Inputs array from while loop, passing $_POST for each input - php

Question

<form role="form" autocomplete="off" action="includes/functions/fisa-init.php" method="POST">
<?php
connectDB();
$query = mysqli_query($mysqli, "SELECT * FROM `optionale`") or die(mysqli_error($mysqli));
while($row = mysqli_fetch_array($query))
{
?>
<span><?php echo $row['denumire']; ?></span>
<input type="text" name="nrBucati[]">
<input type="hidden" value="<?php echo $row['cod']; ?>" name="codProdus[]">
<?php } ?>
</form>
In the while loop I get an array for input name="nrBucati[]" and input name="codProdus[]".
I have the query:
$stmt3 = $mysqli->prepare("
UPDATE
`stocuri`
SET
`cantitate` = `cantitate` - ?
WHERE `cod` = ?
");
$stmt3->bind_param("is", $bucata, $cod);
// set parameters and execute
foreach( $_POST['nrBucati'] as $bucata ) {
return $bucata;
}
foreach( $_POST['codProdus'] as $cod ) {
return $cod;
}
if (!$stmt3->execute())
{
echo "Execuția a întâmpinat o eroare: (" . $stmt3->errno . ") " . $stmt3->error;
}
$stmt3->close();
I cannot manage to take all the input array values through $_POST. Detailed in:
While loop - Only one input from many others is sending a value through POST
How to get each input value from the arrays nrBucati[] and codProdus[] from HTML, through POST?

Answer 1

Something like this to properly assign/pair up your two params and then execute your query call from within the loop.
foreach( $_POST['nrBucati'] as $id => $bucata ) {
$cod = $_POST['codProdus'][$id];
if (!$stmt3->execute())
{
echo "Execuția a întâmpinat o eroare: (" . $stmt3->errno . ") " . $stmt3->error;
}
}

Answer 2

Run a foreach and prepare your data inside foreach loop:
// Get posted data and execute
foreach( $_POST['nrBucati'] as $key=>$bucata ) {
$cod = $_POST['codProdus'][$key]; // For object change this to $_POST['codProdus']->$key;
$stmt3= $mysqli->prepare("UPDATE `stocuri` SET `cantitate` = `cantitate` - ?
WHERE `cod` = ? ");
$stmt3->bind_param("is", $bucata, $cod);
if (!$stmt3->execute()){
echo "Execuția a întâmpinat o eroare: (" . $stmt3->errno . ") " . $stmt3->error;
}
$stmt3->close();
}