I am looking for create a submit button, But I don't know how to get an answer ID and convert it in javascript variable.
My code:
<div id="<?php echo $question_ID?>">
<form method="post">
<p><?php echo $question ['question_content']; ?></p>
<p>
<?php
$poll_option_selection = "SELECT option_ID, option_content FROM poll_options WHERE question_ID='$question_ID'";
$poll_option_result = mysqli_query ($connect,$poll_option_selection) ;
foreach ($poll_option_result as $poll_option) {
$option_ID = $poll_option ['option_ID'] ;
$option_content = $poll_option ['option_content'] ;
?>
<input type="radio" name="option_selected" value ='<?php echo $option_ID ?>' onclick='getVote(this.value) ;' required />
<?php echo $option_content ?>
</br>
<?php } ?>
</form>
</div>
I found my answer after several test.
First. I put this the label "on submit=" on my form.
<form onsubmit='getVote(question_ID);'>
After this, I create my function
<script> function getVote(question_ID) {
var option_ID = document.querySelector('input[id="option"]:checked').value; </script>
Thank you for everthing
Related
I created a form where as soon as I click on the input of the submit, it writes me a value on the column to the database table.
So far everything is fine, but when the current page reloads, I can't see the result that was written to the database.
I can only see the result if I submit the form for the second time on the same page.
My code:
<?php
$increId = $_order->getRealOrderId();
$pathAss = 'My file';
$connectionresource = Mage::getSingleton('core/resource');
$connectionWrite = $connectionresource->getConnection('core_write');
$table = 'sales_flat_order';
$query = "UPDATE ".$table." "
. "SET upload_file_1='" . $pathAss . "'"
. " WHERE increment_id='".$increId."'";
$connectionWrite->query($query);
?>
<form id="abbLogoOrder" action="" method="post" enctype="multipart/form-data">
<a href="<?php echo $_order->getupload_file_1(); ?>"
title="<?php echo basename($_order->getupload_file_1()); ?>">
<?php echo basename($_order->getupload_file_1()); ?>
</a> //THIS VALUE RETURNS EMPTY AFTER FIRST SUBMIT FORM
<b>
<?php
/* $testget = ['getupload_file_'.$count.'()'];
echo $_order->$testget; */
?>
</b>
<div class="upload-btn-wrapper">
<button class="btn" style="font-size:13px;">SELECT YOUR FILES</button>
<input type="file" name="abbFile<?php echo $count; ?>[]" id="abbFile<?php echo $count; ?>" multiple="multiple" />
<input type="submit" value="SEND" />
</div>
</form>
What am I doing wrong?
You are not re-fetching the order details after the save function. So the details are getting from the initial state, so the result is old, but the next reload it changes to updated value and shows the right output.
But still it's unclear where you are loading the order object.
I am using a form having select dropdown. I want to pass the value obtained from the selected option as a $_GET request in form action field but any ways to access it outside the foreach loop. Here is the code sample that I have written
<form id="dynamicForm" action="client-detail-dynamic.php?id=<?php echo $_GET['id']; ?>&r_id=<?php **PASS THE DROPDOWN VALUE ID HERE** ?>" method="post">
<select class="form-control" id="dynamicfy" name="dynamicfy">
<?php
$j = 0;
foreach($payment_data as $pd):
?>
<option value="<?php echo $payment_data[$j]->r_id; ?>"><?php echo $payment_data[$j]->fy; ?></option>
<?php $j++; endforeach; ?>
</select>
</td>
<td class="col-md-4">
<input type="submit" name="submit" id="submit" class="btn btn-sm btn-success">
</td>
</form>
NOTE: $payment_data is an array containing the table data with field names r_id, fy etc
I have two methods for this.
First method
Create a hidden field inside form element to store the value of id.Put form action null
<form id="dynamicForm" action="" method="post">
<input type="hidden" name="id" value="<?php echo $_GET['id']; ?>">
On submit you will get two values
if(isset($_POST['submit'])){
$id=$_POST['id'];
$r_id=$_POST['dynamicfy'];
header("location: client-detail-dynamic.php?id=" . $id . "&r_id=" . $r_id . "");
exit();
}
Second method use javascript
<select class="form-control" id="dynamicfy" name="dynamicfy" onchange="rdrt(this.value)">
<script>
function rdrt(str){
id=<?php echo $_GET['id']; ?>;
if(str!=""){
location.href="client-detail-dynamic.php?id=" + id + "&r_id=" + str;
}
}
</script>
Rather than changing the page from FORM ACTION what you can do is pick the values and set them in url passed to header:location.
try this.
