Why is this mode function returning null? - php

Question

In the below function, when I call
mmmr(array(1,2,3,3,4,3), 'mode', 'ceil'); // null
it returns null. Works fine if I don't set the third ($round) argument.
mmmr(array(1,2,3,3,4,3), 'mode'); // 3
What am I missing? Coffee?
function mmmr( array $array, $output = 'mean', $round = false ) {
switch( $output ) {
case 'mode':
if( $round == "ceil" ) {
foreach( $array as $key => $value ) {
$array[$key] = ceil( $value );
}
} elseif( $round == "floor" ) {
foreach( $array as $key => $value ) {
$array[$key] = floor( $value );
}
} elseif( $round == "normal" ) {
foreach( $array as $key => $value ) {
$array[$key] = round( $value );
}
}
$v = array_count_values( $array );
arsort( $v );
foreach( $v as $k => $v ) {
$total = $k;
break;
}
break;
}
return $total;
}

Answer 1

array_count_values() can only count STRING and INTEGER values. ceil(), floor(), and round() return a float. Casting it to an int fixes your problem:
<?php
function mmmr( array $array, $output = 'mean', $round = false ) {
switch( $output ) {
case 'mode':
if( $round == "ceil" ) {
foreach( $array as $key => $value ) {
$array[$key] = (int) ceil( $value ); // (int)
}
} elseif( $round == "floor" ) {
foreach( $array as $key => $value ) {
$array[$key] = (int) floor( $value ); // (int)
}
} elseif( $round == "normal" ) {
foreach( $array as $key => $value ) {
$array[$key] = (int) round( $value ); // (int)
}
}
$v = array_count_values( $array );
arsort( $v );
foreach( $v as $k => $v ) {
$total = $k;
break;
}
break;
}
return $total;
}
echo mmmr(array(1,2,3,3,4,3), 'mode', 'ceil'); // Returns 3