Mysql Create Table If Not Exists else.... Information Schema - php

Question

Quick one hopefully - not sure where I'm going wrong here but this doesn't seem to work full stop.
Running MySQL query through PHP...
Current code
$uu = mysql_query("
IF EXISTS(SELECT table_name FROM information_schema.tables
WHERE table_schema = 'schema_example' AND table_name = 'test_q')
THEN
insert into `test_q` (code, va_desc, price, category)
values ('$code', '$desc', '$price', '$categ')
on duplicate key update va_desc='$desc', price='$price', category='$categ'
ELSE
CREATE TABLE `test_quote` (
`code` varchar(30) NOT NULL,
`va_desc` text NOT NULL,
`price` text NOT NULL,
`category` text NOT NULL,
PRIMARY KEY (`code`),
UNIQUE KEY `id` (`code`)
) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=1;
insert into `test_q` (code, va_desc, price, category)
values ('$code', '$desc', '$price', '$categ')
END IF;
")or die(mysql_error());
Really appreciate some help on what I need to change, at the moment this does absolutely nothing and doesn't return any specific errors. :/
Having said that if I run it in phpMyAdmin it returns the following (although I can't understand why):
#1064 - You have an error in your SQL syntax;
check the manual that corresponds to your MariaDB server
version for the right syntax to use near
'ELSE CREATE TABLE `test_quote`(
`code` varchar(30) NOT NULL,
`va_desc` text NO' at line 7

Answer 1

You don't need to query INFORMATION_SCHEMA. You can use the IF NOT EXISTS option to CREATE TABLE.
mysql_query("CREATE TABLE IF NOT EXISTS `test_q` (
`code` varchar(30) NOT NULL,
`va_desc` text NOT NULL,
`price` text NOT NULL,
`category` text NOT NULL,
PRIMARY KEY (`code`),
) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=1");
mysql_query("insert into `test_q` (code, va_desc, price, category)
values ('$code', '$desc', '$price', '$categ')
on duplicate key update va_desc='$desc', price='$price', category='$categ'");
Also, a primary key is a unique key, you don't need to specify them both when you create the table.

Answer 2

Trying using the following query as if, else and then statements are not supported in the sql query, for that you can stored procedures.
mysql_query("CREATE TABLE IF NOT EXISTS `test_q` (`code` varchar(30) NOT NULL,
`va_desc` text NOT NULL,
`price` text NOT NULL,
`category` text NOT NULL,
PRIMARY KEY (`code`),
);
mysql_query("insert into `test_q` (code, va_desc, price, category)
values ('$code', '$desc', '$price', '$categ')
on duplicate key update va_desc='$desc', price='$price', category='$categ'");