``<?php
if(isset($_POST['submit'])
{
$option = $_POST['dynamicfy'];
$id = $_POST['id']
header('location: http://client-detail-dynamic.php?id=$id,r_id=$option');
}
?>
<form id="dynamicForm" action="" method="post">
<select class="form-control" id="dynamicfy" name="dynamicfy">
<?php
$j = 0;
foreach($payment_data as $pd):
?>
<option value="<?php echo $payment_data[$j]->r_id; ?>"><?php echo $payment_data[$j]->fy; ?></option>
<?php $j++; endforeach; ?>
</select>
</td>
<td class="col-md-4">
<input type="hidden" name="id" value="<?php echo $_GET['id']; ?>
<input type="submit" name="submit" id="submit" class="btn btn-sm btn-success">
" />
</td>
</form>
What you are trying to do is go somewhere based in the $_GET['id]. That's not possible server side as you have to FIRST make the request, then execute code. If your aren't trying to bring form data with you to this URL, then try this suggestion. However forget what I about not possible. you could do something like:
<?php
if(isset($_POST['submit-button'])) {
header("location: file.php?something=" . $_GET['id']);
}
// set the form action to nothing and add this to the same page the form is on
// and you can redirect based on the $_GET['id']
?>
To change value on selection of dropdown, You will need to use a jQuery on change of select box.
Please refer following code for same.
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.1.1/jquery.min.js"></script>
<script type="text/javascript">
jQuery(Document).ready(function() {
jQuery('#dynamicfy').change();
});
jQuery('#dynamicfy').change(function() {
jQuery('#dynamicForm').attr('action', 'client-detail-dynamic.php?id=' +<?php echo $_GET['id']; ?> + '&r_id=' + jQuery(this).val());
});
</script>
if you just want selected dropdown on the action page then You may also get selected dropdown on the action page with using $_POST['dynamicfy'] on action page "client-detail-dynamic.php"
here is my code:
<?php
ob_start();
session_start();
require 'connection.php';
require 'core.inc.php';
?>
<?php
$take_thread_pid_query = #mysql_query(" select pid from threads ");
$row_take_thread_pid = mysql_fetch_array($take_thread_pid_query);
$pid = $row_take_thread_pid['pid'];
while($row_take_thread_pid = #mysql_fetch_array($take_thread_pid_query))
{
?>
<form action="kill_threads.php" method="POST" >
<label> <?php echo "<br/><br/>thread".$row_take_thread_pid['pid']; ?><input type="submit" value = " <?php echo $row_take_thread_pid['pid'];?> " name = " <?php echo
$row_take_thread_pid['pid']; ?> " /> </label>
<?php }?>
</form>
<?php
$t = "4756";//[4756 is on of the pids in my thread table].this is for testing but doesnt works,it cant find any button with this name.
if ( isset($_POST[$t] ) ) echo "im a killed thread..";
?>
The big problem is that im trying to give different names to each button i create,but it seems this is not working because when im trying to see if a button isset['???']
What i have to do...?
For example
thread 1 [button 1]
thread 2 [button 2]
thread 3 [button 3 ]
So if now i click button 1 i want thread1 row deleted from database.
phpmyadmin works like this.
Im so complicated..please help,thanks in advance.
