string replace without using any in-built function - php

With a program to replace substring in a string without using str_replace
should be generic function should work for below example:
Word : Hello world
Replace word : llo
Replace by : zz
Output should be: Hezz world
Word : Hello world
Replace word : o
Replace by : xx
Output should be: Hellxx wxxrld
This is what i wrote to solve it
function stringreplace($str, $stringtoreplace, $stringreplaceby){
$i=0;$add='';
while($str[$i] != ''){
$add .= $str[$i];
$j=0;$m=$i;$l=$i;$check=0;
if($str[$i] == $stringtoreplace[$j]){
while($stringtoreplace[$j] != ''){
if($str[$m] == $stringtoreplace[$j]){
$check++;
}
$j++;$m++;
}
if($check == strlen($stringtoreplace)){
$n=0;$sub='';
for($n=0;$n<=strlen($stringtoreplace);$n++){
$str[$l] = '';
$sub .= $str[$l];
$l++;
}
$add .= $stringreplaceby;
$i += $check;
}
}
$i++;
}//echo $add;exit;
return $add;
}
I am getting output as helzzworld .
Please take a look what I did wrong or if you have better solution for this please suggest.

You can do this by explode the main string into array then implode your stringreplaceby to your array parts creating new string
<?php
function stringreplce($str,$strreplace,$strreplaceby){
$str_array=explode($strreplace,$str);
$newstr=implode($strreplaceby,$str_array);
return $newstr;
}
echo stringreplce("Hello World","llo","zz")."<br>";
echo stringreplce("Hello World","Hel","zz")."<br>";
echo stringreplce("Hello World"," Wo","zz")."<br>";
echo stringreplce("Hello World","rl","zz")."<br>";
echo stringreplce("Hello World","ld","zz")."<br>";
?>

Try this simplest one, without using str_replace, Here we are using explode and implode and substr_count.
1. substr_count for counting and checking the existence of substring.
2. explode for exploding string into array on the basis of matched substring.
3. implode joining the string with replacement.
Try this code snippet here
<?php
ini_set('display_errors', 1);
$string="Hello world";
echo strReplace($string,"llo","zz");
echo strReplace($string,"o","xx");
function strReplace($string,$toReplace,$replacement)
{
if(substr_count($string, $toReplace))
{
$array=explode($toReplace,$string);
return implode($replacement, $array);
}
}
Solution 2:
Try this code snippet here not best, but working
<?php
ini_set('display_errors', 1);
$string="Hello world";
echo strReplace($string,"llo","zz");
echo strReplace($string,"o","xx");
function strReplace($string,$toReplace,$replacement)
{
while($indexArray=checkSubStringIndexes($toReplace,$string))
{
$stringArray= getChars($string);
$replaced=false;
$newString="";
foreach($stringArray as $key => $value)
{
if(!$replaced && in_array($key,$indexArray))
{
$newString=$newString.$replacement;
$replaced=true;
}
elseif(!in_array($key,$indexArray))
{
$newString=$newString.$value;
}
}
$string=$newString;
}
return $string;
}
function getLength($string)
{
$counter=0;
while(true)
{
if(isset($string[$counter]))
{
$counter++;
}
else
{
break;
}
}
return $counter;
}
function getChars($string)
{
$result=array();
$counter=0;
while(true)
{
if(isset($string[$counter]))
{
$result[]=$string[$counter];
$counter++;
}
else
{
break;
}
}
return $result;
}
function checkSubStringIndexes($toReplace,$string)
{
$counter=0;
$indexArray=array();
$newCounter=0;
$length= getLength($string);
$toReplacelength= getLength($toReplace);
$mainCharacters= getChars($string);
$toReplaceCharacters= getChars($toReplace);
for($x=0;$x<$length;$x++)
{
if($mainCharacters[$x]==$toReplaceCharacters[0])
{
for($y=0;$y<$toReplacelength;$y++)
{
if(isset($mainCharacters[$x+$y]) && $mainCharacters[$x+$y]==$toReplaceCharacters[$y])
{
$indexArray[]=$x+$y;
$newCounter++;
}
}
if($newCounter==$toReplacelength)
{
return $indexArray;
}
}
}
}

function ganti_kata($kata,$kata_awal,$kata_ganti){
$i =0; $hasil;
$panjang = strlen($kata);
while ($i < $panjang) {
if ($kata[$i] == $kata_awal) {
$hasil[$i] = $kata_ganti;
echo $hasil[$i];
}
else if ($kata[$i] !== $kata_awal){
$hasil[$i] = $kata[$i];
echo $hasil[$i];
}
$i++;
}
}
echo ganti_kata('Riowaldy Indrawan','a','x');
This code using php

