In the code below only the values from the last two forms are displayed. What could I be doing wrong?
<form action="" method="post">
<input name="fields[edu][name][]" />
<input name="fields[edu][age][]"/>
<br/><br/>
<input name="fields[edu][name][]" />
<input name="fields[edu][age][]"/>
<br/><br/>
<input name="fields[edu][name][]" />
<input name="fields[edu][age][]"/>
<br/><br/>
<input type="submit" name="submit" value="Submit"/>
if(isset($_POST['submit'])){
print_r($_POST['fields']);
foreach($_POST['fields'] as $field){
echo '<br/>';
echo 'Hello your name is : '.$field['name'];
echo '<br/>';
echo 'Hello your age is : '.$field['age'];
}
}
Update: What would be the best way to echo the values from the array? I've tried several methods none works
<form action="" method="post">
<input name="fields[edu0][name][]" />
<input name="fields[edu0][age][]"/>
<br/><br/>
<input name="fields[edu1][name][]" />
<input name="fields[edu1][age][]"/>
<br/><br/>
<input name="fields[edu2][name][]" />
<input name="fields[edu2][age][]"/>
<br/><br/>
<input type="submit" name="submit" value="Submit"/>
Related
I have a site where I make a payment, a bill is created through it, but the problem is that I can not use $ _POST twice in one, and this example:
<? if (isset($_POST['submit'])) { ?>
<form action="" method="POST" >
<input name="invoice" value="" type="text" />
<input name="pay" value="Pay Now" type="submit" />
</form>
<? } if (isset($_POST['pay'])) {
// MY QUERY HERE
// HEADERS HERE
} else { ?>
<form action="" method="POST" >
<input name="info" value="" type="text" />
<input name="submit" value="Submit" type="submit" />
</form>
<? } ?>
Try this.
Kindly check the code for comment.
<?
if (isset($_POST['submit'])) {
$info = $_POST['info'];
// use echo to display second form
echo '
<form action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]);?>" method="POST" >
<!-- // Note the action value, it's for post back. This allow you to post back to the current page -->
<!-- This is to keep the record passed from the first form -->
<input name="info" value="'. $info .'" type="hidden" />
<input name="invoice" value="" type="text" />
<input name="pay" value="Pay Now" type="submit" />
</form>';
} else if (isset($_POST['pay'])) {
// MY QUERY HERE
} else {
// Note the action value, it's for post back. This allow you to post back to the current page
<form action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]);?>" method="POST" >
<input name="info" value="" type="text" />
<input name="submit" value="Submit" type="submit" />
</form>
}
?>
Not the prettiest way to do this but to achieve your result try this...
<?php if (isset($_POST['submit'])) { ?>
<form action="" method="POST" >
<input name="invoice" value="" type="text" />
<input name="pay" value="Pay Now" type="submit" />
</form>
<?php } elseif (isset($_POST['pay'])) {
// Perform query here
} else { ?>
<form action="" method="POST" >
<input name="info" value="" type="text" />
<input name="submit" value="Submit" type="submit" />
</form>
<?php } ?>
In php, if you name your form fields using numerical indexes, they work as arrays in the $_POST object.
<form method="post" action="post.php">
<input type="text" name="question[0][name]" />
<input type="text" name="question[0][email]"/>
<input type="text" name="question[0][password]" />
<hr>
<input type="text" name="question[1][name]" />
<input type="text" name="question[1][email]"/>
<input type="text" name="question[1][password]" />
<hr>
<input type="submit" value="Add" />
<hr>
<p><?php
if ($_SERVER['REQUEST_METHOD'] == 'POST') {
echo json_encode($_POST, JSON_NUMERIC_CHECK);
}
?></p>
</form>
outputs
{"question":[{"name":"a","email":"aa","password":"aaa"},{"name":"b","email":"bb","password":"bbb"}]}
If the ordering of the fields is not sequential starting at zero and incrementing by only one each time the name is repeated, then they are all interpreted as keys instead. So
<form method="post" action="post.php">
<input type="text" name="question[1][name]" />
<input type="text" name="question[1][email]"/>
<input type="text" name="question[1][password]" />
<hr>
<input type="text" name="question[0][name]" />
<input type="text" name="question[0][email]"/>
<input type="text" name="question[0][password]" />
<hr>
<input type="submit" value="Add" />
<hr>
<p><?php
if ($_SERVER['REQUEST_METHOD'] == 'POST') {
echo json_encode($_POST, JSON_NUMERIC_CHECK);
}
?></p>
</form>
outputs
{"question":{"1":{"name":"a","email":"aa","password":"aaa"},"0":{"name":"b","email":"bb","password":"bbb"}}}
Is there a way to get $_POST to ignore the order of arrays of post keys so they are interpreted as an array?