Your code is:
value = " <?php echo $row_take_thread_pid['pid'];?> "
name = " <?php echo $row_take_thread_pid['pid']; ?> "
You are placing spaces before and after the php text so you either have to remove the spaces or code for them
I would suggest you to use another hidden input element within the form instead of doing it with submit form, in this way you can kill all the threads with one if block by passing thread id to it.
while($row_take_thread_pid = #mysql_fetch_array($take_thread_pid_query))
{
?>
<form action="kill_threads.php" method="POST" >
<label> <?php echo "<br/><br/>thread".$row_take_thread_pid['pid']; ?>
<input type="hidden" name="pid" value="<?php echo $row_take_thread_pid['pid'];?>" />
<input type="submit" value = "Delete" name = "delete_thread" /> </label> <?php }?>
</form>
<?php
$t = "4756";//[4756 is on of the pids in my thread table].this is for testing but doesnt works,it cant find any button with this name.
if ( isset($_POST[$t] ) ) echo "im a killed thread..";
?>
Another problem you may come across is using multiple forms without name and id. So add a dynamic number in the form tag like like this
<form name="<?php echo $i; ?>" id="<?php echo $i; ?>" action="kill_threads.php" method="POST" >
Here $i is counter variable or you can use $row_take_thread_pid['pid'] for this purpose.
I have a page that is created dynamically from the information that a user has submitted on a previous page. For example on page 1, the user inputs some department names. They can enter as many as they want. On page 2, multiple sections are created for each department that was entered on page one. Inside each of these sections are going to be forms, I currently have it set up so that the names of the forms are created using a variable $a. I need to know how to post these items once the submit button in each section is clicked. I have tried several different ways and nothing is working. I want it so that ONLY the items with the same $a value as the submit button's $a get posted.
$departmentSql = "SELECT * FROM b_departments WHERE loc_id='$locid' AND b_id = '$bid'";
$departmentResults = mysql_query($departmentSql,$con);
$a = 0;
while ($departmentRow = mysql_fetch_array($departmentResults)) {
$department = $departmentRow['b_dep_name'];
$departmentID = $departmentRow['dep_id'];
$b_departmentID = $departmentRow['b_dep_id'];
$a++;
echo "
<div id=depDiv>
<div id=depDivHeader>
".$department."
</div>
";
$areaSql = "SELECT * from areas WHERE dep_id = $departmentID ORDER BY area_name ASC";
$areaSqlResult = mysql_query($areaSql);
?>
<br />
<input type="hidden" name="bdep<?php echo $a;?>" value="<?php echo $b_departmentID; ?>" />
Add Area:
<select name="dep_area<?php echo $a;?>" type="menu">
<option value=""></option>
<?php while($areaRows=mysql_fetch_assoc($areaSqlResult)){?>
<option value="<?php echo "".$areaRows['area_id'].",".$areaRows['area_name']."" ?>"><? php echo $areaRows[ 'area_name'] ?></option>
<?php }
?>
</select>
<input type="submit" name="areaSub<?php echo $a;?>" value="Add" />
<?php
echo "</div>";
}
?>
*EDIT I need everything to be in one form because the point of the page is to add up all of the values that will be inserted into each of the individual sections later. *
**EDIT 2 :
I figured it out using #dirt 's jquery suggestion.
HTML:
$departmentSql = "SELECT * FROM b_departments WHERE loc_id='$locid' AND b_id = '$bid'";
$departmentResults = mysql_query($departmentSql,$con);
$a = 0;
while ($departmentRow = mysql_fetch_array($departmentResults)) {
$department = $departmentRow['b_dep_name'];
$departmentID = $departmentRow['dep_id'];
$b_departmentID = $departmentRow['b_dep_id'];
$a++;
echo "
<div id=depDiv>
<div id=depDivHeader>
".$department."
</div>
<div id=$a>
";
$areaSql = "SELECT * from areas WHERE dep_id = $departmentID ORDER BY area_name ASC";
$areaSqlResult = mysql_query($areaSql);
?>
<br />
<input type="hidden" name="bdep<?php echo $a ?>" value="<?php echo $b_departmentID; ?>" />
Add Area:
<select name="dep_area<?php echo $a ?>" type="menu">
<option value=""></option>
<?php while($areaRows=mysql_fetch_assoc($areaSqlResult)){?>
<option value="<?php echo "".$areaRows['area_id'].",".$areaRows['area_name']."" ?>"><? php echo $areaRows[ 'area_name'] ?></option>
<?php }
?>
</select>
<button type="submit" name="areaSub" value="<?php echo $a ?>" />Add</button>
<?php
echo "</div></div>";
} ?>
jQuery:
<script>
$(document).ready(function() {
$('#<?php echo $a ?>').submit(function() {
.post("include/action.php")
});
});
</script>
PHP:
if(isset($_POST['areaSub'])) {
$areaval = intval($_POST['areaSub']);
$area = mysql_real_escape_string($_POST["dep_area".$areaval.""]);
list($area_id, $area_name) = explode(',', $area, 2);
$bdep = mysql_real_escape_string($_POST["bdep".$areaval.""]);
echo $areaval;
echo $area_name;
echo $bdep;
}
EDIT: If its a single form with multiple sections and you don't want to trim out unwanted form data after the POST then I think you must use jQuery to trim the form values prior to the post to the server, so see my jQuery portion below for a crued example of how you would go about only posting the data for the selected button.
