Drop-down PHP-MySqli error - php

Question

I want to make a dropdown list and i use this codes:
<div class="selector">
<?php
include ("connect.php");
$db = new mysqli('localhost', $dbuser, $dbpass, $dbnam);
?>
<div class="label">Select Name:</div>
<select name="names">
<option value = "">---Select---</option>
$stmt = $db->prepare("SELECT `name` FROM `monitoare`");
$stmt->execute();
$stmt->bind_result($name);
while ($stmt->fetch()){
echo "<option value='$name'></option>";
}
$stmt->close();
?>
</select>
as index.php
and this:
<?php
$dbname = 'mydabase';
$dbuser = 'myuser';
$dbpass = 'mypass';
?>
as connect.php and after i launch this the drop stays just with ---select--- as an option

Answer 1

I reckon that you should do all of this using either MySQLi procedural or object oriented rather trying to do with prepared statements.
<?php
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "myDB";
// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}
?>
You can save this in a 'connect.php' file and include it in the relevant file.
The solution to getting dropdown instead of --select-- without any errors is shown below
echo "<select name='names'>"
$sql = "SELECT `name` FROM monitoare";
$result =mysqli_query($db, $sql);
if (mysqli_num_rows($result) > 0) {
// output data of each row
while($row = mysqli_fetch_assoc($result)) {
echo "<option value=".$row['name'].">".$row['name']."</option>";
}
} else {
echo "No results found";
}
?>
For further reference check out http://php.net/manual/en/book.mysqli.php and also https://www.w3schools.com/php/php_mysql_insert.asp

Answer 2

Here's a (corrected) example, adapt to your code :
<?php
error_reporting(E_ALL);
ini_set('display_errors', 1);
$host = ""; /* your credentials here */
$user = ""; /* your credentials here */
$pwd = ""; /* your credentials here */
$db = ""; /* your credentials here */
/* connect to DBd */
$mysqli = mysqli_connect("$host", "$user", "$pwd", "$db");
if (mysqli_connect_errno()) { echo "Error connecting to DB : " . mysqli_connect_error($mysqli); }
$query = " SELECT `name` FROM `monitoare` ";
$stmt = $mysqli->prepare($query);
$stmt->execute();
$stmt->bind_result($name);
$stmt->store_result();
if ($stmt->num_rows > 0) { /* we have results */
echo"<select name=\"names\"><option value=\"\">---Select---</option>";
while($stmt->fetch()){
echo "<option value=\"$name\">$name</option>";
}
echo"</select>";
}
else
{ echo"[ no data ]"; }
?>