Can I use an if statement with multiple conditions? PHP - php

Question

I bet I can, but would it work like this?
function dutchDateNames($) {
$day = explode('-', $date)[2];
$dutchday = ($day < 10) ? substr($day, 1) : $day;
$month = explode('-', $date)[1];
if ($month == '01' . '02') {
$dutchmonth = 'Januari' . 'Februari';
}
$dutchdate = $dutchday . ' ' . $dutchmonth . ' ' . explode('-', $date)[0];
return $dutchdate
}
So, if $month is 01, $dutchmonth should be Januari. If $month is 02, $dutchmonth should be Februari, and so on.
I have the feeling I'm not doing this right?

Answer 1

Like thatyou would not return any month cause you concatenate (mounth 0102 does not exist).
If i correctly understand your question i think an array will be better :
$month = explode('-', $date)[1]; //Ok you use this data like an index
$letterMonth = ['01' => 'Januari', '02' => 'Februari', ....]; // Create an array with correspondance number -> letter month
$dutchmonth = $letterMonth[$month]; Get the good month using your index

Answer 2

Try this:
Use elseif conditions
if ($month == '01') {
$dutchmonth = 'Januari';
} elseif ($month == '02') {
$dutchmonth = 'Februari';
} elseif ($month == '03') {
$dutchmonth = '...';
}

Answer 3

Create lookup array and get value by key:
$month = '02';
$months = [
'01' => 'Januari'
'02' => 'Februari'
// more months here
];
$dutchmonth = isset($months[$month])? $months[$month] : '';
echo $dutchmonth;

Answer 4

I think the proper way is to save the map a array. Demo
<?php
$array['01'] = 'Januari';
$array['02'] = 'Februari';
print_r($array);
echo $array[$month];

Answer 5

You may do any of these:
if else
if ($month == "01") {
$dutchmonth = "Januari";
} else if($month == "02"){
$dutchmonth = "Februari";
}
switch
switch($month) {
case "01":
$dutchmonth = "Januari";
break;
case "02":
$dutchmonth = "Februari";
break;
}
Using array
$month_arr = array('01' => "Januari", '02' => "Februari");
$dutchmonth = $month_arr[$month];
NOTE: To use multiple if conditions use logical operators && or ||