Placing id/option value from dropdown selection into variable PHP, MySQL HTML - php

Question

I have a dropdown list that is filled with some values from a MySQL table.
The issue i'm facing is that I cannot place the ID from the selected value into a variable.
This is my code up until now:
<?php
mysql_connect('localhost', 'confidential', 'confidential');
mysql_select_db('mydb');
$sql = "SELECT zone_naam FROM zone";
$result = mysql_query($sql);
echo "<select name='zone_1' id='zone_1'>";
while ($row = mysql_fetch_array($result)) {
echo "<option value='" . $row['idzone'] . "'>" . $row['zone_naam'] . " </option>";
}
echo "</select>";
?>
I would think that I could get the value from $row['idzone'] by using the code below.
if(isset($_POST['submit'])) {
$zone_1 = $_POST['zone_1'];
$richting = $_POST['richting'];
$zone_2 = $_POST['zone_2'];
}
I've tried several things, but I cannot come to a solution.
If I want to do the same thing in HTML with self set data like below it always works, but whenever I want to use PHP for this purpose I seem to fail.
<select name="zone">
<option value="1">Zone1</option>
<option value="2">Zone2</option>
<option value="3">Zone3</option>
</select>
I hope you all understand what I mean and can help me to find the cause of this problem.
Best regards,
Rudibwoyyy

Answer 1

#Rudi
Then David is correct. If you submit the HTML from your post
<select name="zone">
<option value="1">Zone1</option>
<option value="2">Zone2</option>
<option value="3">Zone3</option>
</select>
you can use, according the select name "zone", the variable $_POST['zone'], assuming you are using <form method="post">, (otherwise it's $_GET['zone']) will contain the value (1, 2 or 3 respectively) of the selected entry.
If this doesn't work for you, check if the generated HTML Code hat the correct name.

Answer 2

Below is my code that works!! Thanks for all the tips
<?php
mysql_connect('localhost', 'root', '');
mysql_select_db('confidential');
$sql = "SELECT * FROM zone";
$result = mysql_query($sql);
echo "<form type='submit' class='form-inline' action='' method='POST'>
<select name='zone_1' id='zone_1' class='form-control mb-2 mr-sm-2 mb-sm-
0'>";
while ($row = mysql_fetch_array($result)) {
echo "<option value='". $row['idzone'] . "'>" . $row['zone_naam'] . "
</option>";
}
echo "</select>";
echo "<form type=\"submit\" method=\"POST\"> ";
echo " <select name=\"richting\" class='form-control mb-2 mr-sm-2 mb-sm-0'> ";
echo " <option value=\"<-->\"> <--> </option> ";
echo " <option value=\"<--\"> <-- </option> ";
echo " <option value=\"-->\"> --> </option> ";
echo "</select> ";
$result2 = mysql_query($sql);
echo "<select name='zone_2' class='form-control mb-2 mr-sm-2 mb-sm-0'>";
while ($row = mysql_fetch_array($result2)) {
echo "<option value='" . $row['idzone'] . "'>" . $row['zone_naam'] . "
</option>";
}
echo "</select>";
echo "<br><br>";
echo "<input type='submit' value='Submit' name='submit' id='submit' class='btn btn-primary btn-sm'>";
echo "</form>";
if(isset($_POST['submit'])) {
$zone_1 = $_POST['zone_1'];
$richting = $_POST['richting'];
$zone_2 = $_POST['zone_2'];
}
?>