Please check if helpful or not :
<form method="post" action="#">
<input type="text" name="question[1][name]" />
<input type="text" name="question[1][email]"/>
<input type="text" name="question[1][password]" />
<hr>
<input type="text" name="question[0][name]" />
<input type="text" name="question[0][email]"/>
<input type="text" name="question[0][password]" />
<hr>
<input type="submit" value="Add" />
<hr>
<p>
<?php
if ($_SERVER['REQUEST_METHOD'] == 'POST') {
ksort($_POST['question']);
print_r($_POST['question']);
}
?>
</p>
</form>
can we use $_POST 2 times with different page ?
this example ..
action.php
<form action="next.php" method="post">
<input name="test" value="test" />
<button type="submit" name="test">submit</button>
</form>
next.php
<?php
$test=$_POST['test'];
?>
<form action="next1.php" method="post">
<input name="test1" value="<?php echo $test; ?>" />
<button type="submit" name="test1">submit</button>
</form>
next1.php
<?php
echo $test2=$_POST['test1']; >> in here i didnt get test1 value . why ?
?>
Within next.php and action.php you need to change your input type like as
<input type="text" name="test" value="test" />
<input type="text" name="test1" value="<?php echo $test; ?>" />
Within next.php and action.php you were missing the type attr of input tag
and you have same name attributes for submit and input within next.php need to remove or change the value from respective
<input type="submit" value="submit"/>
Below code i have tried my local server and it executed successfully.
action.php:-
<form action="next.php" method="POST">
<input type="text" name="test"/>
<input type="submit" value="submit"/>
</form>
next.php:-
<?php
$test = $_POST['test'];
echo $test;
?>
<form action="next1.php" method="POST">
<input name="test1" value="<?php echo $test; ?>" />
<input type="submit" value="submit"/>
</form>
next1.php:-
<?php
$test2=$_POST['test1'];
echo "------".$test2;
?>
Hope this will help.I think this is achieved your requirement.
If you want to do it within one file e.g. index.php then here is the code
<?php
if(isset($_POST['test'])){
if(isset($_POST['test_text'])){
echo 'Output from NEXT: '.$_POST['test_text'];
}
}
elseif(isset($_POST['test1'])){
if(isset($_POST['test_text1'])){
echo 'Output from NEXT1: '.$_POST['test_text1'];
}
}
?>
<table style="width:100%;">
<tr >
<td style="width:50%;">
<form action="" method="post" name="next">
<input type="text" name="test_text" value="<?php echo isset($_POST['test_text']) ? $_POST['test_text']:''; ?>" />
<button type="submit" name="test">submit test1</button>
</form>
</td>
<td style="width:50%;">
<form action="" method="post" name="next1">
<input type="text1" name="test_text1" value="<?php echo isset($_POST['test_text1']) ? $_POST['test_text1']:''; ?>" />
<button type="submit" name="test1">submit test1</button>
</form>
</td>
</tr>
</table>
I hope this will help.
You need to send the POST value with the second form again, e.g. in a hidden field, otherwise the value won't be sent.
Furthermore your submit button shouldn't have the same name as the input field you want the content from. So change the name of your submit button, e.g.:
action.php
<form action="next.php" method="post"> <input name="test" value="test" /> <button type="submit" name="submit">submit</button> </form>
next.php
<form action="next1.php" method="post">
<input name="test1" value="<?php echo $test; ?>" />
<button type="submit" name="submit">submit</button>
</form>
In this
<form method="POST" action="">
<input type="text" class="field small-field" name="tex1" />
<input type="submit" value="search" name="search"/>
<input type="submit" value="print" name="print"/>
</form>
After I submit the form, the page refreshes and the data inside the input texts gets blank
Is it possible to keep the data even after submit?
Regards.
You can simply use ajax for submitting the form.
Or use following
<form method="POST" action=""><input type="text" class="field small-field" name="tex1" value="<?php (isset($_POST['text1]))? echo $_POST['text1] : '';" /><input type="submit" value="search" name="search"/><input type="submit" value="print" name="print"/></form>
try to echo, what ever is the variable named for your input.
