>123.555.789</td>
<td>John Johnny</td>
<td>johnny#example.com</td>
<td>This is the message John sent you</td>
</tr>
</table>
And then all the other values below 'john'.
Example taken from W3Schools: PHP Select Data from MySQL
<?php
$con=mysqli_connect("example.com","peter","abc123","my_db");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$result = mysqli_query($con,"SELECT * FROM Persons");
echo "<table border='1'>
<tr>
<th>Firstname</th>
<th>Lastname</th>
</tr>";
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['FirstName'] . "</td>";
echo "<td>" . $row['LastName'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysqli_close($con);
?>
It's a good place to learn from!
Try this: (Completely Dynamic...)
<?php
$host = "localhost";
$user = "username_here";
$pass = "password_here";
$db_name = "database_name_here";
//create connection
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$connection = mysqli_connect($host, $user, $pass, $db_name);
//get results from database
$result = mysqli_query($connection, "SELECT * FROM products");
$all_property = array(); //declare an array for saving property
//showing property
echo '<table class="data-table">
<tr class="data-heading">'; //initialize table tag
while ($property = mysqli_fetch_field($result)) {
echo '<td>' . $property->name . '</td>'; //get field name for header
$all_property[] = $property->name; //save those to array
}
echo '</tr>'; //end tr tag
//showing all data
while ($row = mysqli_fetch_array($result)) {
echo "<tr>";
foreach ($all_property as $item) {
echo '<td>' . $row[$item] . '</td>'; //get items using property value
}
echo '</tr>';
}
echo "</table>";
Here is an easy way to fetch data from a MySQL database using PDO.
define("DB_HOST", "localhost"); // Using Constants
define("DB_USER", "YourUsername");
define("DB_PASS", "YourPassword");
define("DB_NAME", "Yourdbname");
$dbc = new PDO("mysql:host=".DB_HOST.";dbname=".DB_NAME.";charset-utf8mb4", DB_USER, DB_PASS);
$print = ""; // assign an empty string
$stmt = $dbc->query("SELECT * FROM tableName"); // fetch data
$stmt->setFetchMode(PDO::FETCH_OBJ);
$print .= '<table border="1px">';
$print .= '<tr><th>First name</th>';
$print .= '<th>Last name</th></tr>';
while ($names = $stmt->fetch()) { // loop and display data
$print .= '<tr>';
$print .= "<td>{$names->firstname}</td>";
$print .= "<td>{$names->lastname}</td>";
$print .= '</tr>';
}
$print .= "</table>";
echo $print;
Learn more about PHP and the MySQLi Library at PHP.net.
First, start a connection to the database. Do this by making all the string variables needed in order to connect, adjusting them to fit your environment, then creating a new connection object with new mysqli() and initializing it with the previously made variables as its parameters. Now, check the connection for errors and display a message whether any were found or not. Like this:
<?php
$servername = "localhost";
$username = "root";
$password = "yourPassword";
$database = "world";
mysqli_report(MYSQLI_REPORT_ERROR | MYSQLI_REPORT_STRICT);
$conn = new mysqli($servername, $username, $password, $database);
echo "Connected successfully<br>";
?>
Next, make a variable that will hold the query as a string, in this case its a select statement with a limit of 100 records to keep the list small. Then, we can execute it by calling the mysqli::query() function from our connection object. Now, it's time to display some data. Start by opening up a <table> tag through echo, then fetch one row at a time in the form of a numerical array with mysqli::fetch_row() which can then be displayed with a simple for loop. mysqli::field_count should be self explanatory. Don't forget to use <td></td> for each value, and also to open and close each row with echo"<tr>" and echo"</tr>. Finally we close the table, and the connection as well with mysqli::close().
<?php
$query = "select * from city limit 100;";
$queryResult = $conn->query($query);
echo "<table>";
while ($queryRow = $queryResult->fetch_row()) {
echo "<tr>";
for($i = 0; $i < $queryResult->field_count; $i++){
echo "<td>$queryRow[$i]</td>";
}
echo "</tr>";
}
echo "</table>";
$conn->close();
?>
First, connect to the database:
$conn=mysql_connect("hostname","username","password");
mysql_select_db("databasename",$conn);
You can use this to display a single record:
For example, if the URL was /index.php?sequence=123, the code below would select from the table, where the sequence = 123.