Related

Create a recursive function with an array

I have a function but can't success to make it recursive.
This is my function without recursion :
function resolution_recursion($tab1, $tab2){
$solution = [];
foreach($tab2 as $nb2){
foreach($tab1 as $nb1){
if(($nb2 + $nb1)%2 != 1){
$solution[] = $nb2 + $nb1;
}
}
}
return $solution;
}
And I would like to make it recursive to make it work like :
$nb_ajout = [2];
$next = [[1,2],[3,4],[5,6],[7,8]];
resolution_recursion(
resolution_recursion(
resolution_recursion(
resolution_recursion($nb_ajout, $next[0]),
$next[1]),
$next[2]),
$next[3]);
I can't find the solution, if you can help me.
Something like this would do the trick...
function resolution_recursion($tab1, $tab2, $solution = [])
{
if (empty($tab2)) {
return $solution;
}
$set = array_shift($tab2);
foreach($set as $nb2){
foreach($tab1 as $nb1){
if(($nb2 + $nb1)%2 != 1){
$solution[] = $nb2 + $nb1;
}
}
}
if (!empty($tab2)) {
return resolution_recursion($tab1, $tab2, $solution);
}
return $solution;
}
You can find a demo here (the output however means absolutely nothing to me though so hopefully it means something to you lol)
I think I have found something, not using recursion :
function resolution_recursion($tab1, $tab2){
$solution = [];
$solution[-1] = $tab1;
foreach($tab2 as $key => $tab){
foreach($tab as $nb2){
foreach($solution[$key-1] as $nb1){
if(($nb2 + $nb1)%2 != 1){
$solution[$key][] = $nb2 + $nb1;
}
}
}
}
return $solution;
}

PHP array values not being changed

I was trying to make a program to do synthetic division which requires factoring so I wrote this function to factor an integer which works, but it never changes the values of the php array $factors. Any help will be greatly appreciated.
$factors=array();
$i;
function factor($x){
if($x==0){
echo "(0,0)";
} else {
$n=false;
if($x<0) {
$x=abs($x);
$n=true;
}
for($i=2; $i<=$x; $i++) {
if($x%$i==0){
if($n){
$factors[(count($factors))]=(-1*($x/$i));
$factors[(count($factors))]=($i);
$factors[(count($factors))]=($x/$i);
$factors[(count($factors))]=(-1*$i);
} else {
$factors[(count($factors))]=($x/$i);
$factors[(count($factors))]=($i);
}
}
}
}
}
factor(-4);
Try this
function factor($x){
$factors=array();
if($x==0){
echo "(0,0)";
} else {
$n=false;
if($x<0) {
$x=abs($x);
$n=true;
}
for($i=2; $i<=$x; $i++) {
if($x%$i==0){
if($n){
$factors[(count($factors))]=(-1*($x/$i));
$factors[(count($factors))]=($i);
$factors[(count($factors))]=($x/$i);
$factors[(count($factors))]=(-1*$i);
} else {
$factors[(count($factors))]=($x/$i);
$factors[(count($factors))]=($i);
}
}
} //end for
echo '(' . implode(',', $factors). ')';
} //end if $x == 0
}
factor(-4);
$factors is outside the scope of the function, besides that you were not returning or outputting anything. Seeing as you echo (0,0) I assumed you wanted it echoed such as (2,4,8) etc. Which you can do with implode..

Is there any possibility to break a loop while calling a function?

Let's say I have a simple code:
while(1) {
myend();
}
function myend() {
echo rand(0,10);
echo "<br>";
if(rand(0,10) < 3) break;
}
This will not work with error code 'Fatal error: Cannot break/continue 1 level on line'.
So is there any possibility to terminate the loop during a subfunctin execution?
Make the loop condition depend upon the return value of the function:
$continue = true;
while( $continue) {
$continue = myend();
}
Then, change your function to be something like:
function myend() {
echo rand(0,10);
echo "<br>";
return (rand(0,10) < 3) ? false : true;
}
There isn't. Not should there be; if your function is called somewhere where you're not in a loop, your code will stop dead. In the example above, your calling code should check the return of the function and then decide whether to stop looping itself. For example:
while(1) {
if (myend())
break;
}
function myend() {
echo rand(0,10);
echo "<br>";
return rand(0,10) < 3;
}
Use:
$cond = true;
while($cond) {
$cond = myend();
}
function myend() {
echo rand(0,10);
echo "<br>";
if(rand(0,10) < 3) return false;
}

