I am trying to use INFORMATION_SCHEMA.COLUMNS to get a list of all the columns available in a SQLEXPRESS table. This is the relevant code below:
$getColumns = sqlsrv_query($conn, $columnQuery);
while ($row = sqlsrv_fetch_array($getColumns)) {
echo $row[0];
}
Here are the results from that code:
GUIDFromServerRecTypeProfileNameActionTimeOccurredUserNameUserLDAPNameTSStationTSRemoteAddrUserSIDIPv4FromIPv6FromisDirectorywasBlockedACEtypeFullFilePathShareNameFileNameOnlyNewPathNameSIDOfNewOwnerACLObjectLDAPNameACLObjectDomainACLObjectNameACLMaskACLFlagsACLObjectType
It is the column names I need, but they are all in a single string rather than broken up 1 column per entry in the array the way I need it. I figured this much out by reseaching on this site, but no one mentioned in those other questions that this was a problem.
Related
I want to change the column name with a descriptive name, like in my table I have a field name "job_title",
I want to replace this heading with "what is your job title", and job_description with "Describe your job description"
For accomplishing this task I can use Aliasing but I want to change the column names dynamically instead of hard code.
I have described these questions in the comments section of the individual field of the table and I am trying to fetch these comments from the database and display comments of the field as the column heading but couldn't accomplish it.
This is my PHP code:
$sql_getcolumns="select * interview_col_comments where table_name ='interview'";
$result = $mysqli->query($sql_getcolumns);
echo "<table>";
echo "<tr>";
while($row = mysqli_fetch_array($result))
{
echo "<th>".$row[0]."</th>";
}
echo "";
I also tried to find a way in the PhpMyAdmin interface if I labeled column names and retrieve labels using a query in PHP
but didn't find this option in the SQL interface.
Is there another Approach using PHP, or SQL Which I can use to give columns of the table descriptive names?
One approach can be make an array in php like below.
<?php $comment=[
'job_title' => "what is your job title",'job_description'=>"Describe your job description"];
echo "<th>".$comment[$row[0]]."</th>";
?>'
Another approach can be make a another table with column description in mysql and replace on run time.
id|column_id|description
1|job_title|"what is your job title"
2|job_description|"Describe your job description"
What you are looking for is called "localization".
There are many ways to do that.
I usually ALSO prefer to keep this information tightly wired to the database I'm working with, so what I did is:
I used the Database Column's Comment field to provide meta-information.
For example, a columns comment can look like this:
#required #de=Vertragsnummer #en=Contract_Number #search
Now, using the following query, I can retrieve the comments, and build a ColumnMetadataObject out of the information using some regex / string operations.
SELECT
c.`TABLE_NAME`,
c.`COLUMN_NAME`,
c.`COLUMN_COMMENT`,
t.`TABLE_COMMENT`
FROM
information_schema.columns c left join
information_schema.TABLES t ON
c.TABLE_NAME = t.TABLE_NAME and
c.TABLE_SCHEMA = t.TABLE_SCHEMA
where
c.`table_schema` = 'MyDatabase'
After parsing the information and providing the required Meta-Data-Objects, My header output just looks like this:
<?=$db->getColumnMetdata('contractNumber')->getHeader($_SESSION["user_language"]));?>
Code in between can vary in complexity. My ColumnMetadata also contains other information like required, searchable, length, possible foreign keys, and much more. That part would be up to you - just for localize headers, an associative Array would work as well. something like :
["de"] => {
"table1.contractNumber" => "Vertragsnummer"
"table1.Id" => "Id"
}
I have two mysql tables. I want to get the data from these tables and show it in a loop. The data is totally unrelated to each other and should stay that way. I just need to show data from these two different tables in the same place.
I tried the mysqli_multi_query, but I couldn't show the results from an individual column like I can with a normal query.
For each of these two tables, I need 2 SELECT statements with two WHERE clauses. Does anyone know how to do this?
I've tried all different ways of trying to get the info from both tables and just show them in one loop. I've tried mysqli_multi_query, but don't know how to save specific column results in a variable.
$sql = "SELECT *
FROM misc
WHERE height LIKE '$height_input'
SELECT *
FROM bolts
WHERE name LIKE '$bolt_name_input'
;
";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
// output data of each row
while($row = $result->fetch_assoc()) {
$height_row = $row['height'];
$bolt_name_input = $row['name'];
?>
Height Row: <?php echo $height_row; ?>m<br />
bolt Name: <?php echo $bolt_name_input; ?><br />
} //while
My error message is generally "Trying to get property 'num_rows' of non-object".
Yes everyone, I have taught myself PHP and MySQL through online tutorials and have not had a lot of experience with them yet. I apologise, I am still getting the hang of this.
I have just worked out now by trial and error that I can show information from a table outside of the while loop. I had no idea I could do this! Which changes everything. So I can select information from various database tables using different SELECT statements and then echo them all into one place in my HTML table underneath it on my web page. The results don't have to be shown in the while loop, they can be outside it.