<?php
$sql="SELECT * from table where sequence = '".$_GET["sequence"]."' ";
$rs=mysql_query($sql,$conn) or die(mysql_error());
$result=mysql_fetch_array($rs);
echo '<table>
<tr>
<td>Forename</td>
<td>Surname</td>
</tr>
<tr>
<td>'.$result["forename"].'</td>
<td>'.$result["surname"].'</td>
</tr>
</table>';
?>
Or, if you want to list all values that match the criteria in a table:
<?php
echo '<table>
<tr>
<td>Forename</td>
<td>Surname</td>
</tr>';
$sql="SELECT * from table where sequence = '".$_GET["sequence"]."' ";
$rs=mysql_query($sql,$conn) or die(mysql_error());
while($result=mysql_fetch_array($rs))
{
echo '<tr>
<td>'.$result["forename"].'</td>
<td>'.$result["surname"].'</td>
</tr>';
}
echo '</table>';
?>
Surely a better solution would by dynamic so that it would work for any query without having to know the column names?
If so, try this (obviously the query should match your database):
// You'll need to put your db connection details in here.
$conn = new mysqli($server_hostname, $server_username, $server_password, $server_database);
// Run the query.
$result = $conn->query("SELECT * FROM table LIMIT 10");
// Get the result in to a more usable format.
$query = array();
while($query[] = mysqli_fetch_assoc($result));
array_pop($query);
// Output a dynamic table of the results with column headings.
echo '<table border="1">';
echo '<tr>';
foreach($query[0] as $key => $value) {
echo '<td>';
echo $key;
echo '</td>';
}
echo '</tr>';
foreach($query as $row) {
echo '<tr>';
foreach($row as $column) {
echo '<td>';
echo $column;
echo '</td>';
}
echo '</tr>';
}
echo '</table>';
Taken from here: https://www.antropy.co.uk/blog/handy-php-snippets/
mysql_connect("localhost","root","");
mysql_select_db("database");
$query=mysql_query("select * from studenti");
$x=#mysql_num_rows($query);
echo "<a href='file.html'>back</a>";
echo "<table>";
$y=mysql_num_fields($query);
echo "<tr>";
for($i=0 ,$i<$y,$i++)
{
$values=mysql_field_name($query,$i);
echo "<th>$values</th>";
}
echo "</tr>";
while(list($p ,$n $your_table_list)=mysql_fetch_row($query))
{
print("<tr>\n".
"<td>$p</td>".
"</tr>/n");
}
?>
<?php
$mysql_hostname = "localhost";
$mysql_user = "ram";
$mysql_password = "ram";
$mysql_database = "mydb";
$bd = mysql_connect($mysql_hostname, $mysql_user, $mysql_password) or die("Oops some thing went wrong");
mysql_select_db($mysql_database, $bd) or die("Oops some thing went wrong");// we are now connected to database
$result = mysql_query("SELECT * FROM users"); // selecting data through mysql_query()
echo '<table border=1px>'; // opening table tag
echo'<th>No</th><th>Username</th><th>Password</th><th>Email</th>'; //table headers
while($data = mysql_fetch_array($result))
{
// we are running a while loop to print all the rows in a table
echo'<tr>'; // printing table row
echo '<td>'.$data['id'].'</td><td>'.$data['username'].'</td><td>'.$data['password'].'</td><td>'.$data['email'].'</td>'; // we are looping all data to be printed till last row in the table
echo'</tr>'; // closing table row
}
echo '</table>'; //closing table tag
?>
it would print the table like this
just read line by line so that you can understand it easily..
OOP Style :
At first connection with database.
<?php
class database
{
public $host = "localhost";
public $user = "root";
public $pass = "";
public $db = "db";
public $link;
public function __construct()
{
$this->connect();
}
private function connect()
{
$this->link = new mysqli($this->host, $this->user, $this->pass, $this->db);
return $this->link;
}
public function select($query)
{
$result = $this->link->query($query) or die($this->link->error.__LINE__);
if($result->num_rows>0)
{
return $result;
}
else
{
return false;
}
}
?>
Then :
<?php
$db = new database();
$query = "select * from data";
$result = $db->select($query);
echo "<table>";
echo "<tr>";
echo "<th>Name </th>";
echo "<th>Roll </th>";
echo "</tr>";
while($row = mysqli_fetch_array($result))
{
echo "<tr>";
echo "<td> $row[name]</td>";
echo "<td> $row[roll]</td>";
echo "</tr>";
}
echo "</table>";
?>
This question already has answers here:
PHP parse/syntax errors; and how to solve them
(20 answers)
Closed 5 years ago.