Checking for undefined variables in a function php

So I've been trying to devise a function that will echo a session variable only if it is set, so that it wont create the 'Notice' about an undefined variable. I am aware that one could use:
if(isset($_SESSION['i'])){ echo $_SESSION['i'];}
But it starts to get a bit messy when there are loads (As you may have guessed, it's for bringing data back into a form ... For whatever reason). Some of my values are also only required to be echoed back if it equals something, echo something else which makes it even more messy:
if(isset($_SESSION['i'])){if($_SESSION['i']=='value'){ echo 'Something';}}
So to try and be lazy, and tidy things up, I have tried making these functions:
function ifsetecho($variable) {
if(!empty($variable)) {
echo $variable;
}
}
function ifseteqecho($variable,$eq,$output) {
if(isset($variable)) {
if($variable==$eq) {
echo $output;
}
}
}
Which wont work, because for it to go through the function, the variable has to be declared ...
Has anyone found a way to make something similar to this work?
maybe you can achieve this with a foreach?
foreach ($_SESSION as $variable)
{function ifseteqecho($variable,$eq,$output) {
if($variable==$eq) {
echo $output;
}
else echo $variable;
}
}
now this will all check for the same $eq, but with an array of corresponding $eq to $variables:
$equiv = array
('1'=>'foo',
'blue'=>'bar',);
you can check them all:
foreach ($_SESSION as $variable)
{function ifseteqecho($variable,$equiv) {
if(isset($equiv[$variable])) {
echo $equiv[$variable];
}
else {
echo $variable;
}
}
}
Something like this?, you could extend it to fit your precise needs...
function echoIfSet($varName, array $fromArray=null){
if(isset($fromArray)){
if(isset($fromArray[$varName])&&!empty($fromArray[$varName])){
echo $fromArray[$varName];
}
}elseif(isset($$varName)&&!empty($$varName)){
echo $$varName;
}
}
You may use variable variables:
$cat = "beautiful";
$dog = "lovely";
function ifsetecho($variable) {
global $$variable;
if(!empty($$variable)){
echo $$variable;
}
}
ifsetecho("cat");
echo "<br/>";
ifsetecho("dog");
echo "<br/>";
ifsetecho("elephant");
UPDATE: With a rather complex code I’ve managed to meet your requirements:
session_start();
$cat = "beautiful";
$dog = "lovely";
$_SESSION['person']['fname'] = "Irene";
function ifsetecho($variable){
$pattern = "/([_a-zA-Z][_a-zA-Z0-9]+)".str_repeat("(?:\\['([_a-zA-Z0-9]+)'\\])?", 6)."/";
if(preg_match($pattern, $variable, $matches)){
global ${$matches[1]};
if(empty(${$matches[1]})){
return false;
}
$plush = ${$matches[1]};
for($i = 2; $i < sizeof($matches); $i++){
if(empty($plush[$matches[$i]])){
return false;
}
$plush = $plush[$matches[$i]];
}
echo $plush;
return true;
}
return false;
}
ifsetecho("cat");
echo "<br/>";
ifsetecho("dog");
echo "<br/>";
ifsetecho("elephant");
echo "<br/>";
ifsetecho("_SESSION['person']['fname']");
echo "<br/>";
ifsetecho("_SESSION['person']['uname']");
echo "<br/>";

php regex failed, why?

The value is AbcDefg_123.
Here is the regex:
function checkAlphNum($alphanumeric) {
$return = false;
if((preg_match('/^[\w. \/:_-]+$/', $alphanumeric))) {
$return = true;
}
return $return;
}
Should allow a-zA-Z0-9.:_-/ and space in any order or format and does need all but at least one character.
EDIT: Sorry again, looks like var_dump() is my new best friend. I'm working with XML and it's passing the tag as well as the value.
#SilentGhost thnx for the tips.
It works for me too.
<?php
class RegexValidator
{
public function IsAlphaNumeric($alphanumeric)
{
return preg_match('/^[\w. \/:_-]+$/', $alphanumeric);
}
}
?>
and this is how I am testing it.
<?php
require_once('Classes/Utility.php');
$regexVal = new RegexValidator();
$list = array("abcd", "009aaa", "%%%%", "0000(", "aaaa7775aaa", "$$$$0099aaa", "kkdkdk", "aaaaa", "..0000", " ");
foreach($list as $value)
{
if($regexVal->IsAlphaNumeric($value))
{
echo $value . " ------>passed";
echo "<BR>";
}
else
{
echo $value . "------>failed";
echo "<br>";
}
}
?>
function checkAlphNum($alphanumeric) {
$return = false;
if((preg_match('/^[A-Za-z0-9\w. \/:_-]+$/', $alphanumeric))) {
$return = true;
}
return $return;
}
print checkAlphNum("AbcDefg_123");
Returns true.

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