Populating Php Dropdown list from mysql database [duplicate] - php

Question

This question already has answers here:
Using PHP to populate a <select></select> dropdown? [duplicate]
(7 answers)
Closed 7 months ago.
am trying to populate a dropdown list from mysql database table
here is the code
<div class="form-group">
Select Make
<?php
include '../db_config/dbcon.php';
$sql = "SELECT * FROM vehicle_details";
$result = mysql_query($sql);
echo "<select name='vehicle_make'>";
while ($row = mysql_fetch_array($result)) {
echo "<option value='" . $row['vehicle_make'] . "'>" . $row['vehicle_make'] . "</option>";
}
echo "</select>";
?>
</div>
This is what is displayed by the code
Where am i going wrong??

Answer 1

This worked too, its a modification of janlindo's above
<div class="form-group">
Select Make <?php
include '../db_config/dbcon.php';
$sql = "SELECT * FROM vehicle_details";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
echo "<select name='vehicle_make'>";
// output data of each row
while($row = $result->fetch_assoc()) {
echo "<option value='" . $row['vehicle_make'] . "'>" . $row['vehicle_make'] . "</option>";
}
echo "</select>";
}
?>
</div>

Answer 2

Depending on whats in your dbcon.php, but here's an example using mysqli_query:
<div class="form-group">
Select Make <?php
// start of dbcon
$servername = "localhost";
$username = "username";
$password = "password";
$dbname = "myDB";
$conn = new mysqli($servername, $username, $password, $dbname);
//end of dbcon
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$sql = "SELECT * FROM vehicle_details";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
echo "<select name='vehicle_make'>";
// output data of each row
while($row = $result->fetch_assoc()) {
echo "<option value='" . $row['vehicle_make'] . "'>" . $row['vehicle_make'] . "</option>";
}
echo "</select>";
}
$conn->close();
?>
</div>