How to call a method using array without object? - php

Question

How can I call a method like in laravel or slim route?
Let's say I have class like this:
namespace App;
class App
{
public function getApp(){
return "App";
}
}
and I want to call on this way
$route->get('App\App','getApp');
How can I do this?

Answer 1

The simplest way
call_user_func_array(['App\App', 'getApp'], $params_if_needed);
php.net source call_user_func_array()
If you need to check if method exists, just use
method_exists('SomeClass','someMethod') // returns boolean
php.net method_exists()
So you Router class may be next:
class Router
{
public function get($class, $method)
{
if($_SERVER['REQUEST_METHOD'] !== 'GET') {
throw new SomeCustomNotFoundException();
}
if (!method_exists($class, $method)) {
throw new SomeCustomNoMethodFoundException();
}
call_user_func_array([$class, $method], $_REQUEST); //with params
// OR
call_user_func([$class, $method]); //without params, not sure
}
}
If you want to do in the more clever way, you can use Reflection, it will give you information about class/method existence and also give information about method params, and which of them are required or optional.
UPDATE: This example expects methods to be static. For non-static you can add check, in the Router class, for class existence (class_exists($class)) and do smth like this
$obj = new $class();
$obj->$method(); //For methods without params
UPDATE(2) to check this out go here and paste next code
<?php
class Router
{
public function get($class, $method)
{
if($_SERVER['REQUEST_METHOD'] !== 'GET') {
throw new SomeCustomNotFoundException();
}
if(!class_exists($class)) {
throw new ClassNotFoundException();
}
if (!method_exists($class, $method)) {
throw new SomeCustomNoMethodFoundException();
}
call_user_func_array([$class, $method], $_REQUEST); //with params
// OR
//call_user_func([$class, $method]); //without params, not sure
}
}
class Test
{
public static function hello()
{
die("Hello World");
}
}
$route = new Router();
$route->get('Test', 'hello');