echo array from mysql into <option> value - php

Question

Please help me, I'm inserting the array (11,7,10) into a table.
Now i want to echo this data:
click here to show table
like this structure iwant to make it
<select>
<option value="11">11- HbA1C</option>
<option value="7">10- O"Solivan Test</option>
<option value="10">7- Randam Blood Glucose</option>
</select>
/////////////////////////////////////
table==>
id name date re_doctor sex age no_ana name_pr
11 aaaa 17/04/2017 Female 11,10,7 11- HbA1C,10- O"Solivan Test,7- Randam Blood Gluco.
////////////////////////////////////////////////
my code :-
<?
$qqq=$_GET['n'];
$sql = "SELECT * FROM `profile` where id ='$qqq'"; // select only the username field from the table "users_table"
$result = mysql_query($sql); // process the query
$username_array = array(); // start an array
while($row = mysql_fetch_array($result)){ // cycle through each record returned
$array1[] = $row[6]; // get the username field and add to the array above with surrounding quotes
// get the username field and add to the array above with surrounding quotes
$array3[] = $row[7]; // get the username field and add to the array above with surrounding quotes
}
?>
<select> <option>
<?
foreach($array1 as $it=>$ss){
foreach($array3 as $rr=>$vv){
if ($it==$rr) {
echo str_replace(',', '<option value="'.$ss.'">', $vv .'</option>');
}
}
}
?>
</select>

Answer 1

Lets say your data comes in as 11,7,10 from a multiple option or a checkbox as an array
Do a loop from the incoming form data from the array $no_ana at the user form
foreach($no_ana as $key => $value){
mysql_query("INSERT INTO table_name (id, name, date,
re_doctor, sex, age, no_ana, etc)
VALUES ($val1, $val2, $val3, $val4,
$val5, $val6, $value, $etc");
}
insert this code snippet to your script and test it out.
Here is how you do a multiple attribute
<select multiple name="name_pr[]">
<option value="11">11- HbA1C</option>
<option value="7">10- O"Solivan Test</option>
<option value="10">7 - Ramdam Blood Glocose</option>
</select>