how to create pagination with next and previous button? - php

Question

code:
<table>
<tr style="background: white url(bg.gif) repeat-x left top;color: #fff;">
<th>College Id</th>
<th>College Name</th>
<th>Website</th>
<th>Field</th>
<th>City</th>
<th>Action</th>
</tr>
<?php
$per_page=10;
if (isset($_GET["page"]))
{
$page = $_GET["page"];
}
else {
$page=1;
}
$start_from = ($page-1) * $per_page;
$sql="select * from all_colleges LIMIT $start_from, $per_page";
$result = mysqli_query($link,$sql);
while ($row = mysqli_fetch_array($result))
{
?>
<tr>
<td><?php echo $row['college_id']; ?></td>
<td><?php echo $row['college_name']; ?></td>
<td><?php echo $row['website']; ?></td>
<td><?php echo $row['field']; ?></td>
<td><?php echo $row['city']; ?></td>
<td>
<a class='view' title='view' href='view.php?id=<?php echo $row['college_id']; ?>'>
<img src='gridview/view.png' alt='view' />
</a>
<a class='update' title='Update' href='update.php?id=<?php echo $row['college_id']; ?>'>
<img src='gridview/update.png' alt='Update' />
</a>
<a class='delete' title='delete' href='delete.php?ad_id=<?php echo $row['college_id']; ?>'>
<img src='gridview/delete.png' alt='delete' />
</a>
</td>
</tr>
<?php
}
?>
</table>
<div style="padding: 10px;">
<?php
$query = "select * from all_colleges";
$result = mysqli_query($link, $query);
$total_records = mysqli_num_rows($result);
$total_pages = ceil($total_records / $per_page);
echo "<center><a href='admin.php?page=1' style='padding:5px;'>".'previous'."</a>";
for ($i=1; $i<=$total_pages; $i++) {
echo "<a href='admin.php?page=".$i."'>".$i."</a>";
}
echo "<a href='admin.php?page=$total_pages'>".'next'."</a></center>";
?>
</div>
In this code I want to create a pagination with next and previous button here this code is working properly but it show diffrent pagination i.e. if the number of results is 200 then it will display like
previous 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 next
but I want like
previous 1 2 3 4 5 ....8 9 next
How can I do this please help ?
Thank You

Answer 1

You can check each iteration of your loop if you want to display the number.
In the following code, only:
the first two pages
the last two pages
the current page
each two pages to the left and to the right of the current page
are displayed.
$skipped = false;
for ($i = 1; $i <= $total_pages; $i++) {
if ($i < 3 || $total_pages- $i < 3 || abs($page - $i) < 3) {
if ($skipped)
echo '<span> ... </span>';
$skipped = false;
echo "<a href='admin.php?page=" . $i . "'>" . $i . "</a>";
} else {
$skipped = true;
}
}
If you have a lot of pages, the big loop is unnecessary.
Instead, you could use three different loops:
$done = [];
for ($i = 1; $i < 3; $i++) {
$done[$i] = true;
//echo
}
if ($page > 3)
echo '<span> ... </span>';
for ($i = $page - 2; $i < $page + 3; $i++) {
if (isset($done[$i])
continue;
$done[$i] = true;
//echo
}
if ($page < $total_pages - 3)
echo '<span> ... </span>';
for ($i = $total_pages- 2; $i < $total_pages; $i++) {
if (isset($done[$i])
continue;
$done[$i] = true;
//echo
}
To fix your two other buttons (previous and next), link to $page - 1 and$page + 1 instead of 1 and $total_pages.