<form method="POST" action="">
<input type="text" class="field small-field" name="tex1" value="<?php echo $_POST['tex1'];?>" />
<input type="submit" value="search" name="search"/>
<input type="submit" value="print" name="print"/>
</form>
With php for example:
<form method="POST" action="">
<input type="text" class="field small-field" name="tex1" value="<?php echo $_POST['tex1']; ?>"/>
<input type="submit" value="search" name="search"/>
<input type="submit" value="print" name="print"/>
</form>
If you are handling the post on the same page you could just do like this on the fields where you want the posted value to be shown:
<input type="submit" value="search" name="search" <?php if( isset( $_POST['search'] ) ){ echo "value=\"". $_POST['search'] ."\"; } ?>/>
Use this:
<form method="POST" action="">
<input type="text" class="field small-field" name="tex1" value="<?php if(isset($_POST['tex1'])) echo $_POST['tex1'] ?>" />
<input type="submit" value="search" name="search"/>
<input type="submit" value="print" name="print"/>
</form>
Bascially http is statelessprotocol , hence you need to save the data some where
The simplest way in this case would be to use a conditional operator
<input type="text" class="field small-field" name="tex1" value="<?php echo (isset($_POST['search'] || $_POST['search'] )?$_POST['tex1']:''); ?>" />
This is my HTML:
<form method="POST" action="">
<?php
$skillSubCategory = $skills->showSkills(24);
for ($i = 0; $i < count($skillSubCategory); $i++) {
?>
<input type="hidden" name="skillid" value="<?php echo $skillSubCategory[$i]['skill_id']; ?>" />
<?php echo $skillSubCategory[$i]['title']; ?>
<input type="submit" name="add" value="add" /><br />
<?php } ?>
</form>
<?php if (isset($_POST['add'])) {
echo $_POST['skillid'];
} ?>
Resulting source code:
<form method="POST" action="">
<input type="hidden" name="skillid" value="25" />
Animal Grooming
25
<input type="submit" name="add" value="add" /><br />
<input type="hidden" name="skillid" value="26" />
Dog Trainer
26
<input type="submit" name="add" value="add" /><br />
<input type="hidden" name="skillid" value="27" />
Dog Walking
27
<input type="submit" name="add" value="add" /><br />
<input type="hidden" name="skillid" value="28" />
Vet
28
<input type="submit" name="add" value="add" /><br />
<input type="hidden" name="skillid" value="29" />
Beekeeping
29
<input type="submit" name="add" value="add" /><br />
</form>
What it looks like:
I get number 29 for any button clicked. Any ideas what's wrong? Why the correct number wont show up when i click add?
You can also use the buttons themselves(without changing their values):
<input type="submit" name="skillid[25]" value="add" />
<input type="submit" name="skillid[26]" value="add" />
<input type="submit" name="skillid[27]" value="add" />
To retrieve the submitted value(its not the value in this case, its the first key of the posted array):
if(isset($_POST['skillid']) && is_array($_POST['skillid']))
{
echo key($_POST['skillid'])
}
Because when you have multiple fields with the same name attribute in a form, the last one always takes precedence (with the exception of submit buttons -- the one clicked will be the only one considered). So the last hidden input with the name skillid will always be sent to the server.
When using forms like this, you usually have to use separate forms for each button. Alternatively, change the value attribute of each button and consider that from your PHP code.
Change:
<form method="POST" action="">
to:
<form method="POST" action="<?php echo $_SERVER['PHP_SELF']; ?>">
then change the condition to:
if (isset($_POST['add']) && isset($_POST['skillid'])) {
EDIT: use the <option> tag instead
<select name="skillid">
<option value="25">Animal Grooming</option>
<option value="26">Dog Trainer</option>
...
</select>
Your PHP code now will be:
<form method="POST" action="<?php echo $_SERVER['PHP_SELF']; ?>">
<?php
$skillSubCategory = $skills->showSkills(24);
<select name="skillid">
for ($i = 0; $i < count($skillSubCategory); $i++) { ?>
<option value="<?php echo $skillSubCategory[$i]['skill_id']; ?>"><?php echo $skillSubCategory[$i]['title']; ?></option>
<?php } ?>
</select>
<input type="submit" name="add" value="add" /><br />
</form>
if (isset($_POST['add']) && isset($_POST['skillid'])) {
echo $_POST['skillid'];
} ?>