Dealing with starting index in array - PHP - php

Question

I've got an array of users from a database (I'm working in PHP, using CodeIgniter in Sublime)
I've got a view, that has a select that show display all the users, so in my view, at the top, I have this code (suppose that the arrays has 3 items):
<?php
$optionsUsers = array();
$qtyUsers = count($users); -->
if($qtyUsers > 0){
$optionsUsers[0]['name'] = 'Choose an option';
for($i=0; $i < $qtyUsers; $i++){
$optionsUsers[$i]['id'] = $users[$i]["userId"];
$optionsUsers[$i]['name'] = $users[$i]["username"];
}
}
?>
Then, in the select part, I have this:
<select id="cursadaUsuario">
<?php
$qtyOptionsUsers = count($optionsUsers);
if($qtyOptionsUsers>0){
for($i=0; $i<$qtyOptionsUsers; $i++){
if($i == 0){
echo '<option value="0" disabled selected>Please select an option</option>';
}else{
echo '<option value="'.$optionsUsers[$i]['id'].'">'.$optionsUsers[$i]['name'].'</option>';
}
}
}else{
echo '<option value="">There are no options available</option>';
}
?>
</select>
I've assigned to the $optionsUsers array in [0] the string "Choose an option" because when iterating THAT ARRAY in the select, I wanted to display it as disabled and just iterate the rest of the elements as usual
The problem is that array $users starts in 0 --> I've checked it with a foreach and all the users display are actually there:
foreach ($users as $key => $value){
print_r($users);
});
But I wanted [0] to be the text to display, "Choose your option", so if I assign the text to [0], the first item in array $users is never shown :( (in this example, it would iterate the text and 2 of the items, not the 3)
If I remove the text to [O], and just iterate the array, all the users are shown correctly, no one is missing, but that means... no text to tell "Choose an option" :/
I would like it to look like this --> http://www.hkvstore.com/phpreportmaker/doc/images/dropdownselect.png, so I want the text "Choose you option" to be shown AND disabled, and then the elements of the array, in my case, a list of users.
Note: I would like to keep using a 'for' loop.
Note2: This (Add option selected disabled in PHP) would be kind of similar to what I want to achieve, but still, I don't think I could just change the keys and assign my own to a list of users, the could be changed, added, deleted, etc.. :/
Ideas? Thanks in advance! :)

Answer 1

Unless I'm not understanding you, it's the same as the "No options available" option – it belongs outside the loop:
if ($qtyOptionsUsers > 0) {
echo '<option value="0" disabled selected>Please select an option</option>';
for ($i = 0; $i < $qtyOptionsUsers; $i++) {
echo '<option value="'.$optionsUsers[$i]['id'].'">'.$optionsUsers[$i]['name'].'</option>';
}
} else {
echo '<option value="">There are no options available</option>';
}

Answer 2

you need to push the users data from index 1 rather than from 0 index.Try below code to fix the choose option
for($i=0; $i <= $qtyUsers; $i++){
$optionsUsers[$i+1]['id'] = $users[$i]["userId"];
$optionsUsers[$i+1]['name'] = $users[$i]["username"];
}