How i can use if/else/elseif statment in my case - PHP - php

Question

How i can use if/else/elseif... in my case,
Because when i try those statment,
It says: syntax error, unexpected 'if' (T_IF)
I need to repeat elseif more than 1x time
$row = array();
$row[] = if($aRow['status'] == "deleted"){'code..'};

Answer 1

This might be what you are after. You would loop over each record in your result array you get from fetchAll(), put your if/elseif block here, then I'm assuming your doing some sort of processing and saving the value to $row array?
$row = array();
$result = $sth->fetchAll();
foreach($result as $aRow){
if($aRow['status'] == "deleted"){
//do something
$row[] = //whatever
}
elseif($aRow['status'] == "something else"){
//do something else;
$row[] = //whatever else
}
}

Answer 2

You have 2 ways for implementing this by PHP:
The 1st way
you can use if/else/elseif:
if ($status_var=="deleted")
{
//code .....
}
elseif ($status_var=="inserted")
{
//code .....
}
elseif ($status_var=="edited")
{
//code .....
}
esle
{
//code .....
}
The 2nd way
You can use switch/case structure:
switch ($status_var)
{
case "deleted":
//code .....
break;
case "inserted":
//code .....
break;
case "edited":
//code .....
break;
default:
//code .....
}

Answer 3

You can use ternary operator to assign the result:
$row = array();
$row[] = $aRow['status'] == "deleted" ? 'code..' : null;
When you need to do more things depending on status, best way would be to introduce a function for that:
function process($aRow) {
if ($aRow['status'] == "deleted") {
// do something when `deleted`
return 1;
} elseif ($aRow['status'] == "new") {
// do something when `new`
return 2;
} elseif ($aRow['status'] == "updated") {
// do something when `updated`
return 3;
} else {
// do something else
return 4;
}
}
$row = array();
$row[] = process($aRow);