PHP: Three images from database in a row - php

Question

I would like to display three images from the database in one row. At the moment, all the images are in a vertical line and I do not know how to fix it. Any help would be appreciated. I am only learning PHP, have checked other questions and they have been no help.
I have tried using Bootstrap however that has not worked either. The way I have it does display 3 in a row however, shoes the same product in each row and only if I have the query $show_men="SELECT model, id, price,image FROM products WHERE id='id' "
<div class="col-xs-12 col-sm-4">
<!--selecting products from database and displaying. when user clicks on more info button, information is stored in array and displayed on item.php-->
<?php
include 'mysql.php';
$show_men="SELECT model, id, price,image FROM products WHERE cat='men' ";
$query_men=mysqli_query($conn,$show_men);
while($row=mysqli_fetch_array($query_men,MYSQLI_ASSOC)){
echo '<br><br><table class="table"><tbody>
<tr>
<div><center><img class="img-responsive" src="../images/'.$row['image'].'" width="200" height="200"></center><br>
<center><strong>'.$row['model'].'</strong><br><br><strong>Price:£ '.$row['price'].'</strong><br><br>
More Info<br><br><strong></center></div><hr>
</tr>
</tbody>
</table>';
}?>
</div>

Answer 1

You need to iterate the column instead of the table..
<div class="row">
<?php
include 'mysql.php';
$show_men="SELECT model, id, price,image FROM products WHERE cat='men' ";
$query_men=mysqli_query($conn,$show_men);
while($row=mysqli_fetch_array($query_men,MYSQLI_ASSOC)){
echo '<div class="col-xs-12 col-sm-4"><br><br><table class="table"><tbody>
<tr>
<div><center><img class="img-responsive" src="../images/'.$row['image'].'" width="200" height="200"></center><br>
<center><strong>'.$row['model'].'</strong><br><br><strong>Price:£ '.$row['price'].'</strong><br><br>
More Info<br><br><strong></center></div><hr>
</tr>
</tbody>
</table></div>';
}
?>
</div>