VARCHAR SQL contains numbers how to get 2 decimals after comma - php

Question

I'm having some trouble getting the price to show correct on my website. Currently i have a row VerkoopPP40 which is a VARCHAR input. In this row there is a price e.g. 89,5 or just 9. When I try to get these values it does some unexpected things.
**** Update ****
I've just tried this code:
<?php
function formatNumber($number, $format=[], $oldDecimalSeparator=",.·'", $multiplier=1)
{
if ($format) {
$format += ['numOfDecimals' => 0, 'decimalSeparator' => '.', 'thousandSeparator' => '']; # Default format
# Find decimal separator
# The decimal separator is the one that is the last and does not occur more than once
if ($letters = str_replace(' ', '', $number)) { # Replace spaces
if ($letters = preg_replace('/^-/', '', $letters)) { # Remove minus
if ($letters = preg_replace('/[0-9]/', '', $letters)) { # Get all non digits
$lastletter = substr($letters, -1); # Returns last char
if (substr_count($letters, $lastletter) == 1) {
if (strpos($oldDecimalSeparator, $lastletter) !== false)
$oldDecimalSep = $lastletter;
else
return $number;
}
}
}
}
$number = preg_replace('/[^0-9-]/', '', $number); # Remove all non digits except 'minus'
if ($oldDecimalSep)
$number = str_replace($oldDecimalSep, '.', $number); # Format to float
if ($multiplier != 1)
$number = $number * $multiplier;
# Convert float to new format
$number = number_format($number,
$format['numOfDecimals'],
$format['decimalSeparator'],
$format['thousandSeparator']
);
}
return $number;
}
This returns: 9,00 and 895,00 so the comma is in a different place right now. It's something I guess... Anyone got an idea to move the comma and remove a 0.
**** End Update ****
And echo-ed it like this:
<td><p>vanaf " . formatNumber($number, [
'numOfDecimals' => 2,
'decimalSeparator' => ',',
'thousandSeparator' => ' '
], ',.') . " p.p. <small>Excl btw</small></p></td>
If I just echo the VerkoopPP40 row it returns: €89,5 or €9.
So I googled around some and found this:
$var = $row["VerkoopPP40"];
$var = ltrim($var, '0');
$foo = $var;
$prijzen = number_format($foo, 2, ',', '');
This turns the . into a ,. But also returns €9,00 for the row that has 9 in it. But the strange thing is the row that has 89.5 in it now just returns €89,00. So somewhere in the code it rounds the numbers down.
Does anyone know how to get the price to show just €9,00 and €89,50 respectively.
I tried the following codes as well:
SELECT ROUND(VerkoopPP40,2) AS RoundedPrice
As database query. That didn't work.
$prijzen = CAST($prijzen as decimal(2,2));
Also didn't work. Any more ideas?

Answer 1

Don't know if this will help you, but found in the comments of the PHP doc : "To prevent the rounding that occurs when next digit after last significant decimal is 5 (mentioned by several people)..." read more
$num1 = "89,5";
$num2 = str_replace(',', '.', $num1);
$price = number_format($num2, 2, '.', '');
echo"[ $price ]";

Answer 2

you should use number_format but in the right way let me explain it to you
you tried this with 89.5
$prijzen = number_format($foo, 2, ',', '');
but this is written for 89,5 not for 89.5
//this will work for you
$var = $row["VerkoopPP40"];
echo 'raw output from database is :'.$var;
$var = $var / 10;
echo 'after this step the number is :'.$var;
$var = number_format($var, 2, '.', '');
echo 'after this step the number is :'.$var;
number_format(the input number, decimal places, 'the divider between whole numbers and decimals', '')