Add field /column to array - php

Question

From mysqli request I receive a result that contains a table with 5 columns and a number of rows. I would like to perform a calculation with my data that I just received and add the result of my calc in a NEW COLUMN in my array.
So in different words, I would like to add one column to the array and fill this column with results for each row.
My code so far looks as follows and of course only prints the array that I receive from my SQL query:
<?php
error_reporting(0);
require 'init1.php';
if($result = $db->query("Select * from (select * from(SELECT * FROM `scores`
ORDER BY `battle_id` ASC,user_id asc,score desc) as t1 GROUP BY
t1.battle_id, t1.user_id) as t2 order by `battle_id` ASC,score desc")){
if($count = $result->num_rows){
echo '<p>' , $count, '<p>';
while ($row = $result->fetch_object()){
echo $row->battle_id, ' ' , $row->user_id, ' ' , $row->score, '<br>';
}
//instead of just printing the existing array, I would like to perform a
//calculation and add a result in a new column at the end of every single
//row
}
}

Answer 1

If you use an Array you can simply 'define' a new item in your array to store the calculation result.
while ($row = $result->fetch_row()) {
// Calculation and other stuff here
$row['calc_result'] = $calculation_result;
}
Then in order to access it outside the while scope, you would need to store each row in another array, for example:
$stored_data = array();
while ($row = $result->fetch_row()) {
// Calculation and other stuff here
$row['calc_result'] = $calculation_result;
array_push( $stored_data, $row );
}