So my structure now looks like this basically:
SELECT from table 1 column 1 WHERE (form input value)
num rows
while loop
$height = $row_height['height'];
end num rows
end while loop
SELECT from table 2 column 1 WHERE (form input value)
num rows
while loop
$bolts = $row_bolts['bolts'];
end num rows
end while loop
<table>
<tr>
<td>echo $height</td>
<td>echo $bolts</td>
</tr>
</table>
So, this is working for me to retrieve multiple results from my different tables. I have to change the variable names of the sql statement each time, I guess I could do it with a function so i can repeat it and make it look neater, but this is working for me this way. So, with bolts I am using the variable names $sql_bolts, $result_bolts and $row_bolts and with height I am using variable names $sql_height, $result_height and $row_height and so on.
$bolts_input = $_POST['bolts'];
$sql_bolts = "
SELECT *
FROM bolts
WHERE name LIKE '$bolts_input'
;";
$result_bolts = $conn->query($sql_bolts);
if ($result_bolts->num_rows > 0) {
// output data of each row
while($row_bolts = $result_bolts->fetch_assoc()) {
$bolts = $row_bolts['name'];
} //bolts while
} // bolts num rows
I am not using mysql, but mysqli. I did a whole bunch of tutorials on PDO and how to connect to the database and retrieve information and just couldn't figure out how to show values from a row like I can with the above. It's frustrating because I want to use the latest methods, but I can't find how to online that makes sense to me.
Thank you for eveyone's comments so far.
So im developing a web page with the following sql query:
$sql=mysql_query("SELECT * FROM `fotf_images` WHERE `image_fotfnum` = '$Fivedigits'");
now, $fivedigits is a $_POST from a previous forms input data. So basically the form parses the mysql db for rows that contain ONLY $Fivedigits in a specific column. What i want to do, is output EVERY row that has these criteria. So far i used the following:
while ($row = mysql_fetch_array($sql, MYSQL_ASSOC)) {
print_r($row);
}
this only seems to output the first row, when i know as a fact there are exactly 2 rows that contain the criteria. Please help! Thanks!
try using
Select * from fotf_images
where Concat(image_fotfnum, '', field2, '', fieldn)
like concat('%','",$Fivedigits,"','%')
since its not only numeric you may need to use LOWER or UPPER case while comparing. This will help you search in every mentioned feilds of fotf_images table
Hi there i am working on PHP code that is selecting columns from two tables.
Here is my code:
$result2 = mysql_query("SELECT *
FROM `videos`, `m_subedvids`
WHERE `videos.approved`='yes' AND
`videos.user_id`='$subedFOR'
ORDER BY `videos.indexer`
DESC LIMIT $newVID");
while($row2 = mysql_fetch_array($result2))
{
$indexer = addslashes($row2['videos.indexer']);
$title_seo = addslashes($row2['videos.title_seo']);
$video_id = addslashes($row2['videos.video_id']);
$title = addslashes($row2['videos.title']);
$number_of_views = addslashes($row2['videos.number_of_views']);
$video_length = addslashes($row2['videos.video_length']);
}
When i try to print $indexer with echo $indexer; it's not giving me any results.
Where is my mistake in this code?
It seems to me like the key 'indexer' isn't in your results. It's hard to tell, since you haven't listed a definition for your table and you're using SELECT * so we can't see the names.
It makes the program easier to read later, if instead of SELECT *..., you use SELECT col1, col2, .... Yes, SELECT * will save you some typing right now, but you'll lose that time later when you or anyone else who works on your code has to check the table definition every time they work with that line of code.
So, try changing your query to explicitly select the columns you use. If it's an invalid column you'll get an error right away rather than this silent failure you're getting now, and you'll thank yourself later as well.
So long as videos.indexer is a unique field name among all tables used in the query you can change
$indexer = addslashes($row2['videos.indexer']);
to
$indexer = addslashes($row2['indexer']);
You don't need to (or can not) use the table name when referring to the result.
I am attempting to alphabetically organize an options list populated from an array; the problem is that the array array contains html tags at the front so sorting it seems imposable. I have tried 'ORDER BY' in the mysql query from which the array variables are pulled, but the command gets lost.
The whole system seems hardwired to sort the list by the key column in the mysql table, which is simply not acceptable. Is there any way around this issue? Any help would be VERY appreciated!
Here is an example of what I'm trying to do:
$options = array();
$query1=mysql_query("Select * From table1 Where name='blah'");
while($queryvalue1=mysql_fetch_array($query1)) {
$array1 = $queryvalue1['Column1'];
$query2=mysql_query("Select * From table2 Where id In ($array1) Order by value DESC");
while($queryvalue2=mysql_fetch_array($query2)) {
$var1 = $queryvalue2['Column2'];
$var2 = $queryvalue2['Column3'];
$options[] = "<option value='$var'>$var2</option>"
}
}
$options = implode(PHP_EOL, $options);
There's certainly ways to do it, but they are all much slower than letting the database sort for you.
It might not be the simplest solution, but I'd suggest getting rid of the HTML tags and repopulating the database, even if you have to use a temporary table while you fix the rest of your code. Do it right so you don't have to continually work around a serious problem for the rest of the application lifecycle.