Class pagination - php

Question

I have problem error for load page 2,3,4 n etc of my original link is http://bali-webdesign.com/staging/astina3/subkategori-Bali%20Package-3-3.htm..
here my class_paging.php
class Paging{
function cariPosisi($batas){
if(empty($_GET['halaman'])){
$posisi=0;
$_GET['halaman']=1;
}
else{
$posisi = ($_GET['halaman']-1) * $batas;
}
return $posisi;
}
function jumlahHalaman($jmldata, $batas){
$jmlhalaman = ceil($jmldata/$batas);
return $jmlhalaman;
}
function navHalaman($halaman_aktif, $jmlhalaman){
$link_halaman = "";
// Link ke halaman pertama (first) dan sebelumnya (prev)
if($halaman_aktif > 1){
$prev = $halaman_aktif-1;
$link_halaman .= "<li class='paginate_button previous' id='table-gallery_previous'><a aria-controls='table-gallery' data-dt-idx='0' tabindex='0' href=$_SERVER[PHP_SELF]?halaman=1>«</a></li>
<li><a href=$_SERVER[PHP_SELF]?halaman=$prev>‹</a></li>";
}
else{
$link_halaman .= "<li class='disabled'><a>«</a></li><li class='disabled'><a>‹</a></li>";
}
// Link halaman 1,2,3, ...
$angka = ($halaman_aktif > 3 ? "" : " ");
for ($i=$halaman_aktif-2; $i<$halaman_aktif; $i++){
if ($i < 1)
continue;
$angka .= "<li><a href=$_SERVER[PHP_SELF]?halaman=$i>$i</a></li>";
}
$angka .= "<li class='paginate_button active'><a aria-controls='table-gallery' data-dt-idx='1' tabindex='0'>$halaman_aktif</a></li>";
for($i=$halaman_aktif+1; $i<($halaman_aktif+3); $i++){
if($i > $jmlhalaman)
break;
$angka .= "<li><a aria-controls='table-gallery' data-dt-idx='1' tabindex='0' href=$_SERVER[PHP_SELF]?halaman=$i>$i</a></li>";
}
$angka .= ($halaman_aktif+2<$jmlhalaman ? "<li><a href=$_SERVER[PHP_SELF]?halaman=$jmlhalaman>$jmlhalaman</a></li>" : " ");
$link_halaman .= "$angka";
// Link ke halaman berikutnya (Next) dan terakhir (Last)
if($halaman_aktif < $jmlhalaman){
$next = $halaman_aktif+1;
$link_halaman .= "<li class='paginate_button next' id='table-gallery_next'><a aria-controls='table-gallery' data-dt-idx='2' tabindex='0' href=$_SERVER[PHP_SELF]?halaman=$next>›</a></li><li><a href=$_SERVER[PHP_SELF]?halaman=$jmlhalaman>»</a></li>";
}
else{
$link_halaman .= "<li class='disabled'><a href='#'>›</a></li><li class='disabled'><a href='#'>»</a></li>";
}
return $link_halaman;
}
}
then in my page which I load pagination function
include "inc/config/class_paging.php";
$actual_link = "http://$_SERVER[HTTP_HOST]$_SERVER[REQUEST_URI]";
$s = new Paging;
$batas = 10;
$posisi = $s->cariPosisi($batas);
$produk = mysql_query("SELECT * FROM produk where id_subkategori='$_GET[idkk]' LIMIT $posisi,$batas");
$jmldata = mysql_num_rows(mysql_query("SELECT * FROM produk"));
while($p=mysql_fetch_array($produk)){
echo "blabla";
}
$jmlhalaman = $s->jumlahHalaman($jmldata, $batas);
$linkHalaman = $s->navHalaman($_GET[halaman], $jmlhalaman);
echo "<div align='center' class='dataTables_paginate paging_simple_numbers' id='table-about_paginate'>
<ul class='pagination'>$linkHalaman</ul>
</div>";
Right now, when I click page 2 button of pagination, the result link will be bali-webdesign.com/staging/astina3/subkategori.php?halaman=2 but that link can't show my data. I want when I click page 2 button of pagination will show my data
what should I change in class_paging.php for link url so it can show data on page 2,3,4 n etc