Short answer would be to use the Name/Value attributes of the submit button and evaluate that once posted. Multiple buttons with the same name can have different values and the values don't have to be the labels.
Example:
<form id='<?php echo $a; ?>'>
<input type='text' name='in1'>
<input type='text' name='in2'>
<button type='submit' name='submit' value='<?php echo $a; ?>'>Add</button>
</form>
...
<form id='<?php echo $a; ?>'>
<input type='text' name='in1'>
<input type='text' name='in2'>
<button type='submit' name='submit' value='<?php echo $a; ?>'>Add</button>
</form>
...
<?php
# _POST:
if (isset($_POST['submit']) && $_POST['submit'] == '1') {
echo 'Department 1';
}
if (isset($_POST['submit']) && $_POST['submit'] == '2') {
echo 'Department 2';
}
?>
You could also use jQuery to get all elements contained in a certain Div ID. Something like (this is rough idea):
<div id='<?php echo $a; ?>'>
<input type='text' name='in1'>
<input type='text' name='in2'>
<input type="submit" name="areaSub<?php echo $a;?>" value="Add" />
</div>
jQuery:
$('#<?php echo $a; ?>').submit(function() {
do_something_with_form_$a
});
I'm not sure if I understand completely... but the issue you're having is that, when a user hits the 'submit' button for a given set of values (a given department), it submits ALL of the data on the page? And you only want the input fields for that specific area submitted?
Section off forms with the tag:
<form> </form>
So, you'll have multiple areas:
while(...) {
<form method="..." name="form $a">
<input name="... $a">
<input name="... $a">
...
<submit>
</form>
}
(Obviously this is pseudocode, adjust accordingly)
I have a text box named subscriber name.when I double clicked on that text box,a child window should open.In that child window list of subscriber names are shown using while loop of mysql query.My problem is when I double clicked on it ll pass a value as undefined.This problems comes due to looping of subscriber names from db table.How can I solve it? Please help me soon.Here my code.
<script type="text/javascript">
function displaymessage(){
opener.document.cash_entry.sub_name.value = document.subscriber.subname.value;
self.close();
}
</script>
<form>
<?php
$sel=mysql_query("select * from add_ticket");
while($row=mysql_fetch_array($sel)) {
$subscriber=$row['subscriber'];
?>
<input type="text" name="subid" id="subid" value="<?php echo $subscriber; ?>"
ondblclick="displaymessage()" readonly="true">
<?php } ?>
</form>
You have not named your form and you named your field differently than in the HTML code and you have more than on element with the same name which makes it an array if more than one
Do this
<script type="text/javascript">
function displaymessage(fld){
opener.document.cash_entry.sub_name.value = fld.value;
self.close();
}
</script>
<form>
<?php
$sel=mysql_query("select * from add_ticket");
while($row=mysql_fetch_array($sel)) {
$subscriber=$row['subscriber'];
?>
<input type="text" name="subname"
id="subid<?php echo $subscriber; ?>"
value="<?php echo $subscriber; ?>"
ondblclick="displaymessage(this)" readonly="true">
<?php } ?>
</form>
by why not
<input type="button" value="<?php echo $subscriber; ?>"
onclick="displaymessage(this)" >
For more than one value, you can do
function displaymessage(fld){
var parts = fld.value.split("|");
opener.document.cash_entry.sub_name.value = parts[0];
opener.document.cash_entry.sub_id.value = parts[1];
self.close();
}
<input type="button"
value="<?php echo $subscriber; ?>|<?php echo $subscriberID; ?>"
onclick="displaymessage(this)" >