This code is giving me and unexpected end of file. any help?
im trying to make a sinmple page that has many different queries on it. im making one page as it just keeps things in one place and to save time. anyone got any recommendations?
<?php
$host="127.0.0.1";
$username="root";
$pword="";
$database="spm";
require("db_connection.php");
//for searching by customer name
$customername1 = $_POST['customername1'];
//variables for inserting new restaurant
$restname = $_POST['restname'];
$restaddress = $_POST['restaddress'];
$resthomephone = $_POST['resthomephone'];
$restcolpoints = $_POST['restcolpoints'];
$restdelpoints = $_POST['restdelpoints'];
?>
<html>
<head>
<title>Database search</title>
</head>
<body>
<?php
$custidtosearch = "";
$query_string = "SELECT custID FROM customertable WHERE custname ='".$customername1."'";
if ($result = $mysqli -> query($query_string)) {
while ($row = $result -> fetch_object()) {
$custidtosearch = $row->dateid;
//echo $custidtosearch;
}
Echo "</table>";
$result->close();
}else{
echo ("there was an error or there was no query");
}
$query_string = "SELECT * FROM orderlist WHERE custid = '".$custidtosearch."'" ;
//echo $query_string;
if ($result = $mysqli -> query($query_string)) {
echo "<table border = '1'>";
echo "<tr><th> Customer Name</th> <th>Order ID</th> <th>Customer ID</th> <th>Restaurant ID</th> <th>Order points</th> <th>Customer Points used</th></tr>";
while ($row = $result -> fetch_object()) {
Echo "<tr>".$row->$customername1."</td>";
Echo "<td>".$row->PersonID."</td>";
Echo "<td>".$row->Name."</td>";
Echo "<td>".$row->mobile."</td>";
Echo "<td>".$row->email."</td>";
Echo "<td>".$row->dateid."</td></tr>";
}
Echo "</table>";
$result->close();
$query_string = "INSERT INTO `restauranttable`(`restname`, `address`, `phoneno`, `colpoints`, `delpoints`) VALUES ('".$restname."','".$restaddress."','".$resthomephone."',
'".$restcolpoints."','".$restdelpoints."')";
if ($result = $mysqli -> query($query_string)) {
Echo ("Restaurant added");
$result->close();
}else{
echo ("there was an error or there was no query");
}
$mysqli->close();
?>
<p><a href=enterpageuni.php />Back</a></p>
</body>
</html>
You're missing a closing } for one of your code blocks. Probably from the first if ($result = $mysqli -> query($query_string)) { (before you open the <table>. The end of file is "unexpected" because PHP is still waiting for that code block to be closed.
Your IF-STATEMENT is missing a closing tag. You need to check your code to verify where the closing tag should be placed.
if ($result = $mysqli -> query($query_string)) {
echo "<table border = '1'>";
echo "<tr><th> Customer Name</th> <th>Order ID</th> <th>Customer ID</th> <th>Restaurant ID</th> <th>Order points</th> <th>Customer Points used</th></tr>";
while ($row = $result -> fetch_object()) {
Echo "<tr>".$row->$customername1."</td>";
Echo "<td>".$row->PersonID."</td>";
Echo "<td>".$row->Name."</td>";
Echo "<td>".$row->mobile."</td>";
Echo "<td>".$row->email."</td>";
Echo "<td>".$row->dateid."</td></tr>";
}
Echo "</table>";
$result->close();
} //<!--- I'm guessing this where the close tag should go.
Essentially, I am creating a movie ordering system that has 7 movie genres, and I want each movie tab to populate according to genre. At this point I cant even get the table to show up. Can anyone help me out?
<div id="content">
<table>
<tr><th>Name</th> <th>Genre</th> <th>Year</th> <th>Rating</th></tr>
<?php
//connect to database
$dbc = mysql_connect('localhost' , 'username' , 'password');
$test = mysql_select_db('movies', $dbc);
if ($test = mysql_select_db('movies', $dbc))//test
{
$query = "SELECT * FROM 'movies' WHERE 'genre' = 'Action'";
//call query
$result = mysql_query($query, $dbc);
while ($row = mysql_fetch_array($result))
{
?>
<tr>
<td><?php print $row['name']; ?></td>
<td><?php print $row['genre']; ?></td>
<td><?php print $row['year']; ?></td>
<td><?php print $row['rating'];?></td>
</tr>
<table>
<?php
}//close the while loop
}//close the if statement
mysql_close($dbc);
?>
First of all, do not use mysql because of secure problems and it will be not suported in PHP later. Read about this http://php.net/manual/en/function.mysql-connect.php .
