Data not loaded by the ajax and data modal - php

Question

im trying to loaded the vehicle details using ajax and data modal dialog. but seem that the data does not loaded correctly and i cant seem to figured out what is wrong with codes.
<div class="container" style="width:900px;">
<h3 align="center">View All Available Vehicle</h3>
<br />
<div class="table-responsive">
<table class="table table-striped">
<tr>
<th width="40%">Plate Number</th>
<th width="20%">Type</th>
<th width="20%">Status</th>
<th width="10%">View</th>
</tr>
<?php
while($row = mysqli_fetch_array($result))
{
?>
<tr>
<td><?php echo $row["plateNo_vehicle"]; ?></td>
<td><?php echo $row["vehicle_Type"];?></td>
<td><?php echo $row["vehicle_status"];?></td>
<td><input type="button" name="view" value="more" id="<?php echo $row["id_vehicle"]; ?>" class="btn btn-info btn-xs view_data" /></td>
</tr>
<?php
}
?>
</table>
</div>
</div>
data modal dialog used to display the details.
<div id="dataModal" class="modal fade">
<div class="modal-dialog">
<div class="modal-content">
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal">×</button>
<h4 class="modal-title">Vehicles Details</h4>
</div>
<div class="modal-body" id="vehicle_detail">
</div>
<div class="modal-footer">
<button type="button" class="btn btn-danger" data-dismiss="modal">Close</button>
</div>
</div>
</div>
this is the select.php that i used
<?php
if(isset($_POST["vehicle_id"])) {
$output = '';
$link=msqli_connect("localhost","root","root","vms");
$query = "SELECT * FROM vehicle WHERE id_vehicle = '".$_POST["vehicle_id"]."'";
$result = mysqli_query($link, $query);
$output .= '
<div class="table-responsive">
<table class="table table-bordered">';
while($row = mysqli_fetch_array($result))
{
$output .= '
<tr>
<td width="30%"><label>Plate No</label></td>
<td width="70%">'.$row["plateNo_vehicle"].'</td>
</tr>
<tr>
<td width="30%"><label>Engine Number</label></td>
<td width="70%">'.$row["engineNo_vehicle"].'</td>
</tr>
<tr>
<td width="30%"><label>Engine Capacity</label></td>
<td width="70%">'.$row["engineCapacity_vehicle"].'</td>
</tr>
';
}
$output .= "</table></div>";
echo $output;
}
?>
script used
<script>
$(document).ready(function(){
$('.view_data').click(function(){
var vehicle_id = $(this).attr("id_vehicle");
$.ajax({
url:"select.php",
method:"post",
data:{vehicle_id:vehicle_id},
success:function(data){
$('#vehicle_detail').html(data);
$('#dataModal').modal("show");
}
});
});
});
</script>

Answer 1

Have a look at your select.php file:
<?php
if(isset($_POST["vehicle_id"])) {
$output = '';
$link=msqli_connect("localhost","root","root","vms"); <========
TYPO. It should've been:
$link=mysqli_connect("localhost","root","root","vms");
Also,
Add a data-vehicleid attribute to your view_data button:
<td><input type="button" data-vehicleid="<?php echo $row["id_vehicle"]; ?>" name="view" value="more" id="<?php echo $row["id_vehicle"]; ?>" class="btn btn-info btn-xs view_data " /></td>
And then change your script to receive that attribute value:
<script>
$(document).ready(function(){
$('.view_data').click(function(){
var vehicle_id = $(this).attr("data-vehicleid"); <=====
$.ajax({
....
});
});
});
</script>
Right now, you've set it to :
var vehicle_id = $(this).attr("id_vehicle");
which won't work as you don't have an attribute called id_vehicle="..." on that button. I'm guessing you meant attr("id");

Answer 2

Add this code on your while loop
<?php
while($row = mysqli_fetch_array($result))
{
?>
<tr>
<td><?php echo $row["plateNo_vehicle"]; ?></td>
<td><?php echo $row["vehicle_Type"];?></td>
<td><?php echo $row["vehicle_status"];?></td>
<td><input type="button" name="view" value="more" data-vehicle-id="<?php echo $row["id_vehicle"]; ?>" class="btn btn-info btn-xs view_data" /></td>
</tr>
<?php
}
?>
And in script change your id var vehicle_id = $(this).attr("data-vehicle-id");
Hope this code work

Answer 3

in order to get the id of this this you need to add onclick
<td><input type="button" name="view" value="more" id="<?php echo $row["id_vehicle"]; ?>" class="btn btn-info btn-xs view_data" onclick="getId(this.id)"/></td>
function getId(clicked_id){
var vehicle_id = clicked_id;
$.ajax({
url:"select.php",
method:"post",
data:{vehicle_id:vehicle_id},
success:function(data){
$('#vehicle_detail').html(data);
$('#dataModal').modal("show");
}
});
}

Answer 4

Here is updated code for view:
view:
<div class="container" style="width:900px;">
<h3 align="center">View All Available Vehicle</h3>
<br />
<div class="table-responsive">
<table class="table table-striped">
<tr>
<th width="40%">Plate Number</th>
<th width="20%">Type</th>
<th width="20%">Status</th>
<th width="10%">View</th>
</tr>
<?php
while($row = mysqli_fetch_array($result))
{
?>
<tr>
<td><?php echo $row["plateNo_vehicle"]; ?></td>
<td><?php echo $row["vehicle_Type"];?></td>
<td><?php echo $row["vehicle_status"];?></td>
<td>more</td>
</tr>
<?php
}
?>
</table>
</div>
</div>
Script:
<script>
$('#dataModal').on('show.bs.modal', function (event) {
var button = $(event.relatedTarget)
var vehicle_id = button.data('vehicle_id')
var modal = $(this)
$.ajax({
url:"select.php",
method:"POST",
data:{vehicle_id:vehicle_id},
success:function(data){
modal.find('.modal-body').html('No Response');
modal.find('.modal-body').html(data);
$('#vehicle_detail').html(data);
$('#dataModal').modal("show");
}
});
});
</script>