how to convert multiple array to string in php - php

Question

Hi All,
i'm getting all the data from database for array format i need to pass that data to second drop down list like (group option value),please any one help me.
This is my php code:
<?php
//error_reporting(0);
$servername = "localhost";
$username = "root";
$password = "";
$db = "essae";
$data = "";
$subcategory_id = "";
$subcategory_name = array();
$conn = mysqli_connect($servername, $username, $password,$db);
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}
$category= $_GET["category_id"];
$sql = "SELECT es_category.category_id,es_category_description.name FROM es_category INNER JOIN es_category_description ON es_category.category_id=es_category_description.category_id WHERE parent_id='$category'";
$result = $conn->query($sql);
if ($result->num_rows > 1){
$sql_getrec ="SELECT es_category.category_id AS sub_cat_id,es_category_description.name AS sub_cat_name FROM es_category INNER JOIN es_category_description ON es_category.category_id=es_category_description.category_id WHERE parent_id='$category'";
$sub_category= $conn->query($sql_getrec);
if ($sub_category->num_rows > 1){
while ($row=mysqli_fetch_array($sub_category)){
$subcategory_id = $row['sub_cat_id'];
//$subcategory_name['sub_category_name'][] = $row['sub_cat_name'];
$sql_getrec = "SELECT es_product_description.name AS prod_name FROM es_product_to_category LEFT JOIN es_product_description ON es_product_description.product_id=es_product_to_category.product_id LEFT JOIN es_product ON es_product_description.product_id = es_product.product_id WHERE es_product_to_category.category_id = $subcategory_id AND es_product.status=1";
$sub_product=$conn->query($sql_getrec);
while ($prow=mysqli_fetch_array($sub_product)){
$subcategory_name['sub_category_name'][$row['sub_cat_name']]['products_name'][] = $prow['prod_name'];
}
}
echo "<pre>";print_r($subcategory_name);
}
}
else {
$sql_getrec = "SELECT es_product_description.name FROM es_product_to_category LEFT JOIN es_product_description ON es_product_description.product_id=es_product_to_category.product_id LEFT JOIN es_product ON es_product_description.product_id = es_product.product_id WHERE es_product_to_category.category_id='$category' AND es_product.status=1";
$result_getrec=$conn->query($sql_getrec);
while ($row=mysqli_fetch_array($result_getrec)){
$data .= $row['name'].",";
}
$data = rtrim($data,",");
}
print_r($data);
?>
This is my Html code:
<php?
$decocedData1 = json_decode($str_json_format, TRUE);
//print_r($decocedData1);die;
$decode = $decocedData1;
?>
<div>
<select name="category" id="category" />
<option selected ="selected">Select category</option>
<?php foreach($decode as $key => $value) { ?>
<option value="<?php echo $value['category_id']; ?>"><?php echo $value['name']; ?></option>
<?php } ?>
</select>
</div>
<div><select name="category12" id="category12" />
</select>
</div>
this is my j query and ajax method code:
<script type="text/javascript">
$(document).ready(function(){
$('#category').change(function(){
var category_id=$('#category').val();
$.ajax({
type: "get",
url: 'data_product.php?category_id='+category_id,
success: function(data) {
var products = data.split(",");
state_html = '';
state_html = '<option>Please Select product</option>'
$.each(products, function (index, productName) {
state_html += "<option value='"+productName+"'>"+productName+"</option>";
});
$('#category12').html(state_html);
},
});
})
});
</script>

Answer 1

You may use Type Casting in php
Type casting in PHP works much as it does in C: the name of the
desired type is written in parentheses before the variable which is to
be cast.
<?php
$array = array("name", "age", "mobile", "email");
var_dump($array);
(string)$array;
var_dump($array);
?>

Answer 2

This is not your final answer but you can try below code and figure out your variable names
$('#category12').empty();
$.each(data, function (index) {
var optgroup = $('<optgroup>');
optgroup.attr('label',data[index].name);
$.each(data[index].children, function (i) {
var option = $("<option></option>");
option.val(i);
option.text(data[index].children[i]);
optgroup.append(option);
});
$("#category12").append(optgroup);
});
$("#category12").multiselect('refresh');

Answer 3

you can do a jquery each in the result of your ajax
$.each(products, function(key, value) {
$('#category12')
.append($("<option></option>")
.attr("value",value)
.text(value));
});
$(function(){
//sample result, this will be your ajax result....
var products = ["Candy", "Cotton Candy", "Iced Candy"];
//clear again the select element.
$('#category12').empty();
$.each(products, function(key, value) {
$('#category12')
.append($("<option></option>")
.attr("value",value)
.text(value));
});
})
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<select id="category12"></select>