Try to use PDO or mysqli, for example :
$con=mysqli_connect("example.com","peter","abc123","my_db");
// Check connection
if (mysqli_connect_errno())
{
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
$result = mysqli_query($con,"SELECT * FROM 'movies' WHERE 'genre' = 'Action'");
while($row = mysqli_fetch_array($result))
{
echo $row['name'];
echo "<br>";
}
mysqli_close($con);
I am trying to display all the data from a mysql table into a html table and the PHP is getting the data fine but the table isn't displaying it properly this is my code:
<table border="1">
<tr>
<td>ID</td>
<td>Name</td>
<td>Phone Number</td>
<td>Email</td>
<td>Time</td>
<td>Number Of People</td>
<td>Time Placed</td>
</tr>
<?php
$host = "localhost";
$database = "reservation";
$user = "root";
$pass = "root";
//connection to the database
mysql_connect($host, $user, $pass)
or die ('cannot connect to the database: ' . mysql_error());
//select the database
mysql_select_db($database)
or die ('cannot select database: ' . mysql_error());
$sql = "SELECT * FROM reservation ORDER BY timeplaced";
$result = mysql_query($sql);
while($data = mysql_fetch_row($result)){
echo("<tr><td>$data[0]</td><td>$data[1]</td><td>$data[2]</td></tr><td>$data[3]</td></tr><td>$data[4]</td></tr><td>$data[5]</td></tr><td>$data[6]</td></tr>");
}
?>
</table>
Please help.
$sql = "SELECT * FROM reservation ORDER BY timeplaced";
$result = mysql_query($sql);
while($data = mysql_fetch_row($result)){
echo("<tr>
<td>$data[0]</td>
<td>$data[1]</td>
<td>$data[2]</td>
<td>$data[3]</td>
<td>$data[4]</td>
<td>$data[5]</td>
<td>$data[6]</td>
</tr>");
}
when you use TDs in TR, they all must be same numbers, or use colspan, try the above echo statement, it will display your table properly.
When you are echoing array items it should be
echo "<tr><td>" . $data[0] . "</td></tr>";
echo "<tr><td>{$data[0]}</td><td>{$data[1]}</td><td>{$data[2]}</td></tr><td>{$data[3]}</td></tr><td>{$data[4]}</td></tr><td>{$data[5]}</td></tr><td>{$data[6]}</td></tr>";
Use braces.
I created a database in xampp, made a very simple php script that access/connect to mysql in xampp(saved it to xampp/htdocs). The connection is ok, but when I ran it to a browser, only a table I created in php appeared but the data in mysql did not. What could be the problem?
Here is the php code:
<?php
// Make a MySQL Connection
mysql_connect("localhost", "root", "password") or die(mysql_error());
mysql_select_db("test") or die(mysql_error());
// Get all the data from the "example" table
$result = mysql_query("SELECT * FROM example")
or die(mysql_error());
echo "<table border='1'>";
echo "<tr> <th>Name</th> <th>Age</th> </tr>";
// keeps getting the next row until there are no more to get
while($row = mysql_fetch_array( $result )) {
// Print out the contents of each row into a table
echo "<tr><td>";
echo $row['name'];
echo "</td><td>";
echo $row['age'];
echo "</td></tr>";
}
echo "</table>";
?>
If you just started to use PHP and MySQL why not starting to learn PDO as mysql_* functions are deprecated.
Make sure you have data in the example table, check with PHPMyAdmin and follow this nice guide.
Your code should be:
<?php
$db = new PDO('mysql:host=localhost;dbname=test;charset=UTF-8', 'username', 'password', array(PDO::ATTR_EMULATE_PREPARES => false, PDO::ATTR_ERRMODE => PDO::ERRMODE_EXCEPTION));
echo "<table border='1'>";
echo "<tr> <th>Name</th> <th>Age</th> </tr>";
$stmt = $db->query("SELECT * FROM example");
while($row = $stmt->fetch(PDO::FETCH_ASSOC)) {
echo "<tr><td>";
echo $row['name'];
echo "</td><td>";
echo $row['age'];
echo "</td></tr>";
}
echo "</table>";
?>